xslt-2.0

Visual Studio not supporting XSLT 2.0

由 老子叫甜甜 提交于 2019-12-23 16:32:40
问题 i am using visual studio 2010 . when running xslt2.0 in that getting below errors xsl:value-of/* ** is not yet implemented. 'xsl:result-document'** is not yet implemented. can any one help me to reslove the above issues 回答1: If you want to use XSLT 2.0 you need to switch from XslCompiledTransform to an XSLT 2.0 processor like the .NET version of Saxon 9 or like AltovaXML or like XmlPrime. Microsoft's XslCompiledTransform is an XSLT 1.0 processor, even in .NET 4.5/VS 2012. However the named

Converting XHTML table with rowspan and colspan to LaTeX

由 老子叫甜甜 提交于 2019-12-23 13:13:54
问题 I have been looking for a suitable solution for conversion of an HTML table to LaTeX. I have found the following questions which is similar to my requirement: XML table to LaTeX Converting XHTML table to LaTeX using XSLT But both of these were not 100% helpful with my current requirement, as it does not involve in conversion of content with both colspan and rowspan . The input HTML would look like: <html> <head> </head> <body> <table border="1"> <tr> <td>This</td> <td>is</td> <td>a</td> <td

Split a node if it has certain children

由 拥有回忆 提交于 2019-12-23 12:43:59
问题 UPDATE: I think I have answered most of this question now, except the handling of <pgBreak> . you can see my updates and current XSLT at the end of this post under the EDIT I asked a similar question yesterday, and received good answers. However, I have since realized this didn't cover all my bases so I am asking a more detailed question today. XML IN <?xml version="1.0" encoding="UTF-8"?> <root> <pgBreak pgId="i"/> <p xml:id="a-01"> <highlight rend="italic">Bacon ipsum dolor sit amet<

xsl sum siblings based on node value

由 為{幸葍}努か 提交于 2019-12-23 12:16:13
问题 I need to apply an xsl transformation that sums certain node values based on the value of one of its sibling nodes. Here's my xml pseudo code: <?xml version="1.0" encoding="ISO-8859-1" ?> <Message> <Body> <Order> <Item> <.../> <Type>widget</Type> <Qty>20</Qty> <.../> </Item> <Item> <.../> <Type>gadget</Type> <Qty>10</Qty> <.../> </Item> <Item> <.../> <Type>widget</Type> <Qty>5</Qty> <.../> </Item> <Item/> </Order> </Body> </Message> The desired result of the the quantity summation for all

How to create html list from flat xml file using XSLT

由 拥有回忆 提交于 2019-12-23 06:08:03
问题 I am looking for a clean way to do the following using XSLT. Convert this source: <para>blah blah</para> <list>num1</list> <list>num2</list> <list>num3</list> <para>blah blah</para> <list>num1</list> <list>num2</list> <para>blah blah blah blah blah</para> To this output: <p>blah blah</p> <ol> <li>num1</li> <li>num2</li> <li>num3</li> </ol> <p>blah blah</p> <ol> <li>num1</li> <li>num2</li> </ol> <p>blah blah blah blah blah</p> Keep in mind I do not know exactly how many <list> 's there will be

XSLT: iterating over variable array to get sorted result not working.

由 ≯℡__Kan透↙ 提交于 2019-12-23 04:45:48
问题 I am parsing itunes library xml file. The information in it is stored in following manner. Tracks information are stored separately and playlist information are stored differently. A playlist consists of different tracks. A typical itunes playlist looks like below. <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE plist PUBLIC "-//Apple Computer//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd"> <plist version="1.0"> <dict> <dict> <dict> <key>Track ID</key> <integer>1769<

Replace the XML element with new Element in SQL server

由 别等时光非礼了梦想. 提交于 2019-12-23 01:42:08
问题 Replace <apipAccessbility> element of this content with a new element in multiple rows with a column of type XML : <Item title="1234" xmlns="http://www.imsglobal.org/xsd/imsqti_v2p2"> <ItemBody>xyz</ItemBody> <apipAccessibility xmlns="http://www.imsglobal.org/xsd/apip/apipv1p0/imsapip_qtiv1p0"> <accessibilityInfo> Blablah </accessibilityInfo> </apipAccessibility> </Item> Once element is updated it should look like this: <Item title="1234" xmlns="http://www.imsglobal.org/xsd/imsqti_v2p2">

Access attribute from within current-grouping-key() xslt

由 ▼魔方 西西 提交于 2019-12-23 01:15:13
问题 I have some xml with thousands of movie elements which can all have 1 or MORE director and writer elements, if a director or writer has the same name as another, as seen here, I add an @differentiator of birthyear, if they are NOT the same person <mediaList> <movie id="1603934" dateCreated="2014-08-11"> <title>Night at the Museum</title> <director>Shawn Levy</director> <LCSpecialTopics>Comedy</LCSpecialTopics> <writer>Robert Ben Garant</writer> <writer differentiator="1970">Thomas Lennon<

XSLT: turn flat list into hierarchy

由 。_饼干妹妹 提交于 2019-12-22 17:58:17
问题 I try to understand the grouping functions in XSLT 2.0. My source document is <root> <entry level="a" name="aaa"/> <entry level="a" name="bbb"/> <entry level="b" name="ccc"/> <entry level="c" name="ddd"/> <entry level="a" name="eee"/> <entry level="a" name="fff"/> <entry level="b" name="ggg"/> </root> and the result should be something like <section name="aaa"/> <section name="bbb"> <section name="ccc"> <section name="ddd" /> </section> </section> <section name="eee"/> <section name="fff">

Ant xslt task output to stdout

由 心已入冬 提交于 2019-12-22 10:10:13
问题 Using the <xslt> task in ant, how do I get the output to generate to stdout? My XSLT is generating multiple files through xsl:result-document and the normal output is just status information that I'd like to show up with normal Ant output. Ant seems to force me to supply a destdir= or an out= parameter. Ant 1.8.2 with Saxon 9 回答1: Yes ant does this. However XSLT has the element which you can use to get output on the stdout :) <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
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