version

Nested filtering with Angular.js version 1.2.18

*爱你&永不变心* 提交于 2019-12-01 11:12:05
I'm experimenting with AngularJS for the first time. I do repeat a template based on JSON data, which here is a sample: $scope.users = [ {name: 'first user', status: {name: 'employee'}}, {name: 'second user', status: {name: 'freelancer'}}, {name: 'third user', status: {name: 'employee'}}, ]; This works fine: <p ng-repeat="user in users">{{user.name}}</p> Now I want to prefilter the users displayed. Works fine, too: <p ng-repeat="user in users | filter:{status: 'employee'}">{{user.name}}</p> But when I want to filter on the basis of JSON data within a nested object ( status.name instead of

addChildViewController alternative for iOS 4.3

我与影子孤独终老i 提交于 2019-12-01 10:26:15
I would like to use the same functionality of addChildViewController, but for the version 4.3 (addChildViewController is only available in version 5). Thanks in advance. Although it's not recommended, you can create an instance of a UIViewController access it's view property and set it as a subview of the main view your main UIViewController is managing. It works, and I never experienced a problem with this. That said, the recommended way is to have a NSObject subclass to act as your sub-controller, and not use a UIViewController as it has special behavior. Luis Andrés García Something similar

Nested filtering with Angular.js version 1.2.18

↘锁芯ラ 提交于 2019-12-01 08:46:50
问题 I'm experimenting with AngularJS for the first time. I do repeat a template based on JSON data, which here is a sample: $scope.users = [ {name: 'first user', status: {name: 'employee'}}, {name: 'second user', status: {name: 'freelancer'}}, {name: 'third user', status: {name: 'employee'}}, ]; This works fine: <p ng-repeat="user in users">{{user.name}}</p> Now I want to prefilter the users displayed. Works fine, too: <p ng-repeat="user in users | filter:{status: 'employee'}">{{user.name}}</p>

Reading first line of a text file in javascript

好久不见. 提交于 2019-12-01 08:20:28
Let's say I have a text file on my web server under /today/changelog-en.txt which stores information about updates to my website. Each section starts with a version number, then a list of the changes. Because of this, the first line of the file always contains the latest version number, which I'd like to read out using plain JavaScript (no jQuery) . Is this possible, and if yes, how? Some Guy This should be simple enough using XHR. Something like this would work fine for you: var XHR = new XMLHttpRequest(); XHR.open("GET", "/today/changelog-en.txt", true); XHR.send(); XHR.onload = function (){

addChildViewController alternative for iOS 4.3

两盒软妹~` 提交于 2019-12-01 06:03:35
问题 I would like to use the same functionality of addChildViewController, but for the version 4.3 (addChildViewController is only available in version 5). Thanks in advance. 回答1: Although it's not recommended, you can create an instance of a UIViewController access it's view property and set it as a subview of the main view your main UIViewController is managing. It works, and I never experienced a problem with this. That said, the recommended way is to have a NSObject subclass to act as your sub

Testing uploaded app, other than default version

好久不见. 提交于 2019-12-01 06:01:50
Can you test an uploaded version of an app, other than the "default" version? I'm told it can be: WoLpH Google App Engine version numbers? But I can't find it in the dashboard or the doco. Vishal Biyani If the version of app is 2 and your app URL is appname.appspot.com then URL 2.appname.appspot.com will give you access to version 2 of your app. As Vishal already said correctly (+1), you can prepend the version identifier to your url, so if your version is "version", the URL will be version.appname.appspot.com (app versions are strings, not numbers, although the string "2", is perfectly ok too

How to get JavaCard version on card

核能气质少年 提交于 2019-12-01 05:49:03
问题 How to get java card version from card? Is there any way how to get version of JC from the card. Or should I try to install applets with specific for each JC version options. 回答1: The only full-proof way to determine JavaCard API versions supported by a "white" smart card is to build a separate CAP file for each JavaCard version. I suggest you make each CAP contain just a single simple class extending javacard.framework.Applet . You may want to be able to actually install your simple applet

tkinter woes when porting 2.x code to 3.x, 'tkinter' module attribute doesn't exist

泪湿孤枕 提交于 2019-12-01 04:08:36
问题 UPDATED: SEE BELOW I've been porting the code for this assignment: http://www.stanford.edu/class/cs221/progAssignments/PA1/search.html (the entire source code is available as zip from there) from Python 2.x to 3.x. Note, porting is not the assignment, that's just me trying to keep the code up to date and avoiding installing another version of Python... After the usual 2.x -> 3.x syntax fixes (printing, exception raising, etc), and realizing that the module Tkinter is now known as tkinter in 3

Run test in phpunit with specific php version

戏子无情 提交于 2019-12-01 04:08:06
I have installed multiple PHP versions on my Mac and want to run unit-tests against a specific PHP version (or against multipls versions) Here's the php versions I have: $ php --version Output: PHP 5.4.23 ... $ /Applications/MAMP/bin/php/php5.2.17/bin/php --version Output: PHP 5.2.17 ... My test case looks like this: function test_php_version() { $actual = phpversion(); $expected = '5.2.17'; $this->assertEquals( $expected, $actual, 'Wrong PHP version!' ); } When I run the test I get this response: $ phpunit Wrong PHP version! Failed asserting that two strings are equal. --- Expected +++ Actual

Qt - Don't append major version number to the end of executable/library name

本小妞迷上赌 提交于 2019-12-01 04:06:34
问题 How can I stop Qt from renaming my DLL to MyDLLName{MAJOR_VERSION_NUM}.dll ? This only happens when I set the VERSION in my project file, but I also want to set the version. For example, if I have: VERSION = 1.2.3.4 And my library is named MyDll , it will create my DLL in the debug folder as MyDLL1.dll . If I take the version number away, it keeps the name as I want it ( MyDLL.dll ). Thanks. 回答1: Use this: CONFIG += skip_target_version_ext 回答2: See this answer (on SO) for why it is there: Why