war

I have a maven web app project, where I use JodaTime. JodaTime is not directly referenced in my maven project, but is a part of a transitive dependency. In other words, my web app war, has another project of mine as a direct dependency, and that jar contains JodaTime. I am getting an error after executing these two lines. It compiles fine though. DateTime firstDate = new DateTime(); firstDate = firstDate.withYear(2016); And here is my error: java.lang.NoSuchMethodError: org.joda.time.DateTime.withYear(I)Lorg/joda/time/DateTime; I know that these kinds of errors can happen if I compile and run

Lets assume my classes are loaded from a compressed .war file or loaded elsewhere, how can I discover all the resources in a given package? Enumerating files will not really work, since this is a war file. Most likely this will involve using the current classloader? Is there a library out there that does something like that? Googling revealed only some hacks with listing files. SCdF No, you can't list resources in a package because the JVM simply doesn't know what resources are in what package. See this question . jcfolsom Yes. You can use ClassLoader.getResources("") ; Or you could use ferret

Currently if i deploy a war file on tomcat named say myapp.war , I can access its url by http://localhost/myapp/MyServlet . However what I want is to deploy a war with a version number in the war file name and still have the same url. For eg, I want to deploy myapp-1.1.0.war and still have the url be http://localhost/myapp/MyServlet Of course I need to keep updating the war and the version number will keep changing, so I cant hardcode the war filename anywhere. Is there any setting in web.xml I can use to keep the same url for the app regardless of the war filename? The solution is to stop

Dubbo 服务消费者 Web 应用 war 包的部署 IP: xx.xx.xx.xx 部署容器： apache-tomcat-7.0.57 端口： 8080 应用： jeesml-web.war 1、 下载(或上传)最新版的 Tomcat7: $ wget http://mirrors.hust.edu.cn/apache/tomcat/tomcat-7/v7.0.57/bin/apache-tomcat-7.0.57 .tar.gz 2、 规范安装目录： /home/jeesml/jeesml/web/xxx-tomcat 如： /home/jeesml/jeesml/web/jeesml-tomcat 3、 解压安装 $ mkdir –p /home/jeesml/jeesml/web $ tar -zxvf apache-tomcat-7.0.57.tar.gz $ mv apache-tomcat-7.0.57 /home/jeesml/jeesml/web/jeesml-tomcat 4、 移除/home/jeesml/jeesml/web/jeesml-tomcat/webapps 目录下的所有文件： $ rm -rf /home/jeesml/jeesml/web/jeesml-tomcat/webapps/* 5、 上传 Dubbo 服务消费者 Web 应用

What's the difference in deploying application as EAR (with 1 EJB and 1 WAR module) vs separate modules? I want to use GlassFish 3 web profile but it does not support EAR archive. Can I simply use EJB and WAR as separate modules? Any other options? There seems to be some confusion between 3 variants of deployment: An EAR that includes an EJB and WEB module Deploying a separate EJB module and a separate WEB module Deploying a WEB module that includes EJB classes or an EJB jar. In the first situation, you have logically one application, but one that is divided in two tiers. The WEB module is

I'm becoming a bit crazy because I can't find a guide to setup an angular 4 app inside a java war project that will be built with maven. This is because I want to run it into a wildfly server. Any help? Thanks I had similar requirement to have one source project which has java web-services project as well as angular project(an angular-cli based project) and maven build should create a war with all angular files in it. I used maven-frontend-plugin with few configuration changes for base path. The goal was to create a war file with all the java code in it plus all the aot compiled angular code