yield

迭代器与生成器

徘徊边缘 提交于 2019-12-16 13:38:34
迭代器 1,可迭代对象 在Python中,含有iter方法的对象,都是可迭代对象 str ,list,dict,set,tuple都是可迭代对象 判断方法:print(dir(数据类型)),查看源码 优点:,使用灵活,可以直观的查看里面的数据 缺点:占用内存 2,迭代器 可迭代对象执行obj.__iter__()得到的结果就是迭代器 而迭代器对象指的是即内置有__iter__又内置有__next__方法的对象 在Python中,内部含有iter方法并且含有next方法的对象就是迭代器 迭代器:在可迭代对象中,只有文件句柄是迭代器 可迭代对象转换为迭代器 str list ... ### .__iter__() 就是迭代器 dict set s = [1,2,3,4,5,6.] count = len(s) new_s = s.__iter__() while count: print(new_s.__next__()) count -= 1 for i in 的方式 s = [1,3,4,5,6,2,7] new_s = s.__iter__() while True: try: pirnt(new_s.__next__()) except StopIteration: break 优点:节省内存,惰性机制 缺点:不能直观的看到里面的数据, 递归 不断调用自己本身 有明确的终止条件

sleep、yield、wait的区别

混江龙づ霸主 提交于 2019-12-15 21:00:37
sleep和yield都不会释放锁 sleep不出让cpu使用权,仅暂停执行 yield出让cpu使用权,但处于可运行状态 wait、notify、notifyall被调用之前需要持有锁,调用之后释放锁,是一个“等待通知机制” notify是cpu唤醒被锁的对象上随意一个线程,所以最好使用notifyall 来源: https://www.cnblogs.com/hzq3554055/p/12045829.html

python学习笔记之生成器

邮差的信 提交于 2019-12-15 19:45:21
生成器 一边循环一边计算出后续元素的机制,称为生成器:generator 创建generator的第一种方法: 把列表生成式的[ ]改为( ): >> > L = [ x * x for x in range ( 10 ) ] >> > L [ 0 , 1 , 4 , 9 , 16 , 25 , 36 , 49 , 64 , 81 ] >> > g = ( x * x for x in range ( 10 ) ) >> > g < generator object < genexpr > at ox1022ef63 > 可以通过next( )函数获得generator的下一个返回值。 >> > next ( g ) 0 >> > next ( g ) 1 . . . 超出索引范围后会Stop Iteration 更高效的获取generator的方法是使用for >> > for n in g : print ( n ) 创建generator的第二种方法是yield语句 调用next()的时候执行,遇到yield语句返回,再次执行时从上一次的返回的yield语句处继续执行。 例:定义一个generator,依次返回数字1,3,5 >> > def odd ( ) : print ( 'step 1' ) yield 1 print ( 'step 2' ) yield ( 3 )

Search in nested Python dict and record “path”

坚强是说给别人听的谎言 提交于 2019-12-14 03:13:48
问题 With the help of this answer, I'm trying to come up with a function that searches after a key in a nested Python dict and also records the "path" of each match. My function (see below) seems to work, however it is not possible to save the result in a list (see code output). I'm pretty certain that the difficulty lies in the yield command, but I have not been able to figure it out yet. o={ 'dict1': { 'dict11': { 'entry11_1':1, 'entry11_2':2, }, 'dict12': { 'entry12_1':12, 'entry12_2':22, }, },

Javascript strange generator yield sub function behavior

╄→尐↘猪︶ㄣ 提交于 2019-12-13 15:12:20
问题 I'm using MySQL ( mysql-co ) and ASQ( asynquence ) in a simple project to get a better understanding of ES6 generators and yield functions, and I'm stumped on an odd behavior. Short explanation of asynquence asynquence (https://github.com/getify/asynquence) provides an easy way for me to run generators in sequence. It can also do pseudo-parallel execution but that's not what I need for now. The structure of function *x(token) is from there. token holds a connection object at [0] . yield token

Weird PHP Yield error

China☆狼群 提交于 2019-12-13 07:13:05
问题 I was trying to get yield working and I copied and pasted the following code from http://php.net/manual/en/language.generators.syntax.php into an empty file and got the error Parse error: syntax error, unexpected '$i' (T_VARIABLE) in [FILENAME] I'm running XAMPP v3.2.1 which has been working perfectly for the rest of my code (haven't used a yield statement yet) and PHP 5.4.16. Any idea what I'm doing wrong or what I should do? <?php function gen_one_to_three() { for ($i = 1; $i <= 3; $i++) {

Python exit consumer on first StopIteration

自作多情 提交于 2019-12-13 04:43:21
问题 It's a follow-up to my 1 generator -- multiple consumers question. As StopIteration is the way the generator signals its exhaustion, unfortunately, I now have many exception-handling code littered all over the place in the client code (for every next() statement in the example below). Is there a better way to exit with whatever value is built in meal upon hitting the first StopIteration exception? def client(course, take): meal = [] for _ in range(take): try: some_meal = next(course) meal

scrapy爬取数据的基本流程及url地址拼接

半世苍凉 提交于 2019-12-12 19:22:15
说明:初学者,整理后方便能及时完善,冗余之处请多提建议,感谢! 了解内容: Scrapy :抓取数据的爬虫框架 异步与非阻塞的区别 异步:指的是整个过程,中间如果是非阻塞的,那就是异步过程; 非阻塞:关注拿到结果之前的状态 (如果拿到结果前在等待,是阻塞,反之,是非阻塞) 理解: Scrapy 基本工作流程(简单--->复杂) 每个模块间不通讯,模块之间通过引擎进行数据传输 基本使用 一、创建spider scrapy项目流程 ---创建项目 ---scrapy startproject xxxx ---创建爬虫 ---cd 项目目录下 ---scrapy genspider aaa allowed_domains"” scrapy genspider first_spider jpdd.com   first_spider 爬虫名字    jpdd.com 限制爬取数据的范围 --完善spider ---提取数据,提取url地址构成request对象 xpath extract_first()\extract() response.meta yield scrapy.Requeest --完善管道 --运行爬虫 --- cd 项目目录 ---scrapy crawl first_spider 注意 :避免爬虫名和项目名重复 ; 不管在终端还是pycharm 都要切换到当前目录下

How do I implement a cycle-through array with a generator function

元气小坏坏 提交于 2019-12-12 17:07:21
问题 Today I was wondering what would be the swiftest method to provide a cycle-through array in TypeScript, as in: ['one', 'two', 'three'] where the next value after three would be one , and I thought that it's a good candidate for a generator function. However it does not seem to work for me. What's wrong with the following code? function* stepGen(){ const steps = ['one', 'two', 'three']; let index = 0; if(index < steps.length - 1){ index++; } else { index = 0; } yield steps[index]; } let gen =

Problem with Ruby blocks

血红的双手。 提交于 2019-12-12 10:09:54
问题 What is wrong in the code? def call_block(n) if n==1 return 0 elsif n== 2 return 1 else yield return call_block(n-1) + call_block(n-2) end end puts call_block(10) {puts "Take this"} I am trying to use yield to print Take this other than the tenth fibonacci number. I am getting the error: in `call_block': no block given (LocalJumpError) Even the following code throws error: def call_block(n) if n==1 yield return 0 elsif n== 2 yield return 1 else yield return call_block(n-1) + call_block(n-2)