xslt

Retaining entity in xslt stylesheet output without using character-map

久未见 提交于 2020-06-17 13:12:25
问题 Where did we go wrong? When I process this xml with xslt 2 on saxon he: <data> <grab>Grab me and print me back "</grab> </data> using this stylesheet: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/"> <xsl:apply-templates select="/data/grab"/> </xsl:template> <xsl:template match="/data/grab"> <node><xsl:value-of select="text()"/></node> </xsl:template> </xsl:stylesheet> I get this output: <?xml version="1.0" encoding="UTF-8"?><node>Grab

SubGroup in xslt with mutiple keys

为君一笑 提交于 2020-06-17 11:07:18
问题 I have a source xml like below. Im trying to convert to a desired format using xslt as shown below. Sample XML <table> <row> <tablename>table1</tablename> <tableDesc>table1_desc</tableDesc> <columnname>col1</columnname> <columnDesc>col1_desc</columnDesc> <columnDataType>Number</columnDataType> <ultimateSourceTable>sourceTable1</ultimateSourceTable> <ultimateSourceTableDesc>col1sourceTable1_desc</ultimateSourceTableDesc> </row> <row> <tablename>table1</tablename> <tableDesc>table1_desc<

XSLT 1.0: Format JSON output using XSLT/ Remove defualt quotes in an JSON Array

五迷三道 提交于 2020-06-17 09:52:06
问题 I have a the following JSON response, that I'm getting after a XSLT transformation. The values in the "name" array needed to be present as "ABC","XYZ" Payload <Data> <Mapping> <LocationID>001</LocationID> <GeoX>1.00</GeoX> <GeoY>2.00</GeoY> </Mapping> <Mapping> <LocationID>002</LocationID> <GeoX>56.00</GeoX> <GeoY>42.00</GeoY> <Mapping> </Data> Current Code where the Destination object is implemented. <xsl:template match="//Data"> <Destination> <Locations> <xsl:text disable-output-escaping=

edit out portions of a XML file inside an XSL `for-each` loop

大兔子大兔子 提交于 2020-06-17 09:38:28
问题 I am trying to edit out portions of a XML file inside an XSL for-each loop. I have an XML file with several templates, and the XSL file has a for-each loop to display all of them. My goal was to eliminate certain templates from displaying within the XSL for-each loop by targeting individual templateId's inside the node. This is the code: XML <component typeCode="SEWS" contextConductionInd="true"> <section> <templateId root="2.12.840.1.103883.13.20.23.2.68"/> <code code="58907-0" codeSystem="1

visual studio 2015 xsl debugging transformation failed WebException SocketException

半世苍凉 提交于 2020-06-11 07:39:11
问题 When debugging an xslt in VS 2015 I get the following error message "xsl transformation failed see output window for details WebException Unable to connect to the remote server SocketException No connection could be made because the target machine actively refused it 127.0.0.1:1234" If I start debugging with my cursor in the xml document (as opposed to xsl) it sometimes works, but not always. 回答1: In my web project I fixed this by clicking 'debug->start without debugging'. I could then do

visual studio 2015 xsl debugging transformation failed WebException SocketException

二次信任 提交于 2020-06-11 07:38:20
问题 When debugging an xslt in VS 2015 I get the following error message "xsl transformation failed see output window for details WebException Unable to connect to the remote server SocketException No connection could be made because the target machine actively refused it 127.0.0.1:1234" If I start debugging with my cursor in the xml document (as opposed to xsl) it sometimes works, but not always. 回答1: In my web project I fixed this by clicking 'debug->start without debugging'. I could then do

How to select each child node of a parent in a for-each xslt statement?

允我心安 提交于 2020-06-09 18:18:22
问题 I want to select all child nodes from the adviceRow element (see xml data hereunder) in a for each loop. I want to avoid having to write an xslt file like this: <xsl:for-each select="Tables/routeAdviceTable/routeAdviceRows/adviceRow"> <xsl:value-of select="cog" /> <xsl:value-of select="current" /> <xsl:value-of select="distance" /> <xsl:value-of select="dtg" /> etc.. </xsl:for-each> Because a row can have many cells (and i have lots of similar but contentwise different tables) Can I work with

How to select each child node of a parent in a for-each xslt statement?

对着背影说爱祢 提交于 2020-06-09 18:18:13
问题 I want to select all child nodes from the adviceRow element (see xml data hereunder) in a for each loop. I want to avoid having to write an xslt file like this: <xsl:for-each select="Tables/routeAdviceTable/routeAdviceRows/adviceRow"> <xsl:value-of select="cog" /> <xsl:value-of select="current" /> <xsl:value-of select="distance" /> <xsl:value-of select="dtg" /> etc.. </xsl:for-each> Because a row can have many cells (and i have lots of similar but contentwise different tables) Can I work with

How to Split xml String when using XSLT1.0?

时光怂恿深爱的人放手 提交于 2020-05-24 05:33:04
问题 This is my Xml file I want to split month as different ,year as different and 000/xxx as different How can we do that in XSLT1.0 ?? MY xml Code:- <COMBINED-PAYMENT-HISTORY>January:2019,000/XXX|February:2018,000/XXX| </COMBINED-PAYMENT-HISTORY> Result Expected:- <table> <tr> <td>January</td> </tr> <tr> <td class="AccValue1">2019</td> <td class="AccValue1">000/XXX</td> </tr> <tr> <td>February</td> </tr> <tr> <td class="AccValue1">2018</td> <td class="AccValue1">000/XXX</td> </tr> </table> 回答1:

Sectioning different heading levels

人盡茶涼 提交于 2020-05-23 10:52:34
问题 The goal is to group elements starting with different heading levels into sections nested according to those levels. Problem is similar to XSLT: moving a grouping html elements into section levels. The difference here is that heading levels are not in strict order. To give a simplified example, I want to transform an input like <body> <p>0.1</p> <p>0.2</p> <h2>h2.1</h2> <h3>h3.1</h3> <p>3.1</p> <p>3.2</p> <h1>h1.1</h1> <p>1.1</p> <h3>h3.2</h3> <p>3a.1</p> <p>3a.2</p> </body> into this desired