variable-assignment

Consider the following example: class Quirky { public static void main(String[] args) { int x = 1; int y = 3; System.out.println(x == (x = y)); // false x = 1; // reset System.out.println((x = y) == x); // true } } I'm not sure if there is an item in the Java Language Specification that dictates loading the previous value of a variable for comparison with the right side ( x = y ) which, by the order implied by brackets, should be calculated first. Why does the first expression evaluate to false , but the second evaluate to true ? I would have expected (x = y) to be evaluated first, and then it

I'm trying to assign a print statement to a variable in a function: def namer(fn, ln='Smith'): # return value, default value r = print "Your name is ", fn, ln return r But when I run the module, it says: Traceback (most recent call last): File "<pyshell#1>", line 1, in <module> import m8 File "m8.py", line 3 r = print "Your name is ", fn, ln ^ SyntaxError: invalid syntax Any explanation? As you noted, in Python2.x, print is a statement. A statement is not an object, you cannot assign it to anything, you can just execute it. Why would you want to return the print statement? Why not the string

This question already has an answer here: Is JavaScript a pass-by-reference or pass-by-value language? 29 answers Why is it that when I assign a variable to an object and make a change to that variable it also changed the objects? For example: c = 26; a = b = c; a += 1; a // 27 b // 26 c // 26 but z = {}; x = y = z; x.ab = 5; x // Object {ab: 5} y // Object {ab: 5} z // Object {ab: 5} Why (in the example above) does y.ab and z.ab exist? I only modified x not y or z . Howcome in the first example (with the integers), when I changed the value of a , b and c weren't affected? When you assign an

I have the following code which reads an file name from the command line and opens this file: #include <stdio.h> #include <stdlib.h> int main(int argc, char **argv){ FILE *datei; char filename[255]; //filename = argv[1]; //datei=fopen(filename, "r"); datei=fopen(argv[1], "r"); if(datei != NULL) printf("File opened"); else{ printf("Fehler beim öffnen von %s\n", filename); return EXIT_FAILURE; } return EXIT_SUCCESS; } This example works, but I want to write the string from the command line to the char array and pass that char array to to fopen(), but i get the compiler error Error: assignment to

I am editing a quick sort code so that the values of low, high, and middle point to an array element instead of integers. This is my code: #include <stdio.h> #define N 10 void quicksort(int a[], int *low, int *high); int split(int a[], int *low, int *high); int main(void) { int a[N], i; printf("Enter %d numbers to be sorted: ", N); for (i=0; i<N; i++) scanf("%d", &a[i]); quicksort(a, &a[0], &a[N-1]); printf("In sorted order: "); for (i=0; i<N; i++) printf("%d ", a[i]); printf("\n"); return 0; } void quicksort(int a[], int *low, int *high) { int *middle; if (low >= high) return; middle = split

#include<stdio.h> #include<conio.h> int main(){ char i; int c; scanf("%i",&c); scanf("%c",&i);// catch the new line or character introduced before x number printf("%i",i);// value of that character getch(); return(0); } The program will behave in the same way with the next variable declarations instead of the above variable declaration: this: int c; int *x; int i; or this: int *x; int c; int i; And only this way: c variable and a x pointer before the i variable. I know that those last declarations haven't sense, the int i instead of char i , and an added pointer that isn't even needed. But

This question already has an answer here: adding values to diagonals of matrix using element-wise addition in matlab 3 answers I have an (2n-1)-by-1 vector with certain values and I want to obtain an n-n matrix with the diagonals filled using the same value. Eg. if I have a = [1; 2; 3; 4; 5]; I want to obtain A = [[3 4 5];[2 3 4];[1 2 3]] = 3 4 5 2 3 4 1 2 3 My matrix dimensions are a lot bigger so I'd want this as efficient as possible. I already found following solutions: n = 3; A = toeplitz(a); A = A(1:n,end-n+1:end) and A = a(n)*eye(n); for j=1:n-1 A(1+j:n+1:end-j*n) = a(n-j); A(j*n+1:n+1