Map implementation with duplicate keys

試著忘記壹切 提交于 2019-11-25 23:44:45

问题


I want to have a map with duplicate keys.

I know there are many map implementations (Eclipse shows me about 50), so I bet there must be one that allows this. I know it\'s easy to write your own map that does this, but I would rather use some existing solution.

Maybe something in commons-collections or google-collections?


回答1:


You are searching for a multimap, and indeed both commons-collections and Guava have several implementations for that. Multimaps allow for multiple keys by maintaining a collection of values per key, i.e. you can put a single object into the map, but you retrieve a collection.

If you can use Java 5, I would prefer Guava's Multimap as it is generics-aware.




回答2:


We don't need to depend on the Google Collections external library. You can simply implement the following Map:

Map<String, ArrayList<String>> hashMap = new HashMap<String, ArrayList>();

public static void main(String... arg) {
   // Add data with duplicate keys
   addValues("A", "a1");
   addValues("A", "a2");
   addValues("B", "b");
   // View data.
   Iterator it = hashMap.keySet().iterator();
   ArrayList tempList = null;

   while (it.hasNext()) {
      String key = it.next().toString();             
      tempList = hashMap.get(key);
      if (tempList != null) {
         for (String value: tempList) {
            System.out.println("Key : "+key+ " , Value : "+value);
         }
      }
   }
}

private void addValues(String key, String value) {
   ArrayList tempList = null;
   if (hashMap.containsKey(key)) {
      tempList = hashMap.get(key);
      if(tempList == null)
         tempList = new ArrayList();
      tempList.add(value);  
   } else {
      tempList = new ArrayList();
      tempList.add(value);               
   }
   hashMap.put(key,tempList);
}

Please make sure to fine tune the code.




回答3:


Multimap<Integer, String> multimap = ArrayListMultimap.create();

multimap.put(1, "A");
multimap.put(1, "B");
multimap.put(1, "C");
multimap.put(1, "A");

multimap.put(2, "A");
multimap.put(2, "B");
multimap.put(2, "C");

multimap.put(3, "A");

System.out.println(multimap.get(1));
System.out.println(multimap.get(2));       
System.out.println(multimap.get(3));

Output is:

[A,B,C,A]
[A,B,C]
[A]

Note: we need to import library files.

http://www.java2s.com/Code/Jar/g/Downloadgooglecollectionsjar.htm

import com.google.common.collect.ArrayListMultimap;
import com.google.common.collect.Multimap;

or https://commons.apache.org/proper/commons-collections/download_collections.cgi

import org.apache.commons.collections.MultiMap;
import org.apache.commons.collections.map.MultiValueMap;



回答4:


You could simply pass an array of values for the value in a regular HashMap, thus simulating duplicate keys, and it would be up to you to decide what data to use.

You may also just use a MultiMap, although I do not like the idea of duplicate keys myself.




回答5:


If you want iterate about a list of key-value-pairs (as you wrote in the comment), then a List or an array should be better. First combine your keys and values:

public class Pair
{
   public Class1 key;
   public Class2 value;

   public Pair(Class1 key, Class2 value)
   {
      this.key = key;
      this.value = value;
   }

}

Replace Class1 and Class2 with the types you want to use for keys and values.

Now you can put them into an array or a list and iterate over them:

Pair[] pairs = new Pair[10];
...
for (Pair pair : pairs)
{
   ...
}



回答6:


commons.apache.org

MultiValueMap class



回答7:


This problem can be solved with a list of map entry List<Map.Entry<K,V>>. We don't need to use neither external libraries nor new implementation of Map. A map entry can be created like this: Map.Entry<String, Integer> entry = new AbstractMap.SimpleEntry<String, Integer>("key", 1);




回答8:


Learn from my mistakes...please don't implement this on your own. Guava multimap is the way to go.

A common enhancement required in multimaps is to disallow duplicate keys-value pairs.

Implementing/changing this in a your implementation can be annoying.

In Guava its as simple as:

HashMultimap<String, Integer> no_dupe_key_plus_val = HashMultimap.create();

ArrayListMultimap<String, Integer> allow_dupe_key_plus_val = ArrayListMultimap.create();



回答9:


I had a slightly different variant of this issue: It was required to associate two different values with same key. Just posting it here in case it helps others, I have introduced a HashMap as the value:

/* @param frameTypeHash: Key -> Integer (frameID), Value -> HashMap (innerMap)
   @param innerMap: Key -> String (extIP), Value -> String
   If the key exists, retrieve the stored HashMap innerMap 
   and put the constructed key, value pair
*/
  if (frameTypeHash.containsKey(frameID)){
            //Key exists, add the key/value to innerHashMap
            HashMap innerMap = (HashMap)frameTypeHash.get(frameID);
            innerMap.put(extIP, connName+":"+frameType+":"+interfaceName);

        } else {
            HashMap<String, String> innerMap = new HashMap<String, String>();
            innerMap.put(extIP, connName+":"+frameType+":"+interfaceName);
            // This means the key doesn't exists, adding it for the first time
            frameTypeHash.put(frameID, innerMap );
        }
}

In the above code the key frameID is read from a input file's first string in each line, the value for frameTypeHash is constructed by splitting the remaining line and was stored as String object originally, over a period of time the file started having multiple lines (with different values) associated with same frameID key, so frameTypeHash was overwritten with last line as the value. I replaced the String object with another HashMap object as the value field, this helped in maintaining single key to different value mapping.




回答10:


class  DuplicateMap<K, V> 
{
    enum MapType
    {
        Hash,LinkedHash
    }

    int HashCode = 0;
    Map<Key<K>,V> map = null;

    DuplicateMap()
    {
        map = new HashMap<Key<K>,V>();
    }

    DuplicateMap( MapType maptype )
    {
        if ( maptype == MapType.Hash ) {
            map = new HashMap<Key<K>,V>();
        }
        else if ( maptype == MapType.LinkedHash ) {
            map = new LinkedHashMap<Key<K>,V>();
        }
        else
            map = new HashMap<Key<K>,V>();
    }

    V put( K key, V value  )
    {

        return map.put( new Key<K>( key , HashCode++ ), value );
    }

    void putAll( Map<K, V> map1 )
    {
        Map<Key<K>,V> map2 = new LinkedHashMap<Key<K>,V>();

        for ( Entry<K, V> entry : map1.entrySet() ) {
            map2.put( new Key<K>( entry.getKey() , HashCode++ ), entry.getValue());
        }
        map.putAll(map2);
    }

    Set<Entry<K, V>> entrySet()
    {
        Set<Entry<K, V>> entry = new LinkedHashSet<Map.Entry<K,V>>();
        for ( final Entry<Key<K>, V> entry1 : map.entrySet() ) {
            entry.add( new Entry<K, V>(){
                private K Key = entry1.getKey().Key();
                private V Value = entry1.getValue();

                @Override
                public K getKey() {
                    return Key;
                }

                @Override
                public V getValue() {
                    return Value;
                }

                @Override
                public V setValue(V value) {
                    return null;
                }});
        }

        return entry;
    }

    @Override
    public String toString() {
        StringBuilder builder = new  StringBuilder();
        builder.append("{");
        boolean FirstIteration = true;
        for ( Entry<K, V> entry : entrySet() ) {
            builder.append( ( (FirstIteration)? "" : "," ) + ((entry.getKey()==null) ? null :entry.getKey().toString() ) + "=" + ((entry.getValue()==null) ? null :entry.getValue().toString() )  );
            FirstIteration = false;
        }
        builder.append("}");
        return builder.toString();
    }

    class Key<K1>
    {
        K1 Key;
        int HashCode;

        public Key(K1 key, int hashCode) {
            super();
            Key = key;
            HashCode = hashCode;
        }

        public K1 Key() {
            return Key;
        }

        @Override
        public String toString() {
            return  Key.toString() ;
        }

        @Override
        public int hashCode() {

            return HashCode;
        }
    }



回答11:


 1, Map<String, List<String>> map = new HashMap<>();

this verbose solution has multiple drawbacks and is prone to errors. It implies that we need to instantiate a Collection for every value, check for its presence before adding or removing a value, delete it manually when no values are left, etcetera.

2, org.apache.commons.collections4.MultiMap interface
3, com.google.common.collect.Multimap interface 

java-map-duplicate-keys




回答12:


what about such a MultiMap impl?

public class MultiMap<K, V> extends HashMap<K, Set<V>> {
  private static final long serialVersionUID = 1L;
  private Map<K, Set<V>> innerMap = new HashMap<>();

  public Set<V> put(K key, V value) {
    Set<V> valuesOld = this.innerMap.get(key);
    HashSet<V> valuesNewTotal = new HashSet<>();
    if (valuesOld != null) {
      valuesNewTotal.addAll(valuesOld);
    }
    valuesNewTotal.add(value);
    this.innerMap.put(key, valuesNewTotal);
    return valuesOld;
  }

  public void putAll(K key, Set<V> values) {
    for (V value : values) {
      put(key, value);
    }
  }

  @Override
  public Set<V> put(K key, Set<V> value) {
    Set<V> valuesOld = this.innerMap.get(key);
    putAll(key, value);
    return valuesOld;
  }

  @Override
  public void putAll(Map<? extends K, ? extends Set<V>> mapOfValues) {
    for (Map.Entry<? extends K, ? extends Set<V>> valueEntry : mapOfValues.entrySet()) {
      K key = valueEntry.getKey();
      Set<V> value = valueEntry.getValue();
      putAll(key, value);
    }
  }

  @Override
  public Set<V> putIfAbsent(K key, Set<V> value) {
    Set<V> valueOld = this.innerMap.get(key);
    if (valueOld == null) {
      putAll(key, value);
    }
    return valueOld;
  }

  @Override
  public Set<V> get(Object key) {
    return this.innerMap.get(key);
  }

  @Override
  etc. etc. override all public methods size(), clear() .....

}



回答13:


No fancy libs required. Maps are defined by a unique key, so dont bend them, use a list. Streams are mighty.

import java.util.AbstractMap.SimpleImmutableEntry;

List<SimpleImmutableEntry<String, String>> nameToLocationMap = Arrays.asList(
    new SimpleImmutableEntry<>("A", "A1"),
    new SimpleImmutableEntry<>("A", "A2"),
    new SimpleImmutableEntry<>("B", "B1"),
    new SimpleImmutableEntry<>("B", "B1"),
);

And thats it. Usage examples:

List<String> allBsLocations = nameToLocationMap.stream()
        .filter(x -> x.getKey().equals("B"))
        .map(x -> x.getValue())
        .collect(Collectors.toList());

nameToLocationMap.stream().forEach(x -> 
do stuff with: x.getKey()...x.getValue()...



回答14:


Could you also explain the context for which you are trying to implement a map with duplicate keys? I am sure there could be a better solution. Maps are intended to keep unique keys for good reason. Though if you really wanted to do it; you can always extend the class write a simple custom map class which has a collision mitigation function and would enable you to keep multiple entries with same keys.

Note: You must implement collision mitigation function such that, colliding keys are converted to unique set "always". Something simple like, appending key with object hashcode or something?




回答15:


just to be complete, Apache Commons Collections also has a MultiMap. The downside of course is that Apache Commons does not use Generics.




回答16:


With a bit hack you can use HashSet with duplicate keys. WARNING: this is heavily HashSet implementation dependant.

class MultiKeyPair {
    Object key;
    Object value;

    public MultiKeyPair(Object key, Object value) {
        this.key = key;
        this.value = value;
    }

    @Override
    public int hashCode() {
        return key.hashCode();
    }
}

class MultiKeyList extends MultiKeyPair {
    ArrayList<MultiKeyPair> list = new ArrayList<MultiKeyPair>();

    public MultiKeyList(Object key) {
        super(key, null);
    }

    @Override
    public boolean equals(Object obj) {
        list.add((MultiKeyPair) obj);
        return false;
    }
}

public static void main(String[] args) {
    HashSet<MultiKeyPair> set = new HashSet<MultiKeyPair>();
    set.add(new MultiKeyPair("A","a1"));
    set.add(new MultiKeyPair("A","a2"));
    set.add(new MultiKeyPair("B","b1"));
    set.add(new MultiKeyPair("A","a3"));

    MultiKeyList o = new MultiKeyList("A");
    set.contains(o);

    for (MultiKeyPair pair : o.list) {
        System.out.println(pair.value);
    }
}



回答17:


If there are duplicate keys then a key may correspond to more than one value. The obvious solution is to map the key to a list of these values.

For example in Python:

map = dict()
map["driver"] = list()
map["driver"].append("john")
map["driver"].append("mike")
print map["driver"]          # It shows john and mike
print map["driver"][0]       # It shows john
print map["driver"][1]       # It shows mike



回答18:


I used this:

java.util.List<java.util.Map.Entry<String,Integer>> pairList= new java.util.ArrayList<>();



来源:https://stackoverflow.com/questions/1062960/map-implementation-with-duplicate-keys

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