widget

问题 I am creating a game and trying to make it in python and tkinter. I have already completed it in word-based python and want to make it graphical. I have created a grid of buttons to be used as a grid and these buttons currently have the letter "O" on them to show an empty space. However, what I would like is the button to show text of where a pirate is and then eventually the player and chests. The text cannot be hard coded as the positions are randomly selected. while len(treasure)

问题 I created a widget inside my custom module. Everything is working and the widget can be embedded onto CMS pages. However, instead of a textarea parameter type I want to add a WYSIWYG editor. This is the significant part in my widget.xml: <parameters> <description translate="label"> <required>0</required> <visible>1</visible> <label>Description</label> <type>textarea</type> </description> </parameters> I wonder if there's a way to extend Magento's functionality to allow a WYSIWYG editor

问题 I want to set the default cursor location inside the entry widget when I run the program. So when I run it I don't have to click inside the widget to start typing. Can anyone help me with this? Actually I'm new at programming import tkinter as tk root = tk.Tk() e = tk.Entry(root) e.pack() tk.mainloop() 回答1: Simply call the focus method for the widget: import tkinter as tk root = tk.Tk() e = tk.Entry(root) e.pack() e.focus() tk.mainloop() 来源： https://stackoverflow.com/questions/59499960/set

问题 I am working on a website where I need a "widget" like view in my layout of Zend Framework 2. the widget should show the operational status of the server (this is done). (Correct me if this is bad MVC style) I have build a controller with the function viewStatusAction(){ ... return $viewModel(array($vars)) } then i want to use a viewHelper to get the status of the action. This is where I'm stuck. I know how to create the viewHelper, but not where to start to get the returned view from the

问题 I am working on a website where I need a "widget" like view in my layout of Zend Framework 2. the widget should show the operational status of the server (this is done). (Correct me if this is bad MVC style) I have build a controller with the function viewStatusAction(){ ... return $viewModel(array($vars)) } then i want to use a viewHelper to get the status of the action. This is where I'm stuck. I know how to create the viewHelper, but not where to start to get the returned view from the

问题 I would like to filter a tree without type in the textfield, but when an event is triggered. I tried subclassing StoreFilterField like this: class MyStoreFilter<M extends ModelData> extends StoreFilterField<M>{ public MyStoreFilter() { super(); } public void startFilter(){ super.onFilter(); } @Override protected boolean doSelect(Store<M> store, M parent, M record, String property, String filter) { String name = record.get("name"); name = name.toLowerCase(); if (name.startsWith(filter

问题 I'm new with the jQueryUI widget factory, therefore it may be silliness what I'll ask. I'd like to create an ajax tooltip where I can set the url of the ajax call through an option but this option is not readable in the _mouseOver method which contains the ajax call. (function($) { $.widget("ui.tooltip", { options: { url: '' }, _create: function() { alert(this.options.url); //it works this.element.bind({ mouseenter: this._mouseOver }); }, _mouseOver: function() { alert(this.options.url); //it

问题 I create connections between widged in the constructor and also initialize them. But the connect not working (inside the methode). Code says alot: MyApp::MyApp(QWidget *parent) : QMainWindow(parent) { ui.setupUi(this); // slider to spinbox connect(ui.slider, SIGNAL(valueChanged(int)), ui.spinbox, SLOT(setValue(int))); // SIGNAL To SLOT not called ui.slider->setValue(2); // I have to set this also: ui.spinbox->setValue(2); } 回答1: Have you tried doing connect(ui.slider, SIGNAL(valueChanged(int)

问题 I have installed the WordPress Calendar plugins, and I'd like (in some point of the page) add this plugins, without add the default Calendar to a widget and call this widget to the page (such as <?php dynamic_sidebar( 'secondary-widget-area' ); ?> ). I mean, like to use SidebarEventsList() for the WP Events Calendar Plugins How can I do it? Which method I need to call? Tried with <? {CALENDAR} ?> as the readme.txt says, but I get an error Parse error: syntax error, unexpected '}' 回答1: To use

问题 I am defining an ipywidget button with the objective to run a function when the user clicks on it: import ipywidgets as widgets Button = widgets.Button(description='Search', disabled=False, button_style='info', tooltip='Search') display(Button) def whenclick(b): if catalogue.selected_index+1 ==2: dfS2 = pd.DataFrame({'Name': nameS2}) print(dfS2) Button.on_click(whenclick) Where nameS2 is: ['S2A_MSIL2A_20191205T110431_N0213_R094_T30TVK_20191205T123107.zip', 'S2B_MSIL2A_20191203T111329_N0213