video-streaming

问题 Here is my link format to HTTP stream(user, password and address was changed to dummy): http://username:password@192.168.0.104:8093/axis-cgi/mjpg/video.cgi This stream works perfectly in VLC . However, I can't open it using OpenCV library. Here is my code: #include <iostream> #include "opencv2/opencv.hpp" using namespace std; using namespace cv; int main() { VideoCapture cap; const string videoStreamAddress = "http://username:password@192.168.0.104:8093/axis-cgi/mjpg/video.cgi"; cap.open

问题 So! My question is pretty straight forward, I have a website (Build in ASP.NET 2.0) which uses an old video player to play the videos (FLplayer progressive) the problem is all the videos on the site got converted to .mp4 (For better quality) but this old player won't play them... Which would be a nice player for the site that works on ie6 that would play the files? 回答1: but this old player won't play them The supported video file type(s) are usually not down to the Flash video player product

问题 I'm trying to determine the real type of a file programmatically. It seems I have to use for example FFMPeg for that. I want to determine if an uploaded file is in fact a MP4 or FLV (for flash videos) [or WebM (for HTML5)]. I know the -i operator in FFMPeg but I don't know what to check for. For example: Input #0, flv, from 'c:\www\data.aspbooru\image\0\40c24ba424d1334ef81c88c416ce794e.flv': Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'c:\www\data.aspbooru\image\0\8c1a747b5188349d92cca17a502d2d57

问题 I`m making a WinRT application which includes video streaming. Now I ended at VLC as streaming server and MJPEGDecoder lib (http://mjpeg.codeplex.com/) on client to decode video. But after creating HTTP stream and connecting to it from client, MJPEGDecoder says that header is invalid (it expects multipart stream). VLC-to-VLC works normal. Question 1 : how can it be fixed? Question 2 : what alternatives to create video streaming for WinRT? 回答1: Just to elaborate on your question/answer a bit

问题 I am working to stream a video screencast on our cakephp site using mediaViews and html5. I am using videojs for the player and am running into a few problems: Will not stream in safari/ipad/iphone (I have it converted into an mp4) Does not allow the viewer to skip to the middle of a video in any browser. They must watch the video straight through start to finish, which is not ideal. Is not falling back to the flash object for browsers that don't support html5 It currently streams correctly

问题 I'm using Jmeter to load test a video stream, I can pass the login information but I need to have Jmeter "hold" at a page that serves up a video stream. How can I do this? I have cookie manager already set. 回答1: If video stream doesn't live on your server you don't need to test it at all. For instance, if your site has YouTube frame you need to exclude YouTube domain from embedded resources. If video stream lives at your server - you can use TCP Sampler to request stream If your page contains

问题 I want to show some video files in my local software with some protection in case a user wants to copy them. I searched encryption methods and some DRM solutions, but I don't want internet connection, if that is not the only choice. I am developing my application with C#. Video files will be on CD. Basicly what I am planning to do is, keep video files encrypted on CD, and have decryption on RAM so not every player can play encrypted file, only my player can and they won't be copied (I hope).

问题 I want to capture a thumbnail of Youtube video on certain timeline. (e.g. 3.2sec) I used ytdl and fluent-ffmpeg with node.js to implement it. It was possible to capture a thumbnail when the downloading has finished. var fs = require('fs'); var ytdl = require('ytdl'); var ffmpeg = require('fluent-ffmpeg'); var videostream = fs.createWriteStream('video.flv'); var myytdl = ytdl('http://www.youtube.com/watch?v=A02s8omM_hI'); myytdl.pipe(videostream); videostream.on('close',function() { console

问题 I want to play YouTube video when we redirect from internet area to non internet area. Like I am having internet access at some point and I played Youtube video, and after some times my internet connection is loosed, but now I want to play all those video which I played previously. 回答1: I am not going to write any code for this but only tell you the route you probably need to take. As with any online media, If you don't have access to the internet, well you can't really get the data. What you

问题 I want to play a streaming video in android from a website. For example, I want to play the streaming video from this url: http://florotv.com/canal2.html Using URL Helper, I have been able to capture the rtmp URL that it's rtmp://198.144.153.139:443/kuyo<playpath>ver44?id=acf6f5271f8ce567ed6c8737ce85a044&pid=32342e3136362e37332e323139 <swfUrl>http://yukons.net/yplay2.swf <pageUrl>http://yukons.net/embed/37363635373233343334/eeff74c57593ca38defc902fa6d88005/600/400 Now that I have this URL, I