问题
I am familiar with obtaining the contents of a properties file given the name of the file, and obviously MyClass.class.getResource('*.properties') will not work, but how can I obtain a list of ALL the properties files located in the same package as my class?
回答1:
You can do these sort of things with Spring. See 4. Resources, particurlarely (or notabily ? ) (or principalementely ? ) (or mainly ? ) at 4.7.2 Wildcards in application context constructor resource paths.
回答2:
Assuming that it's not JAR-packaged, you can use File#listFiles() for this. Here's a kickoff example:
String path = MyClass.class.getResource("").getPath();
File[] propertiesFiles = new File(path).listFiles(new FilenameFilter() {
public boolean accept(File dir, String name) {
return name.endsWith(".properties");
}
});
If it's JAR-packaged, then you need a bit more code, to start with JarFile API. You can find another example in this answer.
回答3:
This is how I did it,
Class<? extends Object> clazz = AnyKnownClassInTheJar.class;
String classFileName = clazz.getSimpleName() + ".class";
URL classResource = clazz.getResource(classFileName);
if (!"jar".equals(classResource.getProtocol())) {
// Class not from JAR
return;
}
JarURLConnection classConnection = (JarURLConnection)classResource.openConnection();
JarFile jar = classConnection.getJarFile();
for (Enumeration<JarEntry> i = jar.entries(); i.hasMoreElements();) {
JarEntry entry = i.nextElement();
if (entry.getName().endsWith(".properties")) {
// Load the property file
}
}
来源:https://stackoverflow.com/questions/2960355/is-it-possible-load-all-properties-files-contained-in-a-package-dynamically-i-e