xslt-2.0 | 易学教程

How to update the variable value in xslt?

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问题 I have declared a variable in my .xsl file. Now I want to update the older value with new value. For example: <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main"> <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <Document> <xsl:variable name="topLevelHeadings" select = "//w:body/w:p[w:pPr[w:pStyle[@w:val='Heading1']]]"/> <xsl:variable

using xsl:for-each-group

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Here is my requirement. My sample input document is like below. (I have added white lines to make it clear) <body> Introduction XSLT and XQuery XSLT is used to write stylesheets. XSLT XSLT Some text. <p1 name="bold"> XQuery is used to query XML databases.</p1> XSLT Some text. <p name="h2-title " name=

I would like to implement a `split function/template` which takes as input a string and a delimiter and returns a split array of the string

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I would like to implement a split function/template in XSLT which takes as input a string and a delimiter and returns a split array of the string.. Or rather I'd like the ability to do something along the lines of: <xsl:call-template name="F"> <xsl:with-param name="input" select="'a,b,c,d,e'"/> <xsl:with-param name="replacement"> <option value='$x'>$x</option> </xsl:with-param> </xsl:call-template> which will give me <option value='a'>a</option><option value='b'>b</option><option value='c'>c</option><option value='d'>d</option><option value='e'>e</option> Question targeted at XSLT 1.0 (but i

XSLT - Creating Dynamic Grid

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问题 I am creating dynamic table(grid) using xslt, XSLT : <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:key name="RowAttribsByName" match="Row/@*" use="concat(generate-id(..), '|', name())"/> <xsl:variable name="vColNames" select= "/*/Columns/*[not(@Hidden = 'true')]/@Name"/> <xsl:template match="/*"> <table border="1"> <tr> <xsl:apply-templates select="Columns/*"/> </tr> <xsl:apply-templates select="Rows

Can we do XSLT 2.0 with Netbeans 7?

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In its current form, Netbeans only supports XSLT 1.0 and does not support XSLT 2.0. How do we use XSLT 2.0 with Netbeans 7? How to make Saxon the JRE-installation-default XSLT Processor: (So not only for Netbeans, other Java applications might be impacted as well.) Get Saxon for Java (there are different editions, pick the one suitable for you) and copy saxonXYZ.jar to the jre/lib/ext dir. In the jre/lib dir create a jaxp.properties file with following content: javax.xml.transform.TransformerFactory = net.sf.saxon.TransformerFactoryImpl (Restart Netbeans.) Check success by doing an XSL

Ant xslt task output to stdout

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Using the <xslt> task in ant, how do I get the output to generate to stdout? My XSLT is generating multiple files through xsl:result-document and the normal output is just status information that I'd like to show up with normal Ant output. Ant seems to force me to supply a destdir= or an out= parameter. Ant 1.8.2 with Saxon 9 Yes ant does this. However XSLT has the element which you can use to get output on the stdout :) <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes"/> <xsl:key name="types" match="a" use="text()"/> <xsl

Sorting in XSLT from two xml files

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I have these two xmls 1> default.xml <UI-defination> <class > <list_view > <members> <member col_span="1" name="code" displayName="Code"/> <member col_span="1" name="creationTS" displayName="CreationTS"/> <member col_span="1" name="creator" displayName="Creator"/> <member col_span="1" name="displayName" displayName="DisplayName"/> <member col_span="1" name="emailAddress" displayName="EmailAddress"/> <member col_span="1" name="id" displayName="Id"/> </members> </list_view> </class> </UI-defination> 2>Rules.xml <UI-defination> <class name="Role"> <list_view multiselect="true"> <members> <member

XSLT 2.0 support in JDK 6?

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Does JDK 6 support XSLT 2.0 for transformation. My question is, does it come with an XSLT processor built for XSLT 2.0? or DO I need to go for other libraries like Saxon. No, it doesn't, not by default anyway. As you suggest, you need to use Saxon or another option would be Oracle's XDK . 来源： https://stackoverflow.com/questions/1599957/xslt-2-0-support-in-jdk-6

How to use XSLT 3.0 from a Java application?

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The general java code i use to process XSLT and XML files are : public static final String transformXmlDocument(String inputXmlString, File xsltFile) { TransformerFactory factory = TransformerFactory.newInstance(); StreamSource xslt = new StreamSource(xsltFile); StreamSource text = new StreamSource(new StringReader(inputXmlString)); StringWriter writer = new StringWriter(); StreamResult textOP = new StreamResult(writer); try { Transformer transformer = factory.newTransformer(xslt); transformer.transform(text, textOP); } catch (TransformerConfigurationException e) { e.printStackTrace(); } catch

Using XSLT 2.0 to parse the values of multiple attributes into an array-like structure

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I'd like to be able to select all the attributes of a certain type in a document (for example, //@arch) and then take that node set and parse the values out into second node set. When I say "parse", in specific I mean I want to turn a node set like this: arch="value1;value2;value3" arch="value1:value4" into a node set like this: arch="value1" arch="value2" arch="value3" arch="value1" arch="value4" or something like that; I want to get the individual values out of the attributes and into their own node. If I can get it to that state, I've got plenty of methods for sorting and duplicate removal,