xslt

undefined: undefined error when calling XSLTProcessor.prototype.importStylesheet

拈花ヽ惹草 提交于 2020-04-16 03:26:23
问题 I want to prettify some XML, and I found following code (in this answer, JSFiddle). I modified it like this: const xsltDoc = new DOMParser().parseFromString([ // describes how we want to modify the XML - indent everything '<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform">', ' <xsl:output omit-xml-declaration="yes" indent="yes"/>', ' <xsl:template match="node()|@*">', ' <xsl:copy><xsl:apply-templates select="node()|@*"/></xsl:copy>', ' </xsl:template>', '</xsl:stylesheet>', ]

How to output ampersand (&) from XSLT

风格不统一 提交于 2020-04-10 09:41:30
问题 I'm converting all & into & in my XML so that the XSLT will compile. I'm styling the XML into HTML. However when a textbox is populated by the XSLT, I need the & to display as & . For example, it shows " you & me " in the text box, but I need to see " you & me ". 回答1: How to output & as & in XSLT In general, here are alternative techniques for outputting & as & : Globally: <xsl:output method="html"/> or <xsl:output method="text"/>` For ampersands originating from XSLT: <xsl:text disable

How to output ampersand (&) from XSLT

我是研究僧i 提交于 2020-04-10 09:41:09
问题 I'm converting all & into & in my XML so that the XSLT will compile. I'm styling the XML into HTML. However when a textbox is populated by the XSLT, I need the & to display as & . For example, it shows " you & me " in the text box, but I need to see " you & me ". 回答1: How to output & as & in XSLT In general, here are alternative techniques for outputting & as & : Globally: <xsl:output method="html"/> or <xsl:output method="text"/>` For ampersands originating from XSLT: <xsl:text disable

How to get only changes of two xml files in c# context?

你说的曾经没有我的故事 提交于 2020-03-25 19:29:40
问题 Im setting up an XML Translator and before this step, I have to compare two XML Files, filter out the changes or entrys that are new and save only the changes in a new file. With XmlDiffPatch I was able to compare the two files and save it in a DiffGram format. But when I patch the diffGramFile and the originalFile , the output is just like my originalFile so I win nothing out of it. Is there a way to delete duplicates of two files or like only save the changes? This is my code to generate a

Modifying a XSLT for converting XML to tab delimited text file

爷,独闯天下 提交于 2020-03-25 08:45:08
问题 A system that I am using currently allows me to export selected record data in XML format. The system also provides an option to use XSLT to transform the XML. I like to use it to convert the XML to tab delimited text so that I can import the data to another application. Here is a XML sample with three records exported. Four data fields are selected to be exported with each record. <?xml version="1.1" encoding="UTF-8"?> <!DOCTYPE Export> <ns:Export xmlns:ns="http://www.canto.com/ns/Export/1.0

XSLT for grouping and summing values

落花浮王杯 提交于 2020-03-24 02:45:19
问题 I am a newbie to XSLT and am having trouble accomplishing a result and I come here in case anyone can help me. I have the following XML: <funds> <bags> <bag name="BAG_USD_MAIN" value="10.0" type="USD"> <pockets> <pocket name="bank" value="7.5"> <pocket name="award" value="2.5"> </pockets> </bag> <bag name="BAG_USD_SAVINGS" value="290.75" type="USD"> <pockets> <pocket name="bank" value="290.75"> </pockets> </bag> <bag name="BAG_EUR_EXTRA" value="890.0" type="EUR"> <pockets> <pocket name="bank"

XSLT for grouping and summing values

心已入冬 提交于 2020-03-24 02:45:18
问题 I am a newbie to XSLT and am having trouble accomplishing a result and I come here in case anyone can help me. I have the following XML: <funds> <bags> <bag name="BAG_USD_MAIN" value="10.0" type="USD"> <pockets> <pocket name="bank" value="7.5"> <pocket name="award" value="2.5"> </pockets> </bag> <bag name="BAG_USD_SAVINGS" value="290.75" type="USD"> <pockets> <pocket name="bank" value="290.75"> </pockets> </bag> <bag name="BAG_EUR_EXTRA" value="890.0" type="EUR"> <pockets> <pocket name="bank"

xsl string-join() multiple variables - only use non-empty

こ雲淡風輕ζ 提交于 2020-03-20 08:38:15
问题 I'd like to create several xsl:variable that may or may not be null then join them: <xsl:variable name="creatorType" select="replace(lib:merge(subfields/subfield[matches(@code,'[e]')],' '),'author|[.$]','')" /> <xsl:variable name="creatorAttribution" select="replace(lib:merge(subfields/subfield[matches(@code,'[j]')],' '),'[,-.]$','')" /> <xsl:variable name="creatorNameFullForm" select="replace(lib:merge(subfields/subfield[matches(@code,'[q]')],' '),'[,-()]$','')" /> <xsl:variable name=

xsl string-join() multiple variables - only use non-empty

一个人想着一个人 提交于 2020-03-20 08:36:58
问题 I'd like to create several xsl:variable that may or may not be null then join them: <xsl:variable name="creatorType" select="replace(lib:merge(subfields/subfield[matches(@code,'[e]')],' '),'author|[.$]','')" /> <xsl:variable name="creatorAttribution" select="replace(lib:merge(subfields/subfield[matches(@code,'[j]')],' '),'[,-.]$','')" /> <xsl:variable name="creatorNameFullForm" select="replace(lib:merge(subfields/subfield[matches(@code,'[q]')],' '),'[,-()]$','')" /> <xsl:variable name=

xsl string-join() multiple variables - only use non-empty

馋奶兔 提交于 2020-03-20 08:36:48
问题 I'd like to create several xsl:variable that may or may not be null then join them: <xsl:variable name="creatorType" select="replace(lib:merge(subfields/subfield[matches(@code,'[e]')],' '),'author|[.$]','')" /> <xsl:variable name="creatorAttribution" select="replace(lib:merge(subfields/subfield[matches(@code,'[j]')],' '),'[,-.]$','')" /> <xsl:variable name="creatorNameFullForm" select="replace(lib:merge(subfields/subfield[matches(@code,'[q]')],' '),'[,-()]$','')" /> <xsl:variable name=