JavaScript bitwise undefined pitfalls?
What is the logic of bitwise operators on undefined??? var x; console.log(x); // undefined console.log(x^7); // 7 console.log(7^x); // 7 console.log(x|7); // 7 console.log(7|x); // 7 console.log(7&x); // 0 console.log(x&7); // 0 console.log(~x); // -1 console.log(x*2); // NaN console.log(x/2); // NaN console.log(x+2); // NaN console.log(x-2); // NaN I can see some sense in NaN. Because undefined -2 is really 'not a number'. But I do not follow any logic on bitwise operators and undefined. The internal function [ToInt32] is called on all operands for all bitwise operators. Note that ToInt32