user-input

Do you break up addresses into street / city / state / zip?

白昼怎懂夜的黑 提交于 2019-12-01 17:16:33
问题 My current app needs to store address information for a user. I'm currently debating whether to use the customary street address / city / state / zip textboxes and dropdowns or to go with Google's method of simply having everything on one line. Any thoughts on the pros/cons of storing address information in either of these manners? 回答1: You should split it up. It will make it far easier to do reporting down the road. What happens if you want to pull up all the residents of a state or zip code

How to provide your own delimiter for cin?

一个人想着一个人 提交于 2019-12-01 17:00:34
In c, I can use newline delimeter ([^\n]) with scanf. Using which I can store the line. Similarly for cin, I can use getline. If I have to store a paragraph, I can simulate the functionality using my own special char delimiter like [^#] or [^\t] with scanf function in c. char a[30]; scanf("%[^\#]",a); printf("%s",a); How to achieve the similar functionality with cin object in cpp. istream.getline lets you specify a deliminator to use instead of the default '\n' : cin.getline (char* s, streamsize n, char delim ); or the safer and easier way is to use std::getline . With this method you don't

How to provide your own delimiter for cin?

こ雲淡風輕ζ 提交于 2019-12-01 16:52:19
问题 In c, I can use newline delimeter ([^\n]) with scanf. Using which I can store the line. Similarly for cin, I can use getline. If I have to store a paragraph, I can simulate the functionality using my own special char delimiter like [^#] or [^\t] with scanf function in c. char a[30]; scanf("%[^\#]",a); printf("%s",a); How to achieve the similar functionality with cin object in cpp. 回答1: istream.getline lets you specify a deliminator to use instead of the default '\n' : cin.getline (char* s,

How do I hide user input with cin in C++? [duplicate]

≡放荡痞女 提交于 2019-12-01 14:58:37
Possible Duplicate: Read a password from std::cin I'm trying to make a simple password program so I can get familiar with C++, but I'm having a bit of a problem. In this code, I ask the user for a password they choose, and then they enter it. What I want to code to do is hide the input ( not replace it with *s), but still show the cursor, and the text above, before, and after the password is entered, like this: Please enter password: [don't show input] Please re-enter password: [don't show input] How can I do this? I'm using Linux, so I won't be able to use any windows libraries (windows.h,

How to get user input repeatly until i want to quit? [closed]

感情迁移 提交于 2019-12-01 14:49:44
I want to get user input for multiple times and store the input data together in a string until input "quit" to quit from input. I think a for loop can work but I don't know how to do it. while True: user_input = raw_input("Enter something:") if user_input == "quit": break Try this: input_string = '' while 1: input = raw_input('Add to string: ') if input == 'quit': break input_string += input while True: input = raw_input('Prompt') print input if (input == 'quit'): break; 来源: https://stackoverflow.com/questions/12608654/how-to-get-user-input-repeatly-until-i-want-to-quit

User input without pausing code (c++ console application)

◇◆丶佛笑我妖孽 提交于 2019-12-01 14:17:12
How can I enter an input without causing the code to stop executing? I have been searching for an answer during the last 20 minutes without result. cin >> string; pauses the code AFAIK. Would I need to use mulithreading, or is there a better way? (I don't even know if multithreading would work.) I've recently started learning c++, I am a beginner to say the least, so please explain thoroughly and include any library I might need, thank you. There are two algorithms for getting input without blocking (pausing). The first is polling, the second is by event (interrupt). Polling For Input Polling

How do I hide user input with cin in C++? [duplicate]

笑着哭i 提交于 2019-12-01 14:00:09
问题 This question already has answers here : Closed 6 years ago . Possible Duplicate: Read a password from std::cin I'm trying to make a simple password program so I can get familiar with C++, but I'm having a bit of a problem. In this code, I ask the user for a password they choose, and then they enter it. What I want to code to do is hide the input ( not replace it with *s), but still show the cursor, and the text above, before, and after the password is entered, like this: Please enter

How to get user input repeatly until i want to quit? [closed]

耗尽温柔 提交于 2019-12-01 13:34:10
问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 7 years ago . I want to get user input for multiple times and store the input data together in a string until input "quit" to quit from input. I think a for loop can work but I don't know how to do it. 回答1: while True: user

<h:inputText> doesn't seem to work within <ui:repeat>, only the last entry is submitted

拈花ヽ惹草 提交于 2019-12-01 11:31:08
I have an <ui:repeat> with <ui:inputText> : <ui:composition xmlns="http://www.w3.org/1999/xhtml" xmlns:ui="http://java.sun.com/jsf/facelets" template="./templates/masterLayout.xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:p="http://primefaces.org/ui" xmlns:f="http://java.sun.com/jsf/core" xmlns:c="http://java.sun.com/jsp/jstl/core"> <ui:define name="content"> <ui:repeat value="#{genproducts.dbList()}" var="itemsBuying"> <div class="indproduct"> <p class="center">#{itemsBuying.name}</p> <div class="center"> <h:form style="margin-left: auto; margin-right: auto;"> <h:inputText value="#

Hide user input, and only allow certain characters

耗尽温柔 提交于 2019-12-01 10:51:21
Is there any way to hide user input when asked for in C? For example: char *str = malloc(sizeof(char *)); printf("Enter something: "); scanf("%s", str);getchar(); printf("\nYou entered: %s", str); // This program would show you what you were writing something as you wrote it. // Is there any way to stop that? Another thing, is how can you only allow certain characters? For example: char c; printf("Yes or No? (y/n): "); scanf("%c", &c);getchar(); printf("\nYou entered: %c", c); // No matter what the user inputs, it will show up, can you restrict that only // showing up if y or n are entered?