unique-id

问题 I want to get a unique device id in my application. But As per google document says Android 10 adds restrictions for non-resettable identifiers. I don't want random id. I want to get the unique id so I can identify the device from which my API gets hit. and by that, I can manage my session. is there is another unique id other than Secure.android_id which is unique for android? or is there any way to access the Secure.android_id in Android 10. 回答1: You will get the wifi mac address by using

问题 I want to get a unique device id in my application. But As per google document says Android 10 adds restrictions for non-resettable identifiers. I don't want random id. I want to get the unique id so I can identify the device from which my API gets hit. and by that, I can manage my session. is there is another unique id other than Secure.android_id which is unique for android? or is there any way to access the Secure.android_id in Android 10. 回答1: You will get the wifi mac address by using

问题 Does anyone have a simple suggestion for recording a build ID (generated at compile time) which is displayed in the title bar of the app at runtime? Building from within Eclipse, all I need is the ID, I can then pass it up to the title. 回答1: If you are using Ant, you can easily set up your "jar" or "package" target so that it generates a file including the current timestamp and include this in your jar output. If using Maven, there are a few ways to achieve something similar, such as dropping

问题 Does anyone have a simple suggestion for recording a build ID (generated at compile time) which is displayed in the title bar of the app at runtime? Building from within Eclipse, all I need is the ID, I can then pass it up to the title. 回答1: If you are using Ant, you can easily set up your "jar" or "package" target so that it generates a file including the current timestamp and include this in your jar output. If using Maven, there are a few ways to achieve something similar, such as dropping

问题 I just asked a question about this but I want to go at it a different way. When a user edits his/her profile and hits the save button, I want to be able to generate a random number using UUID. I want this ID to stay the same if the user goes back and edits their profile a second time (if they press 'save' again I want to retain the ID that was generated the first time they pressed 'save'). I have the following code working to save other data, but I'm not sure how to include a check that can

问题 I want to get the Device ID in Windows Phone 8.1 . The DeviceExtendedProperties or DeviceStatus are not available in WP8.1 (there is no Microsoft.Phone.Info namespace). I've just found the EasClientDeviceInformation class that I can't get the Id from it. There is an exception in the Id property: And other properties are't unique. There is another solution here but I don't know if it is safe or reliable to use: (?) https://stackoverflow.com/a/23537207/3682369 回答1: Yes, you can use the

问题 I have a bunch of C++ classes. I want each class to have something like: static int unique_id; All instances of a same class should have the same unique_id; different classes should have different unique_id's. The simplest way to do this appears to be threading a singleton through the classes. However, I don't know what's called when for static class members / things that happen before main. (1) if you have a solution that does not involve using singleton, that's fine too (2) if you have a

问题 This question already has answers here : unique object identifier in javascript (11 answers) Closed last year . Do JavaScript objects/variables have some sort of unique identifier? Like Ruby has object_id . I don't mean the DOM id attribute, but rather some sort of memory address of some kind. 回答1: No, objects don't have a built in identifier, though you can add one by modifying the object prototype. Here's an example of how you might do that: (function() { var id = 0; function generateId() {

问题 Check this, List<String> list = new ArrayList<String>(); for (int i = 0; i < 10000; i++) { String value = (""+UUID.randomUUID().getLeastSignificantBits()).substring(3, 20); assertFalse(list.contains(value)); assertTrue(value.length() < 18); list.add(value); } This method is passing like charm. And I am in the impression that it is slightly better to take least significant bits, rather than the most significant. Because in the most significant bits you have 6 bits fixed for some info, and with

问题 This question already has answers here : How to get the insert ID in JDBC? (12 answers) Closed 4 years ago . My current method is this: SELECT TOP 1 ID FROM DATAENTRY ORDER BY ID DESC This assumes the latest inserted item always has the highest unique ID (primary key, autoincrementing). Something smells wrong here. Alternatives? 回答1: If the JDBC driver supports it, you can also just use Statement#getGeneratedKeys() for that. String sql = "INSERT INTO tbl (col) VALUES (?)"; preparedStatement =