variable-assignment

I was watching this video and at 7:10 he's adding a db dependency and is using a closure to assign the value. My question is why not just use direct assignment instead, I mean isn't doing this: $container['db'] = $capsule; equivalent to doing this: $container['db'] = function ($container) use ($capsule) { return $capsule; } If not, what is the difference and which way is better? TLDR it's because defining dependencies as closures makes it possible for dependency injection container to build them on demand, hence you don't need to worry about their order of definition and managing their

I was having a conversation about the prefix increment operator, and we seem to have run into a disagreement. When running this code: var x = 0; x = ++x; is the second line equivalent to: x = (x = x + 1) OR x = (x + 1) It is hard to tell the difference because the results are identical (both result in x having a value of 1) I believe that the value is not saved to the original variable when the left hand side of the assignment is the variable itself. My counterpart disagrees and thinks the value is saved to the original variable whenever the ++ operator is used. Which one of us is right? It is

When indexing more than one level for an array, it works fine. But when I used it to assign values, it did not. Does anyone know why A does not change below? In [4]: A = rand(6) Out [4]: 6-element Array{Float64,1}: 0.111552 0.155126 0.78485 0.147477 0.362078 0.959022 In [5]: A[3:5][[true,false,true]] Out [5]: 2-element Array{Float64,1}: 0.78485 0.362078 In [6]: A[3:5][[true,false,true]] = [99, 999] Out [6]: 2-element Array{Int64,1}: 99 999 In [7]: A Out [7]: 6-element Array{Float64,1}: 0.111552 0.155126 0.78485 0.147477 0.362078 0.959022 This is because indexing arrays by ranges and vectors

I'd like to use ES6 destructuring to assign properties of an object, but can't figure out the syntax. <= ES5: var dst = {}; // already in existence, with its own props, methods, etc. var src = { a: 'foo', b: 'bar', c: 'baz' }; dst.a = src.a; dst.b = src.b; >= ES6 (my own made-up, not-working syntax): let dst = {}; let src = { a: 'foo', b: 'bar', c: 'baz' }; dst[{a, b}] = src; Is it possible to use destructuring assignment onto an object? What's the correct syntax? EDIT: In my use case, dst is an object that existed well before needing to merge a subset of src 's properties; it is not a new

Below is my script, which basically creates a zero matrix of 12x8 filled with 0. Then I want to fill it in, one by one. So lets say column 2 row 0 needs to be 5. How do I do that? The example below shows how I did it and the wrong (for my needs) output: list_MatrixRow = [] list_Matrix = [] #Not to be confused by what the book calls, optimal alignment score matrix int_NumbOfColumns = 12 int_NumbOfRows = 8 for i in range (0, int_NumbOfColumns): # Puts Zeros across the first Row list_AlignMatrixRow.append(0) for i in range (0, int_NumbOfRows): list_AlignMatrix.append(list_AlignMatrixRow) #add the

I am working on an assignment and I'm stuck on this error: cannot assign a value to final variable count Here is my code so far... public class List { private final int Max = 25; private final int count; private Person list[]; public List() { count = 0; list = new Person[Max]; } public void addSomeone(Person p) { if (count < Max){ count++; // THIS IS WHERE THE ERROR OCCURS list[count-1] = p; } } public String toString() { String report = ""; for (int x=0; x < count; x++) report += list[x].toString() + "\n"; return report; } } I'm very new to java and am obviously not a computer whiz so please

I noticed the following when using '[<-' . I am successful at replacing elements but not at appending an element to the vector. Example: VarX <- integer() VarX[1] <- 11 `[<-`(VarX, 2, 22) VarX # [1] 11 # Expected the value of VarX to be: # [1] 11 22 # Also tried: `[<-`(VarX, i=2, value=22) VarX # [1] 11 However, if there is already a value at the index, the value does get replaced. VarX <- integer() VarX[1] <- 11 VarX[2] <- 99 VarX # [1] 11 99 `[<-`(VarX, 2, 22) VarX # [1] 11 22 Do I simply have the syntax wrong, or is this as intended? Any further insight into what is going on here would be

Looking at this example code similar to this question : public class A { public static void main(String args[]){ A a = new A(); System.out.println(a.equals((a = null))); } } This prints false. Why doesn't it fail with a NullPointerException? The assignment has to get processed before the equals method can run, but somehow that doesn't affect the reference that equals is called on until after the whole line is evaluated? I didn't see where in the Java language spec it describes this, did I miss it somewhere? ζ-- From JLS : At run time, method invocation requires five steps. First, a target