Division on the fly [duplicate]

Question

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• Trouble with calling method [duplicate] 2 answers

I'm trying to make a small program in Java which converts Fahrenheit to Celsius. It involves deducting 32 and multiplying by 5/9. So I did this.

double Fahrenheit = 100;
double celsius = (Fahrenheit - 32) * (5/9);
System.out.println(celsius);

But for some reason that 5/9 returns zero which ruins it all, even

double s = 5/9;

returns zero and I don't know why. The only way I found I can do it is if I declare everything and do it slowly, step by step.

double x = 5, p = 9, n = (x/p), Fah = 100;
double Cel = Fah - 32;
Cel = Cel*n;

Can anyone tell me why this sort of thing happens, I thought at least declaring it as a double would return a value. And if anyone knows, a way round it.

Answer 1

Numbers are int by default in Java. So when you do 5/9, since they're both ints, you'll get 0.something, and since this is an int, only 0 will be stored. Solution:

double s = 5.0/9; //or 5d/9

Note that you can only explicitly cast one side, the other will be implicitly cast.

Now the calculation will be in a double manner and you'll get the desired result.

Answer 2

or you can do (5d/9d); // OR (5d/9) making 5 and 9 explicit double

Answer 3

It's good practice, when you deal with doubles, to write code like this:

double Fahrenheit = 100.0;
double celsius = (Fahrenheit - 32.0) * (5.0 / 9.0);