which

问题 > which(LETTERS=="A") [1] 1 > which(LETTERS=="B") [1] 2 Can i use one statement in which to get the value of 1,2? which(LETTERS=="B" or "A") Error: unexpected symbol in "which(LETTERS=="B" or" 回答1: which(LETTERS == "A" | LETTERS == "B") Or: which(LETTERS %in% c("A", "B")) 回答2: as answer for the title, how subsetting a vector using multiple conditions: # Random Data test1 <- sample(x = c(1:30),size = 15,replace = TRUE) test2 <- sample(x = c(70:75),size = 15,replace = TRUE) test3 <- sample(x =

问题 I want to choose a file like the following line, which didn't do as I wished. which(substr(rownames(fInfo),1,8) == "mySource" ) & which.max(fInfo$mtime) In an English sentence, I want to choose files whose names start with "mySource" and within those whom chosen, I want to pick the most recently updated file. My script below is suffice, but it is too long. Can someone shorten my script? # create dummy files under Folder "scriptFld" ifelse(!dir.exists(file.path("scriptFld")), dir.create(file

问题 I am trying to find multiple strings in my dataframe, using the which function. I am trying to extend the answer from Find string in data.frame An example dataframe is: df1 <- data.frame(animal=c('a','b','c','two', 'five', 'c'), level=c('five','one','three',30,'horse', 'five'), length=c(10, 20, 30, 'horse', 'eight', 'c')) 1 a five 10 2 b one 20 3 c three 30 4 two 30 horse 5 five horse eight 6 c five c on this dataframe when I apply the which function for one string, I get the correct output e

问题 I would like to use something similar to the OFFSET and MATCH functions of Excel, here is an example data set: data= Which Test?|Test1 |Test2 |Test3 |RESULT Test1 |TRUE |80% |0 | Test2 |FALSE |25% |0 | Test1 |TRUE |16% |0 | Test3 |FALSE |12% |1 | Result column should read: Which Test?|Test1 |Test2 |Test3 |RESULT Test1 |TRUE |80% |0 |TRUE Test2 |FALSE |25% |0 |25% Test1 |TRUE |16% |0 |TRUE Test3 |FALSE |12% |1 |1 In the final RESULT column I would like the test result of searching the Which

问题 I realize this might be a dumb question but I have a Centos-7 minimal server install and the "which" command does not exist or is missing. I have a script that needs it and I cannot find out what the yum package is that installs it. The code is below and is from a make file. which grep > /dev/null 2> /dev/null if test "$?" != "0" then echo "\"grep\" command not found." echo "Installation is aborted." exit 1 fi Any help would be appreciated... this is difficult if not impossible to google 回答1:

问题 What does ( !'which npm' ) mean in the following code? if ( !'which npm' ) { die( 'You need to install NPM!' . PHP_EOL ); } Here is a link to the complete file from GITHUB: WPBP/generator/bin/wpbp-generator 回答1: It checks whether a hardcoded string is falsey . Which will always be false . This logic looks a bit meaningless. I suspect the author rather wanted to write: if (!`which npm`) The backtick operator executes the command as shell command, which makes a bit more sense. 来源： https:/

问题 What does ( !'which npm' ) mean in the following code? if ( !'which npm' ) { die( 'You need to install NPM!' . PHP_EOL ); } Here is a link to the complete file from GITHUB: WPBP/generator/bin/wpbp-generator 回答1: It checks whether a hardcoded string is falsey . Which will always be false . This logic looks a bit meaningless. I suspect the author rather wanted to write: if (!`which npm`) The backtick operator executes the command as shell command, which makes a bit more sense. 来源： https:/

问题 I have a dataset that looks something like this: df <- structure(list(Claim.Num = c(500L, 500L, 600L, 600L, 700L, 700L, 100L, 200L, 300L), Amount = c(NA, 1000L, NA, 564L, 0L, 200L, NA, 0L, NA), Company = structure(c(NA, 1L, NA, 4L, 2L, 3L, NA, 3L, NA), .Label = c("ATT", "Boeing", "Petco", "T Mobile"), class = "factor")), .Names = c("Claim.Num", "Amount", "Company"), class = "data.frame", row.names = c(NA, -9L)) I want to remove duplicate rows based on Claim Num values, but to remove

问题 I am trying to take the following R statement and convert it to Python using NumPy: 1 + apply(tmp,1,function(x) length(which(x[1:k] < x[k+1]))) Is there a Python equivalent to which()? Here, x is row in matrix tmp , and k corresponds to the number of columns in another matrix. Previously, I tried the following Python code, and received a Value Error (operands could not be broadcast together with shapes): for row in tmp: print np.where(tmp[tmp[:,range(k)] < tmp[:,k]]) 回答1: The Python code

问题 Have a look at this live demo (from jQuery's site). Clicking - (dash) in Firefox says that event.which is 173 , while doing the same in Chrome produces 189 . This jQuery page says that event.which should be normalized for cross browser consistency. But, it looks like this is not true. Why is this inconsistency? 回答1: This jQuery page says that event.which should be normalized for cross browser consistency. But, it looks like this is not true. jQuery normalizes the property name (e.g., always