zlib

Hashing an IP address to a number in [0, H)

由 感情迁移 提交于 2019-12-10 19:43:54
问题 I'm using Python-2.6. I have very little knowledge of hash functions. I want to use a CRC hash function to hash an IP address like '128.0.0.5' into the range [0, H). Currently I'm thinking of doing zlib.crc32('128.0.0.5')%H. Is this okay? There's a few ques. you could try and answer... does it make any diff. if I hash '128.0.0.5' or its binary '0001110101010..' whatever that is or without the '.'s zlib.crc32 returns a signed integer. Does modding (%) a neg. with a positive H always give a pos

Is ZLIB support in PHP enabled by default or NOT?

由 做~自己de王妃 提交于 2019-12-10 19:16:15
问题 In the documentation of phpmanual it says: Zlib support in PHP is not enabled by default. You will need to configure PHP --with-zlib[=DIR] The Windows version of PHP has built-in support for this extension. You do not need to load any additional extensions in order to use these functions. So as it says it should be enabled by default only in the Windows version of PHP. But I install PHP and Apache on my linux machine from the repository, and then I noticed that it's already enabled. Used

Python3: no gzip or zlib?

由 ぃ、小莉子 提交于 2019-12-10 19:15:41
问题 is this module named something else now? I can't seem to find any info saying that this module was deprecated or dropped completely. (which would confuse me further) Anyone know where this went? Python 3.1.2 (r312:79147, May 20 2010, 09:09:30) [GCC 4.1.2 20080704 (Red Hat 4.1.2-48)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import gzip Traceback (most recent call last): File "", line 1, in File "/usr/local/lib/python3.1/gzip.py", line 9, in import

How to gunzip stream in nodejs?

由 ╄→гoц情女王★ 提交于 2019-12-10 18:27:13
问题 I'm trying to accomplish quite an easy task but I'm a little bit confused and got stuck on using zlib in nodejs. I'm building functionality that includes me downloading file from aws S3 which is gziped, unzipping it and reading it line by line. I want to accomplish all of this using streams as I believe it is possible to do so in nodejs. Here is my current code base: //downloading zipped file from aws s3: //params are configured correctly to access my aws s3 bucket and file s3.getObject

How does gcc/ld find zlib.so?

由 扶醉桌前 提交于 2019-12-10 16:52:18
问题 I've used zlib for ages and never thought about the fact that it is named slightly unconventionally. While most libraries on Linux follow the naming convention of lib<name>.so for shared objects and lib<name>.a for archives, zlib is named zlib.so / zlib.a . My question is: how does gcc/ld know to look for zlib.so when I use -lz as a link flag? I understand that for linking, gcc invokes ld, which searches for libraries in certain default paths and any path specified with -L , and it appends

gzip raised OverflowError: Size does not fit in an unsigned int

由 和自甴很熟 提交于 2019-12-10 15:59:42
问题 Environment: Windows, Python 3.4.1, 64-bit version. I tried to save data with pickle and gzip, simply like this: with gzip.open(filename, 'rb') as f: pickle.dump(data,f) The data can be successfully dumped without gzip, but with gzip, exception raised as: File "C:\Python34\lib\gzip.py", line 344, in write self.fileobj.write( self.compress.compress(data) ) OverflowError: Size does not fit in an unsigned int I traced back the code, and found that gzip is actually built upon zlib. And after

LAMP

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-10 15:31:24
install apache #!/bin/bash cd /usr/local/src/httpd-2.0.63 #2.0版本的编译方法 #./configure --prefix=/usr/local/apache --enable-so --enable-speling --enable-rewrite --with-ssl=/usr/local/ssl --enable-forward ./configure --prefix=/usr/local/apache2 --enable-so --enable-mods-shared=most && make && make install ######################################################### install mysql #!/bin/bash cd /usr/local/src/mysql-5.0.67 userdel mysql groupadd mysql useradd mysql -d /usr/local/mysql -g mysql mkdir -p /usr/local/mysql/data mkdir -p /usr/local/mysql/tmp chown -R mysql:mysql /usr/local/mysql ./configure '

安装libpng出现configure: error: ZLib not installed

由 限于喜欢 提交于 2019-12-10 15:15:42
1.问题描述 安装libpng出现configure: error: ZLib not installed 2.解决方案 1.进入zlib的源文件目录，执行命令 make clean,清除zlib； 2.重新配置 ./configure,后面不要接--prefix参数； 3.编辑 make && make install 安装； 4.进入libpng目录，执行命令 ./configure --prefix=/usr/local/libpng; 5.编译 make && make install 安装； 结果还是不行， 3.其他 解决办法： 执行以下命令： #export LDFLAGS="-L/usr/local/zlib/lib" #export CPPFLAGS="-I/usr/local/zlib/include" 来源： oschina 链接： https://my.oschina.net/u/123905/blog/199764

GraphicMagic安装说明

由 淺唱寂寞╮ 提交于 2019-12-10 15:15:28
GraphicMagic安装说明 GraphicMagic号称图片处理的瑞士军刀，可以处理包括图片压缩、补白、水印等等一系列的功能；GraphicMagic到官网下载，解压之后，需要在本地进行相应的 make install 处理； 此处列出一些注意事项； GraphicMagic 依赖的包包括：zlib , libpng(处理png图片) , libjpeg(处理jpg图片)；所以在安装GraphicMagic之前要先安装以上三个包； zlib安装 rpm -qa | grep zlib 查看软件安装情况； zlib安装: 解压； 在目录下执行./configure --prefix=需要安装的目录 执行命令： make test或make make install 安装完成之后，为避免与系统提供的zlib包冲突，需要将zlib包加入当前用户的环境变量；步骤如下： 修改 .bash_profile文件 vi .bash_profile 并在其中增加以下环境变量： export LD_LIBRARY_PATH=zlib安装目录/lib:$LD_LIBRARY_PATH export C_INCLUDE_PATH=zlib安装目录/include:$C_INCLUDE_PATH export CPLUS_INCLUDE_PATH=zlib安装目录/include:$CPLUS

Node Zlib creating invalid .gz files when streaming

由 柔情痞子 提交于 2019-12-10 14:44:47
问题 I am trying to create a .gz file by streaming strings (JSONs separated by newlines) to it gradually. Using Node 0.11 and 0.12 (both with same reasult, .gz file won't open). I reduced the code to this: var fs = require('fs'); var output = fs.createWriteStream('test.gz'); var zlib = require('zlib'); var compress = zlib.createGzip(); var myStream = compress.pipe(output); myStream.write('Hello, World!'); myStream.end(); The file is created, but I cannot open it. What am I doing wrong? 回答1: Okay,
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