Bresenham algorithm in Javascript

≡放荡痞女 提交于 2019-11-26 20:08:54
Phrogz

Rewriting your supplied pseudo-code into JavaScript:

function line(x0, y0, x1, y1) {
   var dx = Math.abs(x1 - x0);
   var dy = Math.abs(y1 - y0);
   var sx = (x0 < x1) ? 1 : -1;
   var sy = (y0 < y1) ? 1 : -1;
   var err = dx - dy;

   while(true) {
      setPixel(x0, y0); // Do what you need to for this

      if ((x0 === x1) && (y0 === y1)) break;
      var e2 = 2*err;
      if (e2 > -dy) { err -= dy; x0  += sx; }
      if (e2 < dx) { err += dx; y0  += sy; }
   }
}

Note that comparing floats directly may fail as you step (though it shouldn't when stepping by integer amounts, it might if either end point is non-integer), so instead of directly comparing the end points you might want to use an epsilon:

if (Math.abs(x0 - x1) < 0.0001 && Math.abs(y0 - y1) < 0.0001) break;

This will necessarily slow you down, however, so only do this if you are dealing with non-integers.

Disclaimer: I extracted this answer from the OPs question. Answers should not be contained in the question itself.


Answer provided by Boris Hamanov:

Thanks everybody! This is what I came with at the end:

function calcStraightLine (startCoordinates, endCoordinates) {
    var coordinatesArray = new Array();
    // Translate coordinates
    var x1 = startCoordinates.left;
    var y1 = startCoordinates.top;
    var x2 = endCoordinates.left;
    var y2 = endCoordinates.top;
    // Define differences and error check
    var dx = Math.abs(x2 - x1);
    var dy = Math.abs(y2 - y1);
    var sx = (x1 < x2) ? 1 : -1;
    var sy = (y1 < y2) ? 1 : -1;
    var err = dx - dy;
    // Set first coordinates
    coordinatesArray.push(new Coordinates(y1, x1));
    // Main loop
    while (!((x1 == x2) && (y1 == y2))) {
        var e2 = err << 1;
        if (e2 > -dy) {
            err -= dy;
            x1 += sx;
        }
        if (e2 < dx) {
            err += dx;
            y1 += sy;
        }
        // Set coordinates
        coordinatesArray.push(new Coordinates(y1, x1));
    }
    // Return the result
    return coordinatesArray;
}
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!