variables

问题 So this is my code. Now how do I use $pubname in another file. mysqli_select_db($connect,"membership"); $retname = "select username from users where email='$globalname' limit 1"; $rn = mysqli_query($connect,$retname) or die(mysqli_error($connect)); $name = mysqli_fetch_array($rn); //connecting for mathcing username with fullname and displaying it $pubname = mysqli_real_escape_string($name['username']); include('profile.php'); echo $pubname; and also is this code secure? I did that...does not

问题 So this is my code. Now how do I use $pubname in another file. mysqli_select_db($connect,"membership"); $retname = "select username from users where email='$globalname' limit 1"; $rn = mysqli_query($connect,$retname) or die(mysqli_error($connect)); $name = mysqli_fetch_array($rn); //connecting for mathcing username with fullname and displaying it $pubname = mysqli_real_escape_string($name['username']); include('profile.php'); echo $pubname; and also is this code secure? I did that...does not

问题 So this is my code. Now how do I use $pubname in another file. mysqli_select_db($connect,"membership"); $retname = "select username from users where email='$globalname' limit 1"; $rn = mysqli_query($connect,$retname) or die(mysqli_error($connect)); $name = mysqli_fetch_array($rn); //connecting for mathcing username with fullname and displaying it $pubname = mysqli_real_escape_string($name['username']); include('profile.php'); echo $pubname; and also is this code secure? I did that...does not

问题 Is it possible to detect when the value of a variable has changed using the lua debug library. Something like A callback function which would give details like the function in which the value was changed, previous value, etc. Is such a thing possible? I read about hooks, but I'm not sure hooks can be set to variables. 回答1: If you don't mind using a debugger, then some debuggers allow you to set Watch expressions, which will be triggered when the condition in the expression is true. I'll show

问题 I am trying to create a script that sets a local variable, references it from a function, and can return the manipulated value back to the main scope (or whatever it's called; I'm new to Python) I have simplified my code to show the utmost basics of what I am trying to accomplish, which is to import a local from the module into a function block, I think. I have gotten this to work by using globals , but that isn't the best solution . . . chambersinreactor = 0; cardsdiscarded = 0; def find

问题 I'm running a PHP script and continue to receive errors like: Notice: Undefined variable: my_variable_name in C:\wamp\www\mypath\index.php on line 10 Notice: Undefined index: my_index C:\wamp\www\mypath\index.php on line 11 Line 10 and 11 looks like this: echo "My variable value is: " . $my_variable_name; echo "My index value is: " . $my_array["my_index"]; What is the meaning of these error messages? Why do they appear all of a sudden? I used to use this script for years and I've never had

问题 I have a container that should be created with the IP user. This is what i have inside the Dockerfile: ENV REMOTE_HOST=xxxxxxxxxx RUN { \ echo '[xdebug]'; \ echo 'zend_extension=/usr/local/lib/php/extensions/no-debug-non-zts-20131226/xdebug.so'; \ echo 'xdebug.remote_enable=1'; \ echo 'xdebug.remote_port=9000'; \ echo 'xdebug.remote_autostart=1'; \ echo 'xdebug.remote_handler=dbgp'; \ echo 'xdebug.idekey=dockerdebug'; \ echo 'xdebug.profiler_output_dir="/var/www/html"'; \ echo 'xdebug.remote

问题 Is it possible to have two different variables in with the same name in jQuery? I have my jQuery linking to outside scripts. Is it possible to have two variables using the same letter name? ie: Contained in compressed.js: var m = $$('li', s), and Contained in http://www.google.com/jsapi: var m = "push", Are these two affecting each other? 回答1: The simple answer is no, they will not effect each other. how it works is that each variable name is unique, so m , m1 , m2 , m3 , m4 does not have any

问题 This question already has answers here : #define IDENTIFIER without a token (4 answers) Using #define in C with no value (1 answer) Closed 2 years ago . can you guys tell me, what does this mean in C? #define Privileged_Data Privileged_Data static int dVariable Is it specific meaningful for Compiler to address variable? 回答1: This is just a macro Privileged_Data doing nothing. The compiler will not even see it after the preprocessor pass. It's probably a readability or company standards

问题 This question already has answers here : #define IDENTIFIER without a token (4 answers) Using #define in C with no value (1 answer) Closed 2 years ago . can you guys tell me, what does this mean in C? #define Privileged_Data Privileged_Data static int dVariable Is it specific meaningful for Compiler to address variable? 回答1: This is just a macro Privileged_Data doing nothing. The compiler will not even see it after the preprocessor pass. It's probably a readability or company standards