Erlang list comprehension
问题 I'm testing an expression with two inequalities for the condition of a list comprehension. Is there a way to have assignments here and not duplicate that expression? (The following code doesn't work, but I wish it would) diagnose(Expertise,PatientSymptoms)-> {[CertainDisease|| {CertainDisease,KnownSymptoms}<-Expertise, C=length(PatientSymptoms)-length(PatientSymptoms--KnownSymptoms), C>=2, C<=5 ]}. 回答1: A way of writing it directly without a fun would be to use a begin ... end block ending