zend-framework

What is wrong with this where clause of zend query

依然范特西╮ 提交于 2019-12-11 15:03:46
问题 Hi I am mad on not understanding the error in this where clause of zend query. My query is $select->where("id=".$get['value']." OR description like '%".$get['value']."%'"); $get['value'] is the query that I want to search. But result is 500 internal server error and it always says the value of get['value'] is unkown column. For example if I have searched testing for description column it always says that testing in unknown columns... why is this happening 回答1: Check this docs zend_db_select

How to dynamically override forms and/or views using Zend?

眉间皱痕 提交于 2019-12-11 14:56:36
问题 I'm working on a web application using Zend that we'd like to ship with some default forms and views. We'd like the client to be able to create custom forms and/or views that could be placed in another directory that could override the default forms. IE, Zend would check to see if any custom forms (or views) existed, and if so, load those, otherwise load the default ones. Is this possible to do using Zend? I already thought about creating subclasses for every form that by default would just

how to set a custom view in zend-framework2

怎甘沉沦 提交于 2019-12-11 14:54:58
问题 I am trying to return a custom view using ajax in zend framework2. This view may be changed dynamically according to the condition in ajax call.. So how i can return a full view through ajax in zf2 ? 回答1: You can return a full view through ajax in the same way as you would return a full view through your browsers location bar. If you just want to return html, then simply return a view model in the same way you usually would. You may want to disable the layout, this can be done with:

Zend_Gdata library and Picasa data API — loader.php file missing

假装没事ソ 提交于 2019-12-11 14:44:41
问题 Im trying to develop an application in php to download pics from picasa using Zend_Gdata library. My project folder structure is like this: www(wamp) /project test.php /Zend /Authentication /Barcode . . /View /XmlRpc As you can see, i havent copied the full Zend Framework. I dont want the full MVC paradigm in this project, just the Zend_Gdata library. Is this the way to do this? Or do i have to use the complete zend framework? Im completely new to Zend. I found this article at IBM site http:/

PHP postgres Zend Framework Select query with WHERE 'AND' clause

假装没事ソ 提交于 2019-12-11 14:18:57
问题 Ok Im still new to Zend, and trying to find how the ORM works in general for it, seems to be posing a difficult task (anyone know where they have a specific document for it). That aside what I am trying to do is take an existing query and add a "AND" clause to it. Just not sure how to go about doing that, as the examples I have found else where dont look like this one, and I'd rather avoid breakage on this $select = $this->select() ->from('offer_term') ->setIntegrityCheck(false) ->joinUsing(

Accessibility of a session in a view

邮差的信 提交于 2019-12-11 14:11:21
问题 I have created a Zend session in a view: $user = Tools::getUserByLoginAndPassword($form); if ($user instanceof Membre) { $sessionUser = new Zend_Session_Namespace('user'); $sessionUser->data = $user; $this->_redirect('/adresse'); } I have tested $sessionUser->data, it contains the right data. But i need to get this session in another view, and there, it's not working anymore... for instance <?php var_dump($sessionUser->data->prenom); ?> displays "NULL" it worked fine in the previous view but

xml sitemap not displaying in xml format

好久不见. 提交于 2019-12-11 13:46:13
问题 I want to display my sitemap in proper xml format but it displays in one line: http://www.example.com/home 1.00 http://www.example.com/about 0.50 http://www.example.com/login 0.20 http://www. etc not: <?xml version="1.0" encoding="UTF-8"?> <urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9" xmlns:xhtml="http://www.w3.org/1999/xhtml" xmlns:image="http://www.google.com/schemas/sitemap-image/1.1"> <url> <loc>http://www.example.com/home</loc> <priority>1.00</priority> </url> <url> <loc

How to give zend library path in our application? (In zend framework 2.3)

爱⌒轻易说出口 提交于 2019-12-11 13:45:13
问题 I have installed zend skeleton application in my local machine. I am working on ubuntu. I have installed it manually without using composer. I have given the ZF2_PATH(zend library path) in my httpd.conf. as in the below : <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /var/www/ SetEnv ZF2_PATH /var/www/lib/ZendFramework-2.3.1/library SetEnv APPLICATION_ENV "development" ErrorLog ${APACHE_LOG_DIR}/error.log CustomLog ${APACHE_LOG_DIR}/access.log combined It is working fine. I

Zend framework deployment on the shared hosting

a 夏天 提交于 2019-12-11 13:26:00
问题 I want to deploy my project made in zend framework to my shared hosting. My project has such structure: application docs library Obsolete public scripts tests This is what I have done: I copied Zend folder (all library files) into library folder I copied all the structure above into public_html/projects/project (so if I type www.mydomain.com/projects/project/public I run the project I tried to click on some link so that it redirected me to www.mydomain.com/projects/project/public

What/Where are the Naming Rules for Controller actions in a Zend_Application App

China☆狼群 提交于 2019-12-11 13:24:02
问题 I've created a Zend_Application using the zf tool that's bundled with Zend Framework (1.96, if that matters) What at the rules for formatting action names and how those action names get translated into into URL paths, and where in the Framework codebase does this happen? I ask because I tried to create an action like public function createFooAction() { } and it wouldn't load with a URL like http://example.com/controller/createFoo BUT, the following did work public function createfooAction() {