xquery | 易学教程

how to add attribute for all subnodes of the xml in sql

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问题 I have a xml like below in a variable @xml <ContentTemplate> <Tab Title="Lesson"> <Section Title="Lesson Opening" /> <Section Title="Lesson/Activity" /> </Tab> <Tab Title="Wrap Up and Assessment"> <Section Title="Lesson Closing" /> <Section Title="Tracking Progress/Daily Assessment" /> </Tab> <Tab Title="Differentiated Instruction"> <Section Title="Strategies - Keyword" /> <Section Title="Strategies – Text" /> <Section Title="Resources" /> <Section Title="Acceleration/Enrichment" /> </Tab>

Oracle Ora 错误解决方案合集

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注：本文来源于《 Oracle学习笔记 --- Oracle ORA错误解决方案》 ORA-00001: 违反唯一约束条件 (.) 错误说明：当在唯一索引所对应的列上键入重复值时，会触发此异常。 ORA-00017: 请求会话以设置跟踪事件 ORA-00018: 超出最大会话数 ORA-00019: 超出最大会话许可数 ORA-00020: 超出最大进程数 () ORA-00021: 会话附属于其它某些进程；无法转换会话 ORA-00022: 无效的会话 ID；访问被拒绝 ORA-00023: 会话引用进程私用内存；无法分离会话 ORA-00024: 单一进程模式下不允许从多个进程注册 ORA-00025: 无法分配 ORA-00026: 丢失或无效的会话 ID ORA-00027: 无法删去当前会话 ORA-00028: 您的会话己被删去 ORA-00029: 会话不是用户会话 ORA-00030: 用户会话 ID 不存在。 ORA-00031: 标记要删去的会话 ORA-00032: 无效的会话移植口令 ORA-00033: 当前的会话具有空的移植口令 ORA-00034: 无法在当前 PL/SQL 会话中 ORA-00035: LICENSE_MAX_USERS 不能小于当前用户数 ORA-00036: 超过递归 SQL () 级的最大值 ORA-00037:

IBM DB2 SQL error code list

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SQL return codes that are preceded by a minus sign (-) indicate that the SQL statement execution was unsuccessful. IBM DB2 SQL error code list 官方文档地址： https://www.ibm.com/support/knowledgecenter/SSEPEK_10.0.0/codes/src/tpc/db2z_n.html -007 STATEMENT CONTAINS THE ILLEGAL CHARACTER invalid-character -010 THE STRING CONSTANT BEGINNING string IS NOT TERMINATED -011 COMMENT NOT CLOSED -029 INTO CLAUSE REQUIRED -051 identifier-name (sql-type) WAS PREVIOUSLY DECLARED OR REFERENCED -056 AN SQLSTATE OR SQLCODE VARIABLE DECLARATION IS IN A NESTED COMPOUND STATEMENT -057 THE RETURN STATEMENT IN AN SQL

C# What query language to specify in rule to pull out the two book nodes

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问题 <?xml version="1.0" encoding="ISO-8859-1"?> <bookstore> <book category="COOKING"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="CHILDREN"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="WEB"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt Cagle<

C# What query language to specify in rule to pull out the two book nodes

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how to print XML documents to the REPL console when using ConvertTo-Xml in Powershell?

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问题 "almost" printing the elements to the console: PS /home/nicholas/flwor> PS /home/nicholas/flwor> $nodes = Select-Xml "/" $xml PS /home/nicholas/flwor> PS /home/nicholas/flwor> $nodes Node Path Pattern ---- ---- ------- #document InputStream / PS /home/nicholas/flwor> not quite sure how print the actual node values. for larger context,reading in a file and converting it to xml as: PS /home/nicholas/flwor> PS /home/nicholas/flwor> $xml=./bookstore.xml PS /home/nicholas/flwor> PS /home/nicholas

how to include the value of position() in an Xquery result?

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问题 Without using tumbling windows, how is the position itself included in a result? Obviously "$p" should be the "index" of each $item in $items. That being said, iteration isn't guaranteed to be sequential at all. output: <result> <items> <item pos="$p">5</item> <item pos="$p">3</item> <item pos="$p">7</item> <item pos="$p">2</item> <item pos="$p">7</item> <item pos="$p">3</item> </items> </result> query: xquery version "3.1"; let $items := (5,3,7,2,7,3) return <result> <items> { for $item in

How do I get a list of all elements and their attributes via XQuery

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问题 I am quite new to XQuery and I am trying to get a list of all elements and all attributes. It should look like this: element1 @attributex, @attribue y, ... element 2 @attribute x, @attribute y, ... element 3 @attribute x, @attribute y, ... I am trying this so far, but the error "Item expected, sequence found": for $x in collection("XYZ") let $att := local-name(//@*) let $ele := local-name(//*) let $eleatt := string-join($ele, $att) return $eleatt I feel like I am turning an easy step into a

How do I get a list of all elements and their attributes via XQuery

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nested looping within Xquery results in a mismatch? and idioms

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问题 I'm playing with the bookstore XML from w3schools: <bookstore> <book category="cooking"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="children"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="web"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt