weekday

Need to find next and previous working day in oracle

南笙酒味 提交于 2019-12-01 10:44:32
My query is somewhat like this: select 1 from dual where :p1_task_date in (sysdate,sysdate+1,sysdate-1) and :p1_task_id is not null This works fine, but I wanted to get next/previous working days (next/previous week days) instead of sysdate+1 and sysdate-1. I tried something like: select next_day(sysdate, to_char(sysdate+1,'DAY')) from dual` but cannot proceed with this :( Please Help!!!! @Tawman's answer will work, but I prefer this method for readability: select sysdate as current_date, case when to_char(sysdate,'D') in (1,6,7) then next_day(sysdate,'Monday') else sysdate+1 end as next

Need to find next and previous working day in oracle

流过昼夜 提交于 2019-12-01 09:24:06
问题 My query is somewhat like this: select 1 from dual where :p1_task_date in (sysdate,sysdate+1,sysdate-1) and :p1_task_id is not null This works fine, but I wanted to get next/previous working days (next/previous week days) instead of sysdate+1 and sysdate-1. I tried something like: select next_day(sysdate, to_char(sysdate+1,'DAY')) from dual` but cannot proceed with this :( Please Help!!!! 回答1: @Tawman's answer will work, but I prefer this method for readability: select sysdate as current_date

How to set first day of week in a Java application calendar

十年热恋 提交于 2019-12-01 08:10:37
We use a java application, it has a date selection field, when you click there a small calendar opens. First day of the week is Sunday there. But I want it to be Monday. I try to change it from Windows Control Panel from Date settings. I set Windows calendar's first day to Thursday, for instance. But in Java application's calendar, first day of the week is still Sunday. Is it possible to change the Java application's first day of the week from Windows, or is it only changed from Java application's code? Regards Which framework does your java app use? What kind of component is the date

How to get the day of the week from a Unix timestamp (PHP)?

为君一笑 提交于 2019-11-30 18:34:30
How do I get the day (1-7) from a Unix timestamp in PHP? I also need the day date (1-31) and month (1-12). You can use date() function $weekday = date('N', $timestamp); // 1-7 $month = date('m', $timestamp); // 1-12 $day = date('d', $timestamp); // 1-31 see http://docs.php.net/getdate e.g. $ts = time(); // could be any timestamp $d=getdate($ts); echo 'day of the week: ', $d['wday'], "\n"; echo 'day of the month: ', $d['mday'], "\n"; echo 'month: ', $d['mon'], "\n"; It's the date() function you're after. You can get more details from the PHP manual but in a nutshell here are the functions you

How to set first day of week in a Java application calendar

筅森魡賤 提交于 2019-11-30 18:17:34
问题 We use a java application, it has a date selection field, when you click there a small calendar opens. First day of the week is Sunday there. But I want it to be Monday. I try to change it from Windows Control Panel from Date settings. I set Windows calendar's first day to Thursday, for instance. But in Java application's calendar, first day of the week is still Sunday. Is it possible to change the Java application's first day of the week from Windows, or is it only changed from Java

Java: getting current Day of the Week value

元气小坏坏 提交于 2019-11-30 09:02:29
问题 At the moment, I'm creating a java schedule app and I was wondering how to find the current day of the week while using the Calendar class to get the first day of the week. Here is the method I'm using in a class in order to set up a week schedule public static String getSunday() { SimpleDateFormat d = new SimpleDateFormat(dayDate); Calendar specific = cal; specific.add(Calendar.DAY_OF_YEAR, (cal.getFirstDayOfWeek() - ??)); return d.format(specific.getTime()); } 回答1: You can get the current

Generate series of week intervals for given month

与世无争的帅哥 提交于 2019-11-30 07:03:59
In a Postgres 9.1 database, I am trying to generate a series of weeks for a given month but with some constraints. I need all weeks to start on Monday and get cut when they start or end in another month. Example: For February, 2013 I want to generate a series like this: start ------------------------ 2013-02-01 00:00:00+00 2013-02-04 00:00:00+00 2013-02-11 00:00:00+00 2013-02-18 00:00:00+00 2013-02-25 00:00:00+00 The query that I have now looks like this: SELECT GREATEST(date_trunc('week', dates.d), date_trunc('month',dates.d)) as start FROM generate_series(to_timestamp(1359676800),to

Get weekdays in English in R

廉价感情. 提交于 2019-11-30 06:20:27
问题 I am using R outside the US and I got everything working in English, but the result of weekdays() is still in Spanish: Day <- seq(as.Date("2013-06-01"), by=1, len=30) weekdays(Day) [1] "sábado" "domingo" "lunes" "martes" "miércoles" (...) Any ideas on how to get the weekdays in English? 回答1: Printing of Date and POSIX*t objects seems to be controlled by the LC_TIME locale category. On Windows, you change it like this: ## First in Spanish Sys.setlocale("LC_TIME","Spanish Modern Sort") # [1]

How to get the day of the week from a Unix timestamp (PHP)?

 ̄綄美尐妖づ 提交于 2019-11-30 02:48:53
问题 How do I get the day (1-7) from a Unix timestamp in PHP? I also need the day date (1-31) and month (1-12). 回答1: You can use date() function $weekday = date('N', $timestamp); // 1-7 $month = date('m', $timestamp); // 1-12 $day = date('d', $timestamp); // 1-31 回答2: see http://docs.php.net/getdate e.g. $ts = time(); // could be any timestamp $d=getdate($ts); echo 'day of the week: ', $d['wday'], "\n"; echo 'day of the month: ', $d['mday'], "\n"; echo 'month: ', $d['mon'], "\n"; 回答3: It's the

Generate series of week intervals for given month

南笙酒味 提交于 2019-11-29 08:38:18
问题 In a Postgres 9.1 database, I am trying to generate a series of weeks for a given month but with some constraints. I need all weeks to start on Monday and get cut when they start or end in another month. Example: For February, 2013 I want to generate a series like this: start ------------------------ 2013-02-01 00:00:00+00 2013-02-04 00:00:00+00 2013-02-11 00:00:00+00 2013-02-18 00:00:00+00 2013-02-25 00:00:00+00 The query that I have now looks like this: SELECT GREATEST(date_trunc('week',