yql

YQL gives out result only in tree view. Is there any way to get the result in Formatted view?? Use an XSLT stylesheet to create a formatted view. Here is an example for an RSS feed: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="XML" encoding="utf-8" doctype-public="-//W3C//DTD XHTML 1.0 Transitional//EN" doctype-system=http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd indent="yes"/> <xsl:template match='//channel'> <page> <content> <module> <header layout="simple"> <layout-items> <block class=

How can I create a YQL Query that will return me companies from Yahoo Finance? select * from yahoo.finance.quotes where name like "apple" Doesn't work. That won't work for many reasons. Please try: select * from html where url="http://finance.yahoo.com/d/quotes.csv?s=AAPL&f=snl1d1t1ohgdr" To get exactly what you want, you could further filter with xpath in the where clause. To get a symbol of any company you can use the below url : http://d.yimg.com/autoc.finance.yahoo.com/autoc?query=<company name>&callback=YAHOO.Finance.SymbolSuggest.ssCallback here in the query you can pass any company name

I have the following code: import re from re import sub import cookielib from cookielib import CookieJar import urllib2 from urllib2 import urlopen cj = CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) opener.addheaders=[('user-agent' , 'Safari/7.0.2')] def check(word): try: query = "select * from geo.places where text ='"+word+"'" sourceCode=opener.open('http://query.yahooapis.com/v1/public/yql?q='+query+'&diagnostics=true').read() print sourceCode except Exception, e: print str(e) print 'ERROR IN MAIN TRY' myStr = ['I','went','to','Boston'] for item in myStr: check

I am new to Javascript and trying to extract some text stored in an object. The object is defined as an object literal and is passed to a function in a Javascript script that calls the function. The script (and object) have this structure: foo({ "query": { "count": "2", "created": "2009-07-25T08:17:54Z", "lang": "en-US", }, "results": { "result": [ { "abstract": "<b>Pizza</b> Hut®. Order Online for Delivery or Carry-out. Fast & Easy.", "title": "<b>Pizza</b> Hut" }, { "abstract": "Official site of Domino's <b>Pizza</b> delivery chain, which offers thin crust, deep dish, and hand tossed <b

I have a pipe that filters an RSS feed and removes any item that contains "stopwords" that I've chosen. Currently I've manually created a filter for each stopword in the pipe editor, but the more logical way is to read these from a file. I've figured out how to read the stopwords out of the text file, but how do I apply the filter operator to the feed, once for every stopword? The documentation states explicitly that operators can't be applied within the loop construct, but hopefully I'm missing something here. You're not missing anything - the filter operator can't go in a loop. Your best bet

Hey what do I have to do to implement the Yahoo Query Language in Java? Or is this generally possible? I want to parse the JSON after that. YQL is interpreted server-side, so there's not much to do in Java. I'd just make a URL, open it, and read the data stream. Just copy the PHP example code , mostly: String baseUrl = "http://query.yahooapis.com/v1/public/yql?q="; String query = "select * from upcoming.events where location='San Francisco' and search_text='dance'"; String fullUrlStr = baseUrl + URLEncoder.encode(query, "UTF-8") + "&format=json"; URL fullUrl = new URL(fullUrlStr); InputStream