widget

How to prevent closing the menu after a select?

China☆狼群 提交于 2020-01-24 11:07:15
问题 I am using the jQuery Autocomplete widget and, inspired by this question in order to prevent closing the menu after select , I came up with this code: $(#input_field).autocomplete({ select : function(event, ui) { // I also tried to run 'ui.item.data( "item.autocomplete" );' and it happens // the same thing (keep reading for more information). ui.item.option.selected = false; }, ... }); It works: the menu is not closed after select. However, I get the following error (in the Firebug console):

How to prevent closing the menu after a select?

谁说我不能喝 提交于 2020-01-24 11:06:26
问题 I am using the jQuery Autocomplete widget and, inspired by this question in order to prevent closing the menu after select , I came up with this code: $(#input_field).autocomplete({ select : function(event, ui) { // I also tried to run 'ui.item.data( "item.autocomplete" );' and it happens // the same thing (keep reading for more information). ui.item.option.selected = false; }, ... }); It works: the menu is not closed after select. However, I get the following error (in the Firebug console):

Python bokeh CustomJS callback update DataTable widget

时光毁灭记忆、已成空白 提交于 2020-01-24 00:45:08
问题 How can I update the values of my DataTable widget using Select widget? Here is my sample code: import pandas as pd from bokeh.io import show from bokeh.layout import column from bokeh.models import ColumnDataSource, CustomJS, Select from bokeh.models.widgets import DataTable, TableColumn df = pd.DataFrame({'a': range(10,50), 'b': range(110,150)}) source_foo = ColumnDataSource(data=df.loc[df['a'] < 25]) source_bar = ColumnDataSource(data=df.loc[df['a'] > 25]) source_fill = ColumnDataSource

How can I use a MediaBrowserService with a widget?

我的未来我决定 提交于 2020-01-23 03:16:08
问题 My service extends the MediaBrowserService class and it responds to certain MediaController actions such as getMediaController().getTransportControls().onPlay() . However, I didn't find a way to "control" my service from a Widget, because the MediaController class isn't available from it. How can I communicate with my service? 回答1: The recommended approach is to use a MediaButtonReceiver, which will forward commands to your MediaBrowserService , where you can then handle them by adding a call

How to avoid name clashes in JavaScript widgets

泄露秘密 提交于 2020-01-22 15:03:47
问题 I have a JavaScript widget (a piece of embedded JS and HTML code) that's embedded on other sites. What should I do to make sure it's variable names don't clash with the hosting page variables? I'd like this widget to be "inlined" meaning on the same page as the hosting page, not in an iframe, what's the best way to avoid name clashes with the hosting page or clashes with other widgets? Name clashes can happen in several ways: JavaScript variable names JavaScript function names DOM elements

How to avoid name clashes in JavaScript widgets

為{幸葍}努か 提交于 2020-01-22 15:03:00
问题 I have a JavaScript widget (a piece of embedded JS and HTML code) that's embedded on other sites. What should I do to make sure it's variable names don't clash with the hosting page variables? I'd like this widget to be "inlined" meaning on the same page as the hosting page, not in an iframe, what's the best way to avoid name clashes with the hosting page or clashes with other widgets? Name clashes can happen in several ways: JavaScript variable names JavaScript function names DOM elements

Android - adding AppWidgets to an Activity

我是研究僧i 提交于 2020-01-22 04:32:46
问题 My initial goal is to add the Google Search widget to the linear layout of the activity. I need to include it just like it appears and works in the Launcher (this is why I need to be able to add the widget). I would like to add widgets to my activity whithout having to launch the widget picker activity. I tried to: 1. directly specify an integer id (I always get inflate errors) 2. get the id like this: ComponentName cn = new ComponentName(getBaseContext(), "com.android.quicksearchbox

Connecting two different widgets together on qt with python through a button

故事扮演 提交于 2020-01-22 03:42:06
问题 I was wondering how to connect two widgets together. I have two widgets i created on QtDesigner, one being a Login page, and another being a Main Menu. I want to connect them so that when the Login is successful, the user will be redirected to the Main Window, and the Login widget will close automatically. Does anyone know how to do this? PS. I have the code for the main menu and login in separate .py files 回答1: You could do the following: In your QApp create first a dialogue containing the

How to access Switch button that is declared in MainActivity(layout) in BroadcastReceivers

我的未来我决定 提交于 2020-01-22 03:40:10
问题 I have a task in which i have to change state of Switch button when airplane mode is ON/OFF. I have a main activity in which i declared Switch Button and i want to Change the state on/off of Switch from BroadcastReceiver Class Receiver public class MyReceiver extends BroadcastReceiver { @Override public void onReceive(Context context, Intent intent) { boolean isAirplaneModeOn = intent.getBooleanExtra("state", false); if(isAirplaneModeOn){ What Should i do ? } } } layout_main_activity <?xml

Clear output widget using onclick Button event - Python

我的未来我决定 提交于 2020-01-22 02:21:12
问题 I am working on a Jupyter Notebook in which I am using a button created with ipywidgets to display a df when clicking on it. For this I am using the following code: import ipywidgets as widgets import numpy as np vartest = 0 Button = widgets.Button(description='Search', disabled=False, button_style='info', tooltip='Search') display(Button) def whenclick2(b): global df if vartest==0: df = pd.DataFrame(np.arange(5)) class displayDF(object): def _create_widgets(self): self.button = Button self