xslt-1.0

This is my xml input <issues> <issue status="open" type="Bug"> <fix_versions> <fix_version>6.14.0</fix_version> <fix_version>6.13.0</fix_version> <fix_version>6.12.0</fix_version> </fix_versions> <title>issue1</title> <description>Description</description> </issue> <issue status="open" type="Feature"> <fix_versions> <fix_version>6.13.0</fix_version> </fix_versions> <title>issue2</title> <description>Description</description> </issue> <issue status="open" type="Improvement"> <fix_versions> <fix_version>6.14.0</fix_version> </fix_versions> <title>issue3</title> <description>Description<

Does contains() work for multiple words stored in a variable? Will the below one work? If it won't work, please help me with a solution. <xsl:variable name="games" select="footballvolleyballchesscarrom"/> <xsl:when test="contains($games,'chess,carrom')">CORRECT</xsl:when> I think multiple variables will not work with contains method. As per the defination: boolean contains(str1, str2) str1 : A string that might contain the second argument. str2: A string that might be contained in the first argument. Refer : https://msdn.microsoft.com/en-us/library/ms256195(v=vs.110).aspx You can use or

I have a requirement where i need to show the difference amount ( <TotalAmount> ) based on two different values which is in different section.The input xml as below. <TXLife xmlns="http://ACORD.org/Standards/Life/2"> <TXLifeRequest> <FundCode>LTRW00</FundCode> <AccountNumber>34142</AccountNumber> <ReversalInd>Cr</ReversalInd> <TotalAmount>1600</TotalAmount> </TXLifeRequest> <TXLifeRequest> <FundCode>LTRW00</FundCode> <AccountNumber>34142</AccountNumber> <ReversalInd>Dr</ReversalInd> <TotalAmount>350</TotalAmount> </TXLifeRequest> <TXLifeRequest> <FundCode>LUL500</FundCode> <AccountNumber>34142

I want the output xml to have grouped for the element 'c', according to the attribute 'f'. Here is my input xml and the xslt. I want the group to occur only once and the other nodes should be copied as is to the output. The xslt i tried, copies the entire input xml. So if there are two or more elements with c element and same attribute value for 'f', want the first occurence of that group to the output. My wanted result is also copied. input xml <M> <a> <b> <c f="123"> <d>Al</d> <e NO="678"> <f>Y</f> <g> <h>FTO</h> </g> </e> </c> </b> </a> <a> <b> <c f="123"> <d>Al</d> <e NO="678"> <f>Y</f> <g

Similar to this question (http://stackoverflow.com/q/1333558/948404) I want to use XPath to calculate a sum over products in a structure like this: <items> <item> <value>1.0</value> <quantity>3</quantity> </item> <item> <value>2.5</value> <quantity>2</quantity> </item> <!-- ... --> </items> Is there an XPath expression that calculates the sum of the products of each items value and quantity ? Update: The solution has to work with PHPs XSLTProcessor class meaning that it probably has to be XSLT 1.0 compliant. This is why I did not yet accept the two probably correct answers using XSLT 2.0. I

Trying to calculate day of the week number from date. Found some examples in the internet, but instead of day of the week number i see this : NaN. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:strip-space elements="*"/> <xsl:output indent="yes"/> <xsl:template match="node()"> <xsl:copy> <xsl:apply-templates/> </xsl:copy> </xsl:template> <xsl:template match="date"> <xsl:copy> <xsl:call-template name="date-format"> <xsl:with-param name="date-time" select="."/> </xsl:call-template> </xsl:copy> </xsl:template> <xsl