xslt-2.0

XSLT - Updating the Header

删除回忆录丶 提交于 2019-12-25 02:38:25
问题 The request XML i have is given below and the XSLT transformation Iam using is also given. Unfortunately the ordertotal xml tag is repeating twice after transformation. How can i update the existing tag rather than inserting double tag Request XML is <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <ns2:fetchOrderListResponse xmlns:ns2="http://impl.lob.wipro.com/"> <return> <customerOrderNumber>1</customerOrderNumber> <orderDetails> <itemPrice>50.0</itemPrice

xsl use-character-maps eqivalent in xsl 1.0

白昼怎懂夜的黑 提交于 2019-12-25 02:28:29
问题 I have a xsl 2.0 stylsheet which uses xsl 2.0 specific enhancements. I am now trying to move templates in xsl 1.0 as I have some restrictions in using xsl2.0. When I am running my xsl 1.0 templates I am getting some encoding related errors. I wanted to understand what is the equivalent of use-character-maps in xsl 1.0. Thanks 回答1: Character maps are a new feature in XSLT 2.0, there is no equivalent feature in XSLT 1.0. However if you want to output a certain entity or character reference in

Convert copy-of output to string and escape XML special characters (like less than (<) and greater than (>) symbols)

∥☆過路亽.° 提交于 2019-12-25 02:26:40
问题 I am trying this in an XQuery (assume that doc('input:instance') does indeed return a valid XML document) which is generated using XSLT let $a:= <xsl:text>"<xsl:copy-of select="doc('input:instance')//A" />"</xsl:text> let $p := <xsl:text>"<xsl:copy-of select="doc('input:instance')//P" />"</xsl:text> let $r := <xsl:text>"<xsl:copy-of select="doc('input:instance')//R" />"</xsl:text> But I get the error: xsl:text must not contain child elements How do I retrieve XML results using the XPath in

how to extract particular elements

扶醉桌前 提交于 2019-12-25 01:17:05
问题 I need to extract customer names with "Name" and save it in a variable. Input is any dummy xml like response variable should have only this <customer name="Name">John</customer> <customer name="Name">Kevin</customer> <customer name="Name">Leon</customer> <customer name="Name">Adam</customer used this stylesheet <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:template match="/"> <xsl:variable name="request">

XSLT date format translation from eg: Aug 23 2018 to 23/08/2018

◇◆丶佛笑我妖孽 提交于 2019-12-25 00:27:26
问题 How to do date format translation from e.g: Aug 23 2018 to 23/08/2018 using XSLT? 回答1: XSLT 1.0 does not have any date functions and you will need to use string manipulation functions to convert from one format to another and translate Aug to 08 using some processing logic. XSLT 2.0 does have format-date() function however the input format expected by this function is YYYY-MM-DD which can then be converted into formats shown in these examples. You can use the below options for converting the

XSLT doubling outputs with variances for toggled HTML view

别等时光非礼了梦想. 提交于 2019-12-24 21:42:19
问题 XSLT 2.0 The ultimate goal for my project is to output a webpage which provides two views of the same medieval document to the user according to two academic standards, between which the user can toggle with a button (see a proof of concept from 18 months and many iterations ago here ). This requires me to frequently output two HTML segments from a single XSLT template call, differentiated by their @class with value 'inter' or 'diplo'. This is beginning to negatively affect the 'named

How to WRAP the elements in XSLT using for-each-group?

随声附和 提交于 2019-12-24 21:17:07
问题 I want to Wrap value5 to value7 in a single node call COUNTRY using XSLT Example XML Document - <root> <root1> <root2> <value1>somevalue</value1> <value2>somevalue</value2> <value3>somevalue</value3> <value4>somevalue</value4> <value5>Australia</value5> <value6>India</value6> <value7>USA</value7> <value8>somevalue</value8> <value9>somevalue</value9> <value10>somevalue</value10> </root2> </root1> </root> Output XML - <root> <root1> <root2> <value1>somevalue</value1> <value2>somevalue</value2>

XSLT Sort grandchild nodes and pick the value of another grandchild

為{幸葍}努か 提交于 2019-12-24 21:01:16
问题 I am trying to figure out the XSLT (CSV output) for the below XML. I would like to sort the grandchildren nodes i.e. sort Month node and pick the Sales_Program-ID node value of the set with the highest month value. XML <Root> <Level1> <EMPLID>123</EMPLID> <Program> <Sales_Program Name="XYZ"> <ID1>ab</ID1> </Sales_Program> <Start_Date>Jan1st</Start_Date> **<Month>1</Month>** </Program> <Program> <Sales_Program Name="ABC"> <ID1>cd</ID1> </Sales_Program> <Start_Date>Feb1</Start_Date> **<Month>2<

xslt Merge children of 2 parents and Store in a variable

大城市里の小女人 提交于 2019-12-24 19:37:28
问题 I receive an xml input like this: <root> <Tuple1> <child11></child11> <child12></child12> <child13></child13> </Tuple1> <Tuple1> <child11></child11> <child12></child12> </Tuple1> <Tuple2> <child21></child21> <child22></child22> </Tuple2> <Tuple2> <child21></child21> <child22></child22> <child23></child23> </Tuple2> </root> How can I merge the children of each Tuple1 with children of Tuple2 and store them in a variable that will be used in the rest of xslt document? First tuple1 will be merged

Does the name of the xsl:template effects the result of function fn:key,and why? thanks a lot

橙三吉。 提交于 2019-12-24 19:33:26
问题 I find a appearance , that I can't get a correct result with fn:key function in a template which has a name attribute. When I just delete the name attribute of xsl:template, the result are right. That amazes me. Would somebody like to tell the reason? thanks. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:rel="http:/