wildcard

Subdomain wildcard htaccess redirection to new domain

回眸只為那壹抹淺笑 提交于 2019-12-10 09:43:38
问题 One of my websites I want to redirect o another domain. The situation: [old] *.example.com [new] *.example.net for now I have this in my htaccess #RewriteCond %{HTTP_HOST} ^(.*).allwebsitestats.com [NC] #RewriteRule ^(.*)$ http://$1.allwebsitestats.nl [R=301,L] The result of this; Request [old] *.example.com results in [new] .example.net, the problem is it doesn't get the wildcard subdomain with it. Thanks you! Regards, Nick 回答1: Enable mod_rewrite and .htaccess through httpd.conf and then

Makefile pattern rule either ignores phony rule or spontaneously deletes output file

天涯浪子 提交于 2019-12-10 05:26:02
问题 I'm trying to write a makefile to produce several output files for each of several sources, using pattern rules. I have the following Makefile (GNU Make 3.8.1): all : foo.all bar.all %.all : %.pdf %.svg @echo Made $* %.pdf : touch $@ %.svg : touch $@ .PHONY: foo.all bar.all Since *.all do not represent real output files, I tried marking them as .PHONY. However, running make then doesn't work: $ ls Makefile $ make make: Nothing to be done for `all'. According to make -d : No implicit rule

Generics (and Wildcards) in Java

倖福魔咒の 提交于 2019-12-10 04:49:47
问题 A book I am reading on Java tells me that the following two pieces of code are equivalent: public <T extends Animal> void takeThing(ArrayList<T> list) public void takeThing(ArrayList<? extends Animal> list); On the opposite page, I am informed that the latter piece of code uses the '?' as a wildcard, meaning that nothing can be added to the list. Does this mean that if I ever have a list (or other collection types?) that I can't make them simultaneously accept polymorphic arguments AND be re

Using rm * (wildcard) in envoy: No such file or directory

梦想的初衷 提交于 2019-12-10 04:24:39
问题 I'm using Python and Envoy. I need to delete all files in a directory. Apart from some files, the directory is empty. In a terminal this would be: rm /tmp/my_silly_directory/* Common sense dictates that in envoy, this translates into: r = envoy.run('rm /tmp/my_silly_directory/*') However: r.std_err -> "rm: cannot remove `/tmp/my_silly_directory/*': No such file or directory" Naturally there are alternatives to using envoy in this case, I am simply wondering why it doesn't work. Any clues? 回答1

Is there such a thing as a wildcard character in Java?

大兔子大兔子 提交于 2019-12-10 04:03:00
问题 I'm running a comparison program and at the minute it does a direct 'string-to-string' comparison and if they are an exact match it outputs that they are a match. Well, I was hoping to add an additional feature that allowed for 'similarity'... so for example: String em1 = "52494646"; String em2 = "52400646"; if (em1.equals(em2)){ output.writeUTF(dir + filenames[i]); } This is sort of a snippet of the code. I'd like it so that it skips over the "00" and still recognises it as 'almost' the same

Apache Spark: Using folder structures to reduce run-time of analyses

本秂侑毒 提交于 2019-12-09 13:39:53
问题 I want to optimize the run-time of a Spark application by subdividing a huge csv file into different partitions, dependent of their characteristics. E.g. I have a column with customer ids (integer, a), a column with dates (month+year, e.g. 01.2015, b), and a column with product ids (integer, c) (and more columns with product specific data, not needed for the partitioning). I want to build a folder structure like /customer/a/date/b/product/c . When a user wants to know information about

How can LIKE '%…' seek on an index?

巧了我就是萌 提交于 2019-12-09 11:13:37
问题 I would expect these two SELECT s to have the same execution plan and performance. Since there is a leading wildcard on the LIKE , I expect an index scan. When I run this and look at the plans, the first SELECT behaves as expected (with a scan). But the second SELECT plan shows an index seek, and runs 20 times faster. Code: -- Uses index scan, as expected: SELECT 1 FROM AccountAction WHERE AccountNumber LIKE '%441025586401' -- Uses index seek somehow, and runs much faster: declare @empty

Avoiding Returning Wildcard Types

风流意气都作罢 提交于 2019-12-09 10:41:35
问题 I have a class with a collection of Wildcard Types that is a singleton, something like: public ObliviousClass{ private static final ObliviousClass INSTANCE = new ObliviousClass(); private Map<Key, Type<?>> map = new HashMap<Key, Type<?>>(); public void putType(Key key, Type<?> type){ map.put(type); } // returns the singleton public static ObliviousClass getInstance(){ return INSTANCE; } } I'd like to be able to add different Parameterized types to this collection in client code: void

Wildcard of Number in SQL Server

走远了吗. 提交于 2019-12-09 08:52:48
问题 How to match numbers in SQL Server 'LIKE'. SpaceName ------------ | New_Space_1 | . | . | New_Space_8 | New_Space_9 | New_Space_10 | New_Space_11 | New_Space_SomeString | New_Space_SomeString1 Above is my table contents. I want to get only records ending with Numeric chars, ie I want the records from New_Space_1 to New_Space_11 . Don't want New_Space_SomeString and New_Space_SomeString1 I have some query like this. SELECT SpaceName FROM SpaceTable WHERE SpaceName LIKE 'New_Space_%' But this

“git add” using wildcard is not functioning as I hoped - must I cd into specific directories?

时间秒杀一切 提交于 2019-12-08 23:03:19
问题 When I try to do a basic git add *.erb (or any simple wildcard expressions) git is not recognizing it (them). As a side-note, I have never done this before so I'm sure it's a rookie mistake, but I've found no help in other SO posts or my school's alumni listserv so I thought this post may be appropriate. For (a different) example, git status is giving me: # modified: config/routes.rb # modified: spec/models/question_spec.rb I wanted to only stage the routes file, so I tried git add *s.rb and