uidatepicker

Trying to set only time in UIDatePicker in Swift 2.0

由 不羁的心 提交于 2019-11-27 08:04:07
问题 I am trying to set the UIDatePicker to come up with the time only. The DatePicker comes up through an action when the textfield is pressed. I have not used the DatePicker Viewer. Any help is appreciated. Thanks let starttimedatePicker = UIDatePicker() startTimeDiveTextField.inputView = starttimedatePicker starttimedatePicker.addTarget(self, action: "startTimeDiveChanged:", forControlEvents: .ValueChanged) func startTimeDiveChanged(sender: UIDatePicker) { let formatter = NSDateFormatter()

How to set Minimum time to appear as default in UIDatepicker everytime

由 …衆ロ難τιáo~ 提交于 2019-11-27 07:28:58
问题 In Datepicker i have set Min and Max time where uidatepicker can scroll for example i have set 3:00PM as minimum time and 8:00PM as maximum time , when i run the app i want the datepicker to display the Minimum time not the current time of the device . I have hard coded UIDatepicker in my project havent used in xib file . I have set Min time but when i switch from control.tag ==1 to 2 the minimum time changes and also when i open the app for first time the datepicker doesnt start from minimum

Disable enter key in JQuery ui datepicker

由 守給你的承諾、 提交于 2019-11-27 06:54:37
问题 There seems to be a bug with JQuery UI datepicker, when user manually enters a date, and hits enter, the datepicker closes but focus stays on the field and therefor calendar won't open again until the textbox loses focus and gets it again. How can I supress the enter key behavior? Or are there any other known solutions for this seemingly known bug? Thanks! EDIT After working on this a bit more, this is the solution I came up with: $('#someid').bind('keydown', function(event) { if (event.which

UIDatePicker bug? UIControlEventValueChanged after hitting minimum internal

由 落花浮王杯 提交于 2019-11-27 05:28:50
问题 I've run into a weird effect that sure looks like a bug in iOS7 -- but often in the past, when I have thought I found a bug in Apple's APIs, it has turned out to be my own misunderstanding. I have a UIDatePicker with datePickerMode = UIDatePickerModeCountDownTimer and minuteInterval = 5. I initialize the duration to 1 hour, and present it to the user, where it appears as a two-column picker with hours and minutes. (So far so good.) The user is thinking "20 minutes," and so scrolls the Hour

Show Time in 12 and 24 hour format in UIDatepicker on the basis of app settings not on device Settings

由 我们两清 提交于 2019-11-27 04:25:14
问题 My problem is there is a switch in my app which toggles for 12 hour and 24 hour time format.I am displaying my labels time according to that, but the UIDatePicker time is not getting changed.It's time is depending on device time settings format.Is it possible to show time in UIDatePicker according to my app settings which might be different from device time settings. Somewhere I read that UIDatePicker respects only device settings but still I want to ask if it is possible to show time in 12

problem when cloning jQuery UI datepicker

由 限于喜欢 提交于 2019-11-27 04:06:15
I have a div in which there is a datepicker. I use something like this to clone it: mydiv = $('#someDiv'); // works fine so far mydiv.find('input.datefield').datepicker(); // clone without the events and insert newDiv = myDiv.clone(false).insertAfter(myDiv); // datepicker won't re-init if this class is present newDiv.find('.hadDatepicker').removeClass('hadDatepicker'); // reinitialize datepicker newDiv.find('input.datefield').datepicker(); This is a stripped down version of my code. It works and the calendar shows up as expected where it is expected .. but when a date is clicked, the previous

Trigger jQueryUI datePicker on button click, send result to disabled input field

由 江枫思渺然 提交于 2019-11-27 02:47:45
问题 I've been searching for a way to do this, but could not find anything I want to have a: Disabled input text field, called #XX. This input will store the selected value from datepicker (as this input is disabled I won't be able to use this to trigger the datePicker) Button, besides #XX. When user clicks this button, datePicker will show. User will select the date, and this date will be assigned to disabled input #XX. I want this so user can't change manually -by typing crap- the selected date

UIControlEventEditingChanged doesn't get fired when using setText of UITextfield

由 ↘锁芯ラ 提交于 2019-11-27 01:44:36
问题 I am currently trying to track the states of a textfield. I am using a custom datePicker which sets the text via -setText [self.textField setText:[self.dateFormatter stringFromDate:self.date]]; Inside my textFieldDelegate I wrote the following code: -(void)viewDidLoad { [super viewDidLoad]; self.travelToOnTextField.delegate = self; [self.travelToOnTextField addTarget:self action:@selector(travelToOnTextFieldDidChange:) forControlEvents:UIControlEventEditingChanged]; } -(void

UIDatePicker in UIPopover

由 不羁岁月 提交于 2019-11-27 01:12:12
I have searched the entire internet (maybe I am exaggerating a little) for a tutorial on how to put a DatePicker into a UIPopover and display that in an iPad application. I have tried creating a viewcontroller, placing the datepicker in the view controller and then: self.popover = [[UIPopoverController alloc] initWithContentViewController:sa]; (sa is the name of the viewcontroller i created), but this doesn't work, and the app crashes. Can anyone help? Try with below code. It will work fine: Objective-C - (IBAction)showDatePicker:(UIButton *)sender { UIDatePicker *datePicker = [[UIDatePicker

How do I make a modal date picker that only covers half the screen?

由 别等时光非礼了梦想. 提交于 2019-11-27 00:46:54
问题 I want to have the same effect as the birthday date setter in the iPhone contacts app. How do I have a modal date picker come up only halfway on the screen. I want the date picker to be over a UITableView (like in the iphone contacts app). I would like the UITableView to scroll freely behind the date picker (like in the iphone contacts app). Thanks in advance. 回答1: By far, the best way to achieve a date-picker/uipicker keyboard-like is to use the input view property of a textfield: Build a
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