问题
I want to know how can i find all the values that are NULL in the MySQL database for example I'm trying to display all the users who don't have an average yet.
Here is the MySQL code.
SELECT COUNT(average) as num
FROM users
WHERE user_id = '$user_id'
AND average IS_NULL
回答1:
SELECT
COUNT(*) as num
FROM
users
WHERE
user_id = '$user_id' AND
average IS NULL
回答2:
A more generic version (that doesn't depend on the where clause and hence limits your overall results):
SELECT
SUM(CASE WHEN average IS NULL THEN 1 ELSE 0 END) As null_num,
SUM(CASE WHEN average IS NOT NULL THEN 1 ELSE 0 END) AS not_null_num
FROM users
It's not better then the specific queries presented by other answers here, but it can be used in situations where using a limiting where clause is impractical (due to other information being needed)...
回答3:
Also, you can:
Select Count(*) - Count(Average) as NullAverages
From Users
Where user_id = '$user_id'
回答4:
you're on the right track. Remove '_' from 'IS_NULL' and change 'COUNT(average)' to 'COUNT(1)' and you will have it.
For more information on working with NULL in MYSQL see http://dev.mysql.com/doc/refman/5.0/en/working-with-null.html
And for working with IS NULL specifically see
http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html#operator_is-null
回答5:
I may be missing something mysql specific but this would work in sql server
SELECT COUNT(*) as num
FROM users
WHERE user_id = '$user_id'
AND average IS NULL
回答6:
A bit late but you can do it in MySQL 5.0.51:
SELECT COUNT(*) AS total, COUNT(field1) AS notNullFields1
FROM table
GROUP BY field5, field6
Regards.
回答7:
This is a one liner that also could be used for this problem :
SELECT COUNT(IF(average IS NULL,1,0))
FROM table;
It worked like a charm for me!
来源:https://stackoverflow.com/questions/3057746/how-to-count-null-values-in-mysql