web-crawler

Is it possible to crawl billions of pages on a single server? Not if you want the data to be up to date. Even a small player in the search game would number the pages crawled in the multiple billions. " In 2006, Google has indexed over 25 billion web pages,[32] 400 million queries per day,[32] 1.3 billion images, and over one billion Usenet messages. " - Wikipedia And remember the quote is mentioning numbers from 2006. This is ancient history. State of the art is well more than that. Freshness of content: New content is constantly added at a very large rate (reality) Existing pages often

I am trying to goose to read from .html files(specified url here for sake convenience in examples) [1] . But at times it's doesn't show any text. Please help me out here with the issue. Goose version used: https://github.com/agolo/python-goose/ Present version gives some errors. from goose import Goose from requests import get response = get('http://www.highbeam.com/doc/1P3-979471971.html') extractor = Goose() article = extractor.extract(raw_html=response.content) text = article.cleaned_text print text Goose indeed uses several predefined elements which are likely a good starting point for

We actually have burned static/archived copies of our asp.net websites for customers many times. We have used WebZip until now but we have had endless problems with crashes, downloaded pages not being re-linked correctly, etc. We basically need an application that crawls and downloads static copies of everything on our asp.net website (pages, images, documents, css, etc) and then processes the downloaded pages so that they can be browsed locally without an internet connection (get rid of absolute urls in links, etc). The more idiot proof the better. This seems like a pretty common and

Consider the case, I want to crawl websites frequently, but my IP address got blocked after some day/limit. So, how can change my IP address dynamically or any other ideas? aberna An approach using Scrapy will make use of two components, RandomProxy and RotateUserAgentMiddleware . Modify DOWNLOADER_MIDDLEWARES as follows. You will have to insert the new components in the settings.py : DOWNLOADER_MIDDLEWARES = { 'scrapy.contrib.downloadermiddleware.retry.RetryMiddleware': 90, 'tutorial.randomproxy.RandomProxy': 100, 'scrapy.contrib.downloadermiddleware.httpproxy.HttpProxyMiddleware': 110,

I cant seem to get this peice of code to work: $self->{_current_page} = $href; my $response = $ua->get($href); my $responseCode = $response->code; if( $responseCode ne "404" ) { my $content = LWP::Simple->get($href); die "get failed: " . $href if (!defined $content); } Will return error: get failed: http://www.google.com The full code is as follows: #!/usr/bin/perl use strict; use URI; use URI::http; use File::Basename; use DBI; use LWP::Simple; require LWP::UserAgent; my $ua = LWP::UserAgent->new; $ua->timeout(10); $ua->env_proxy; $ua->max_redirect(0); package Crawler; sub new { my $class =

My project is to crawl the certain web data and put them into my Google spreadsheet every morning 9:00. And it has to get the authorization to read & write something. That's why the code below is located at the top. # Google API CLIENT_ID = blah blah CLIENT_SECRET = blah blah OAUTH_SCOPE = blah blah REDIRECT_URI = blah blah # Authorization_code def get_authorization_code client = Google::APIClient.new client.authorization.client_id = CLIENT_ID client.authorization.client_secret = CLIENT_SECRET client.authorization.scope = OAUTH_SCOPE client.authorization.redirect_uri = REDIRECT_URI uri =

A friend has asked me this, and I couldn't answer. He asked: I am making this site where you can archive your site... It works like this, you enter your site like, something.com and then our site grabs the content on that website like images, and all that and uploads it to our site. Then people can view an exact copy of the site at oursite.com/something.com even if the server that is holding up something.com is down. How could he do this? (php?) and what would be some requirements? It sounds like you need to create a webcrawler. Web crawlers can be written in any language, although I would