variables

printf a variable in C [closed]

孤街浪徒 提交于 2021-01-18 10:02:08
问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 7 years ago . #include <stdio.h> #include <stdlib.h> int main() { int x = 1; printf("please make a selection with your keyboard\n"); sleep(1); printf("1.\n"); char

printf a variable in C [closed]

倖福魔咒の 提交于 2021-01-18 09:59:42
问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 7 years ago . #include <stdio.h> #include <stdlib.h> int main() { int x = 1; printf("please make a selection with your keyboard\n"); sleep(1); printf("1.\n"); char

printf a variable in C [closed]

人走茶凉 提交于 2021-01-18 09:58:29
问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 7 years ago . #include <stdio.h> #include <stdlib.h> int main() { int x = 1; printf("please make a selection with your keyboard\n"); sleep(1); printf("1.\n"); char

Code Igniter POST Variable

杀马特。学长 韩版系。学妹 提交于 2021-01-07 22:01:32
问题 I am brand new to Code Igniter but I can't seem to find a way to do this in the documentation, In normal PHP you can retrieve the contents of the entire POST variable like this $_POST = $postedVars But I can't seem to find something that does this in the same manner, I've tried $arr = $this->input->post; and $arr = $this->input->post(); With no luck! Is this possible in CI? Thanks in advance! 回答1: First, you need a form or something that sets the variables Then, you retrieve them. $this-

Code Igniter POST Variable

試著忘記壹切 提交于 2021-01-07 21:59:59
问题 I am brand new to Code Igniter but I can't seem to find a way to do this in the documentation, In normal PHP you can retrieve the contents of the entire POST variable like this $_POST = $postedVars But I can't seem to find something that does this in the same manner, I've tried $arr = $this->input->post; and $arr = $this->input->post(); With no luck! Is this possible in CI? Thanks in advance! 回答1: First, you need a form or something that sets the variables Then, you retrieve them. $this-

Code Igniter POST Variable

夙愿已清 提交于 2021-01-07 21:58:46
问题 I am brand new to Code Igniter but I can't seem to find a way to do this in the documentation, In normal PHP you can retrieve the contents of the entire POST variable like this $_POST = $postedVars But I can't seem to find something that does this in the same manner, I've tried $arr = $this->input->post; and $arr = $this->input->post(); With no luck! Is this possible in CI? Thanks in advance! 回答1: First, you need a form or something that sets the variables Then, you retrieve them. $this-

Finding the largest number in an array using predefined java methods

痴心易碎 提交于 2021-01-04 05:49:18
问题 Here is the code snippet that I am working on and my goal is to find the largest value from the list using predefined java methods. import java.util.*; public class Test { public static void main(String[] args) { Scanner s = new Scanner(System.in); System.out.println("Enter a list of integers: "); int array[] = new int[10]; for (int i = 0; i < array.length; i++) { array[i] = s.nextInt(); } for (int j = 0; j < array.length; j++) { if (j < array.length) { int maximum = Math.max(array[j], array

How PHP variable variables work?

喜你入骨 提交于 2021-01-03 06:26:07
问题 I know how PHP variable variables works, but have trouble understanding why this script outputs "I am r." instead of "I am B." <?php class fooo { var $bar = 'I am bar.'; var $arr = array('I am A.', 'I am B.', 'I am C.'); var $r = 'I am r.'; } $fooo = new fooo(); $arr = 'arr'; echo $fooo->$arr[1] . "\n"; //above line output //I am r. ?> 回答1: You are defining $arr = 'arr'; and then getting the second character from the string 'arr', not the array inside class Foo, that is why you are getting 'r

Why should I “Transform myVariable to final one element array”?

◇◆丶佛笑我妖孽 提交于 2020-12-30 07:44:13
问题 I'm trying to access the h variable in the inner class but an error keeps showing up "Cannot assign a value to final variable h ". I tried quick-fix and it instructed me to "Transform h to final one element array".What does that mean? int Update () { final int h; SharedPreferences preferences = PreferenceManager.getDefaultSharedPreferences(this); preferences.registerOnSharedPreferenceChangeListener(new SharedPreferences.OnSharedPreferenceChangeListener() { @Override public void

Get variable type in bash

筅森魡賤 提交于 2020-12-26 05:18:31
问题 In Python I can get variable type by: >>> i = 123 >>> type(i) <type 'int'> I saw on this page that there are no variable types in bash. The explanation given is: Untyped variables are both a blessing and a curse. They permit more flexibility in scripting and make it easier to grind out lines of code (and give you enough rope to hang yourself!). However, they likewise permit subtle errors to creep in and encourage sloppy programming habits. But I'm not sure what it means and what are the real