yahoo

How to send emails using yahoo or gmail in c++

梦想与她 提交于 2019-12-02 06:08:12
I wanna send an email in my c++ program, it seems little complex. Is there way to use yahoo or gmail to use them to send my emails? Bas Bossink A basic internet search reveals the following: C++ SMTP example VMime a C++ Mail library libsmtp a C library to send mail via smtp In short if you have a gmail or yahoo account you can use their SMTP server to send messages using either of the three links above to assist you in using SMTP. You could try using the SMTPClientSession from the POCO library. This tutorial has everything you need, if you are working in a .net environment. 来源: https:/

雅虎34条军规

有些话、适合烂在心里 提交于 2019-12-01 18:48:24
官方原地址:http://developer.yahoo.com/performance/rules.html 另附 SAE CDN: http://lib.sinaapp.com/ 雅虎团队经验:网站页面性能优化的34条黄金守则 1、尽量减少HTTP请求次数 终端用户响应的时间中,有80%用于下载各项内容。这部分时间包括下载页面中的图像、样式表、脚本、Flash等。通过减少页面中的元素可以减少HTTP请求的次数。这是提高网页速度的关键步骤。 减少页面组件的方法其实就是简化页面设计。那么有没有一种方法既能保持页面内容的丰富性又能达到加快响应时间的目的呢?这里有几条减少HTTP请求次数同时又可能保持页面内容丰富的技术。 合并文件是通过把所有的脚本放到一个文件中来减少HTTP请求的方法,如可以简单地把所有的CSS文件都放入一个样式表中 。 当脚本或者样式表在不同页面中使用时需要做不同的修改,这可能会相对麻烦点,但即便如此也要把这个方法作为改善页面性能的重要一步。 CSS Sprites是减少图像请求的有效方法。 把所有的背景图像都放到一个图片文件中 ,然后通过CSS的background-image和background-position属性来显示图片的不同部分; 图片地图是把多张图片整合到一张图片中。虽然文件的总体大小不会改变,但是可以减少HTTP请求次数

codeigniter localhost email not sending

佐手、 提交于 2019-12-01 12:15:13
I have some problem and I don't understand. This is my code $this->load->library('email'); $config['protocol'] = 'sendmail'; $config['mailpath'] = '/usr/sbin/sendmail'; $config['charset'] = 'iso-8859-1'; $config['wordwrap'] = TRUE; $this->email->initialize($config); $this->email->from('rudzstyle@yahoo.co.id', 'Your Name'); $this->email->to('rudzstyle@gmail.com'); $message = $data->nama_depan.'<br>'.$this->input->post('snk'); $this->email->subject($message); $this->email->message('Testing the email class.'); $this->email->send(); echo $this->email->print_debugger(); that 2 email are active

codeigniter localhost email not sending

…衆ロ難τιáo~ 提交于 2019-12-01 10:56:58
问题 I have some problem and I don't understand. This is my code $this->load->library('email'); $config['protocol'] = 'sendmail'; $config['mailpath'] = '/usr/sbin/sendmail'; $config['charset'] = 'iso-8859-1'; $config['wordwrap'] = TRUE; $this->email->initialize($config); $this->email->from('rudzstyle@yahoo.co.id', 'Your Name'); $this->email->to('rudzstyle@gmail.com'); $message = $data->nama_depan.'<br>'.$this->input->post('snk'); $this->email->subject($message); $this->email->message('Testing the

Email authentication (Gmail, Yahoo etc) — android [duplicate]

℡╲_俬逩灬. 提交于 2019-12-01 05:07:05
问题 This question already has answers here : How should I validate an e-mail address? (32 answers) Closed 6 years ago . I am pretty new to this topic, is that possible to authenticate all email id in one stretch. Actual need is i want to authenticate the email(gmail, yahoo etc) in my application, once the authenticate approves, it should continue to my application. It may be single sign on or whatever. Is this possible to do. Can anyone guide me on this topic. Thanks in advance 回答1: I'm not 100%

DotNetOpenAuth: Message signature was incorrect

六眼飞鱼酱① 提交于 2019-11-30 23:51:11
问题 I'm getting a "Message signature was incorrect" exception when trying to authenticate with MyOpenID and Yahoo. I'm using pretty much the ASP.NET MVC sample code that came with DotNetOpenAuth 3.4.2 public ActionResult Authenticate(string openid) { var openIdRelyingParty = new OpenIdRelyingParty(); var authenticationResponse = openIdRelyingParty.GetResponse(); if (authenticationResponse == null) { // Stage 2: User submitting identifier Identifier identifier; if (Identifier.TryParse(openid, out

Yahoo YQL RSS - Bad Request

≡放荡痞女 提交于 2019-11-30 23:44:57
For making cross-domain AJAX requests with jQuery, I am trying to use YQL RSS. select * from rss where url='https://www.top1000funds.com/feed/most-popular-posts/' My code: var feed = "https://www.top1000funds.com/feed/most-popular-posts/"; var yql = "https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20rss%20where%20url%3D%22"+encodeURIComponent(feed)+"%22&format=json&diagnostics=true&callback=&rnd=_"+event.timeStamp; console.log(yql); $.getJSON(yql, function(res) { var html = '<div class="feedListWrap">'; if(res.query && res.query.results && res.query.results.item){ //code goes

phpmailer, php, header, email goes to spam

你说的曾经没有我的故事 提交于 2019-11-30 20:32:07
I am running into a problem while sending out emails from the system and the problem is that the email gets delivered to the spam box in gmail/yahoo/hotmail. I am posting here, after doing my bit of homework, and have already validated and checked the SPF settings, Reverse DNS settings(was pointing elsewhere, and made the change this morning about 5 hours ago). The RDNS check now says the mapping is perfect. Yet no luck. Mails are going to spambox. What could be the problem? Background : I use PHP with PHPMailer to send out emails. The header from the mail received in the spam box : Delivered

Yahoo YQL RSS - Bad Request

落爺英雄遲暮 提交于 2019-11-30 19:26:03
问题 For making cross-domain AJAX requests with jQuery, I am trying to use YQL RSS. select * from rss where url='https://www.top1000funds.com/feed/most-popular-posts/' My code: var feed = "https://www.top1000funds.com/feed/most-popular-posts/"; var yql = "https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20rss%20where%20url%3D%22"+encodeURIComponent(feed)+"%22&format=json&diagnostics=true&callback=&rnd=_"+event.timeStamp; console.log(yql); $.getJSON(yql, function(res) { var html = '

How do I combine multiple rest queries using YQL?

余生颓废 提交于 2019-11-30 18:50:35
问题 For example I would like to combine multiple queries rest queries together. Right now I do the following code with different URLs one at a time. I think it would be faster to ultimately make one request for 10 links in my case. Any help is appreciated. use 'http://javarants.com/yql/javascript.xml'as j; select * from j where code='response.object = y.rest("http://feedproxy.google.com/~r/Techcrunch/~3/P%5FqWQXyAPU/").followRedirects(false).get().headers.location;' 回答1: One possibility would be