views

问题 I am trying to get a final layout like... Left Column (collectionView) PanelLayout(LayoutView) BannerView (ItemView) ContentView (LayoutView) Section1 (CompositeView) gridRow (ItemView) PanelLayout(LayoutView) BannerView (ItemView) ContentView (LayoutView) Section1 (CompositeView) gridRow (ItemView) but my Left Column (collectionView) does not want to show the panelLayout(LayoutView). Is it possible to have a childView: that is a LayoutView (like the example below) and not a ItemView (http:/

问题 I need to create a view that lists out taxonomy terms and then list the top 3 recent(sort by node:date updated) nodes with that tag example out put: Article Article 1 Article 2 Article 3 Podcast Podcast 1 Podcast 2 Podcast 3 . . . I created a view of type "Term" and I can get the view to output all of the terms. However, I don't see how to link in the nodes tagged with the taxonomy term. I looked around in the view of type node, but I couldn't get anywhere close to what I needed to output.

问题 I'm using the class-based views in Flask for creating a CRUD REST API and registering the routes using add_url_rule like so... class GenericAPI(MethodView): def get(self, item_group, item_id): ... def post(self, item_group, item_id): ... ... api_view = GenericAPI.as_view('apps_api') app.add_url_rule('/api/<item_group>', defaults={'item_id': None}, view_func=api_view, methods=['GET',]) app.add_url_rule('/api/<item_group>/<item_id>', view_func=api_view, methods=['GET',]) app.add_url_rule('/api/

问题 I have a scenario in which I have created an updatable view composed of several tables that uses INSTEAD OF triggers. I have verified that I can manually insert into this view using SSMS without an issue. However, as my application is using EF Code-First to represent the view, when attempting to insert a record I end up with a problem because of the EF's use of SCOPE_IDENTITY() in the subsequent SELECT after the insert statement. I have tried including a statement at the end of my trigger to

问题 I generated a Rails application, and am playing around with the internals. Previously my application.html.erb was rendering properly, but now it seems like Rails is totally ignoring it because it won't even generate an error. There have been a bunch of questions on Stack Overflow regarding this problem. I've looked at what I think is all of them, but none have helped. My routes: Rails.application.routes.draw do # static_pages from rails tutorial ch. 3 get 'static_pages/home' get 'static_pages

问题 In my onCreate() method, I'm instantiating an ImageButton View: public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.layout_post); final ImageButton ib = (ImageButton) findViewById(R.id.post_image); ... In onResume, I want to be able to change the properties of the ImageButton with something like: @Override protected void onResume() { super.onResume(); ib.setImageURI(selectedImageUri); } //END onResume But onResume doesn't have access

问题 tl;dr - I want to set a put-attribute in my tiles definitions based on the individual model passed to a view in tiles I'm trying to create a page to display a user using spring and tiles. Right now my page gets the model fine, but I want the title of the page to include the username (which it would have to get from the model). I've included some excerpts from my code below: tiles.xml: <definition name="baseLayout" template="/WEB-INF/jsp/layout/layout.jsp"> <put-attribute name="title" value=

问题 In each of the activities in my application, all the views (grids/lists/buttons... lots of them) are declared as static members of the activity. Is this good practice or is there a better way. Been trying to figure this for a month now and finally decided to ask. Any help appreciated! 回答1: http://developer.android.com/training/articles/perf-tips.html. Check the documentation to understand when to use static variables. I agree with Boardy's comment. Why do you need your ui elements to be

问题 This question already has answers here : How to horizontally align some programmatically added views? (2 answers) Closed 6 years ago . As per my requirement i need to create a view like following view but my problem is, i'm able to add a new view to the existing view but as i mentioned in this i'm unable to move forward from this flaw ,can anybody help me in solving this. Thanks. 回答1: Got Answer in the following link. Answer 来源： https://stackoverflow.com/questions/10809975/how-to-create-view

问题 I have a view called edit_order, and I have another view called client_items. def edit_order(request, order_no) change_item = order.contact.client def client_items(request, client_id = 0): client = None items = None try: client = models.Client.objects.get(pk = client_id) items = client.storageitem_set.all() except: return HttpResponse(reverse(return_clients)) return render_to_response('items.html', {'items':items, 'client':client}, context_instance = RequestContext(request)) And in my edit