wpfdatagrid

I want the context menu for a DataGrid's column headers to be different than the rest of the cells. So using the regular ContextMenu property is not going to work. There is DataGrid.RowHeaderTemplate, but I can't find DataGrid.ColumnHeaderTemplate. Edit/Note: Columns are generated dynamically. WPF-it Target a common Style to all DataGridColumnHeaders: <DataGrid.Resources> <ContextMenu x:Key="DataGridColumnHeaderContextMenu" ...> </ContextMenu> <Style TargetType="{x:Type DataGridColumnHeader}"> <Setter Property="ContextMenu" Value="{StaticResource DataGridColumnHeaderContextMenu}" /> </Style> <

I have a matrix kind datagrid like this. this grid is designed entirely in XAML Now how to insert values into these datagridcell with 2 dimensional array ? the values which is needed to be inserted must be of bool datatype (either TRUE or FALSE). Any ideas ? Here is my approach for a MVVM scenario, using a converter which creates a DataView which can be bound to the grids ItemsSource . It's for a special Matrix datatype which holds doubles, but you'll be able to modify it yourself for your requirements: public class MatrixToDataViewConverter : IValueConverter { public object Convert(object

How to change column header's background color when using WPF datagrid? Need to modify xaml directly? Use a style with a setter targeted at DataGridColumnHeader: <DataGrid> <DataGrid.Resources> <Style BasedOn="{StaticResource {x:Type DataGridColumnHeader}}" TargetType="{x:Type DataGridColumnHeader}"> <Setter Property="Background" Value="Blue" /> </Style> </DataGrid.Resources> </DataGrid> Jeetendra negi Use this: <windows.Resources> <LinearGradientBrush x:Key="HeaderBrush" StartPoint="0.5,0" EndPoint="0.5,1"> <GradientStop Color="#FF6B8E95" Offset="0"/> <GradientStop Color="#FF14A7C1" Offset="1

My source is in a MySQL database, I've made an update command and now I need to refresh my DataGrid . MySqlCommand cmd = new MySqlCommand( "update request set status = " + StatusRequest(value) + " where id = " + rowView[0].ToString() + "", conn); MySqlDataReader myReader = cmd.ExecuteReader(); How do I refresh my DataGrid ? Reload the datasource of your grid after the update myGrid.ItemsSource = null; myGrid.ItemsSource = myDataSource; Try mydatagrid.Items.Refresh() From MSDN - CollectionViewSource.GetDefaultView(myGrid.ItemsSource).Refresh(); Bind you Datagrid to an ObservableCollection , and

I want to copy all the datagrid records into datatable without using any loop. For Ex: Dim dt as New DataTable dt = Datagrid1.Items But this is not Working and giving an error message. My Development platform is Visual studio 2010 and language is WPF with vb.net 4.0 Rishap Gandhi This is the way to transfer all the records from DATAGRID to DATATABLE without using the LOOP. VB: Dim dt As New DataTable dt = CType(DataGrid1.ItemsSource, DataView).ToTable C#: DataTable dt = new DataTable(); dt = ((DataView)DataGrid1.ItemsSource).ToTable(); It depends how the datagrid is populated. If the

Well, actually rotated -90 degrees from horizontal is what I mean. I need to do this because the text for the header is quite long but the cell value is short, and I want to fit a lot of columns on the screen. Is it possible to do this easily or do I need to learn about resources and templates first? I don't mind a "hack" solution! This will rotate the whole ColumnHeaderCell: <DataGrid.ColumnHeaderStyle> <Style TargetType="{x:Type DataGridColumnHeader}"> <Setter Property="LayoutTransform"> <Setter.Value> <RotateTransform Angle="270" /> </Setter.Value> </Setter> </Style> </DataGrid

I'm using the excellent MVVM Light Toolkit. My ViewModel exposes: public const string CourtCodesTypeCourtPropertyName = "CourtCodesTypeCourt"; private List<CourtType> _courtCodesTypes = new List<CourtType>(); public List<CourtType> CourtCodesTypeCourt { get { return _courtCodesTypes; } set { if (_courtCodesTypes == value) { return; } var oldValue = _courtCodesTypes; _courtCodesTypes = value; // Update bindings and broadcast change using GalaSoft.MvvmLight.Messenging RaisePropertyChanged(CourtCodesTypeCourtPropertyName, oldValue, value, true); } } public const string CourtCodesPropertyName =