wireframe

问题 I'm trying to draw a 3d image that displays a ripple: function myFunc(x, y) { let zRipple = Math.pow(2, -0.005 * (Math.abs(x) + Math.abs(y))) * Math.cos(((x * x + y * y) * 2 * pi) / 180 / width) * height; return zRipple; } width and height here are constants that define a drawing area and are equal to 200 in my tests. My approach is based on what I recall from an article that I read 30 years ago and trying to recall now. The idea is to: split the whole drawing board into the 10-pixel grid for

问题 I'm trying to draw a 3d image that displays a ripple: function myFunc(x, y) { let zRipple = Math.pow(2, -0.005 * (Math.abs(x) + Math.abs(y))) * Math.cos(((x * x + y * y) * 2 * pi) / 180 / width) * height; return zRipple; } width and height here are constants that define a drawing area and are equal to 200 in my tests. My approach is based on what I recall from an article that I read 30 years ago and trying to recall now. The idea is to: split the whole drawing board into the 10-pixel grid for

问题 This question already has an answer here : Manually defining the colours of a wireframe (1 answer) Closed 2 years ago . Is there a way to change the drape color scale in lattice: wireplot? I have a series of plots and would like to adjust the colors so they each show the same color scale. I am able to change the z axis scale, but that only makes it so the surface itself moves up and down, not the color scale. Is there a keyword I am missing when looking it up? wireframe(InitFe2solid.ug.gdw

问题 I have a fixed header at the top of the screen, and if I try to put an element after the header, said element ends up ignoring the height of the header. HTML <header></header> <p>Empty text</p> CSS header { display: block; height: 100px; width: 100%; background: #eee; position: fixed; top: 0; z-index: 100; } JSFIDDLE I've searched on StackOverflow and other places for solutions to problems similar to this but with no avail (in part due to me having a hard time verbalizing the specific problem

问题 I'm trying to implement the paper "Single-Pass Wireframe Rendering", which seems pretty simple, but it's giving me what I'd expect as far as thick, dark values. The paper didn't give the exact code to figure out the altitudes, so I did it as I thought fit. The code should project the three vertices into viewport space, get their "altitudes" and send them to the fragment shader. The fragment shader determines the distance of the closest edge and generates an edgeIntensity. I'm not sure what I

问题 Qt3D documentation is increasing but still lacking some information especially on how to do things without Qml/QtQuick. After heavily searching the web about rendering a mesh in wireframe mode I found a lot of helpful hints and examples that all together resulted in an example viewer that I wanted to present here as a contribution to all the guys that wrote the articles and others who may have searched similar examples. The most helpful links were these: Qt basic shapes example Qt wireframe

问题 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. Closed 8 years ago . I'm looking for an easy to use wireframing tool. I've heard of gliffy, are there any others? Specifically, I'd like something that is

问题 Does Mathematica support hidden line removal for wire frame images? If this isn't the case, has anybody here ever come across a way to do it? Lets start with this: Plot3D[Sin[x+y^2], {x, -3, 3}, {y, -2, 2}, Boxed -> False] To create a wire frame we can do: Plot3D[Sin[x+y^2], {x, -3, 3}, {y, -2, 2}, Boxed -> False, PlotStyle -> None] One thing we can do to achieve the effect is to color the all the surfaces white. This however, is undesirable. The reason is because if we export this hidden

问题 I am trying to draw a colored mesh plot of a travelling wave like this (just ignore the grey background): I am looking at the example shown in How to obtain 3D colored surface via Python?, but I'm not sure how to adapt it for my function z : from mpl_toolkits.mplot3d import axes3d, art3d import matplotlib.pyplot as plt import numpy as np import matplotlib as mpl fig = plt.figure() ax = fig.add_subplot(111, projection='3d') X = T = np.arange(0,10,0.1) z = np.array([np.cos(2*np.pi*(x/3.0-t/6.0)

问题 Assume I want to plot the following dataframe: df <- data.frame(expand.grid(1:10,1:10),rep(10,100)) colnames(df) <- c("x","y","z") with the lattice wireframe() function: wireframe(z~x*y,df,colorkey=TRUE,drape=TRUE) How do I get it to plot the given coordinates? I would assume it has something to do with having to scale/adjust the z-axis as the automatic scaling within wireframe is probably confused by all z-coordinates being equal. 回答1: Just add a zlim argument. wireframe(z~x*y,df,colorkey