Guzzle 6: no more json() method for responses

问题

Previously in Guzzle 5.3:

$response = $client->get('http://httpbin.org/get');
$array = $response->json(); // Yoohoo
var_dump($array[0]['origin']);

I could easily get a PHP array from a JSON response. Now In Guzzle 6, I don't know how to do. There seems to be no json() method anymore. I (quickly) read the doc from the latest version and don't found anything about JSON responses. I think I missed something, maybe there is a new concept that I don't understand (or maybe I did not read correctly).

Is this (below) new way the only way?

$response = $client->get('http://httpbin.org/get');
$array = json_decode($response->getBody()->getContents(), true); // :'(
var_dump($array[0]['origin']);

Or is there an helper or something like that?

回答1:

I use json_decode($response->getBody()) now instead of $response->json().

I suspect this might be a casualty of PSR-7 compliance.

回答2:

You switch to:

json_decode($response->getBody(), true)

Instead of the other comment if you want it to work exactly as before in order to get arrays instead of objects.

回答3:

I use $response->getBody()->getContents() to get JSON from response. Guzzle version 6.3.0.

回答4:

If you guys still interested, here is my workaround based on Guzzle middleware feature:

Create JsonAwaraResponse that will decode JSON response by Content-Type HTTP header, if not - it will act as standard Guzzle Response:

<?php

namespace GuzzleHttp\Psr7;


class JsonAwareResponse extends Response
{
    /**
     * Cache for performance
     * @var array
     */
    private $json;

    public function getBody()
    {
        if ($this->json) {
            return $this->json;
        }
        // get parent Body stream
        $body = parent::getBody();

        // if JSON HTTP header detected - then decode
        if (false !== strpos($this->getHeaderLine('Content-Type'), 'application/json')) {
            return $this->json = \json_decode($body, true);
        }
        return $body;
    }
}

Create Middleware which going to replace Guzzle PSR-7 responses with above Response implementation:

<?php

$client = new \GuzzleHttp\Client();

/** @var HandlerStack $handler */
$handler = $client->getConfig('handler');
$handler->push(\GuzzleHttp\Middleware::mapResponse(function (\Psr\Http\Message\ResponseInterface $response) {
    return new \GuzzleHttp\Psr7\JsonAwareResponse(
        $response->getStatusCode(),
        $response->getHeaders(),
        $response->getBody(),
        $response->getProtocolVersion(),
        $response->getReasonPhrase()
    );
}), 'json_decode_middleware');

After this to retrieve JSON as PHP native array use Guzzle as always:

$jsonArray = $client->get('http://httpbin.org/headers')->getBody();

Tested with guzzlehttp/guzzle 6.3.3

回答5:

Adding ->getContents() doesn't return jSON response, instead it returns as text.

You can simply use json_decode

回答6:

$response is instance of PSR-7 ResponseInterface. For more details see https://www.php-fig.org/psr/psr-7/#3-interfaces

getBody() returns StreamInterface:

/**
 * Gets the body of the message.
 *
 * @return StreamInterface Returns the body as a stream.
 */
public function getBody();

StreamInterface implements __toString() which does

Reads all data from the stream into a string, from the beginning to end.

Therefore, to read body as string, you have to cast it to string:

$stringBody = (string) $response->getBody()

Gotchas

json_decode($response->getBody() is not the best solution as it magically casts stream into string for you. json_decode() requires string as 1st argument.
Don't use $response->getBody()->getContents() unless you know what you're doing. If you read documentation for getContents(), it says: Returns the remaining contents in a string. Therefore, calling getContents() reads the rest of the stream and calling it again returns nothing because stream is already at the end. You'd have to rewind the stream between those calls.

来源：https://stackoverflow.com/questions/30530172/guzzle-6-no-more-json-method-for-responses

标签

php

guzzle