try-catch

Use pyunpack inside an executable file made with pyinstaller in combination with try except

大兔子大兔子 提交于 2020-03-16 08:11:05
问题 The bounty expires in 6 days . Answers to this question are eligible for a +50 reputation bounty. Matt Dnv wants to draw more attention to this question: I really need to have pyunpack work inside an executable for all cases I have a strange behaviour for pyunpack, a package for unpacking, inside an executable. I want to do the following thing: I have a .7z type of file whose ending is not in .7z but in .sent. First I try to unzip it the direct way, which leads to an expected error that is

Use pyunpack inside an executable file made with pyinstaller in combination with try except

偶尔善良 提交于 2020-03-16 08:10:39
问题 The bounty expires in 6 days . Answers to this question are eligible for a +50 reputation bounty. Matt Dnv wants to draw more attention to this question: I really need to have pyunpack work inside an executable for all cases I have a strange behaviour for pyunpack, a package for unpacking, inside an executable. I want to do the following thing: I have a .7z type of file whose ending is not in .7z but in .sent. First I try to unzip it the direct way, which leads to an expected error that is

IOException can not be resolved to a type error

烈酒焚心 提交于 2020-03-14 18:46:56
问题 For my final in Java we have a "exceptions" part on the test with try, catch, and finally calls. When I try to put the example code into Eclipse I get errors in the catch and throw new areas. All of the errors say "Can not be resolved to type". How do I fix this so I can learn/review what the code is supposed to be doing? Q4 Class public static void main(String [] args) { Q4Exception q1 = new Q4Exception(); try{ q1.sampleMethod(); try{ q1.sampleMethod(); } //This catch does not throw an error

IOException can not be resolved to a type error

笑着哭i 提交于 2020-03-14 18:41:43
问题 For my final in Java we have a "exceptions" part on the test with try, catch, and finally calls. When I try to put the example code into Eclipse I get errors in the catch and throw new areas. All of the errors say "Can not be resolved to type". How do I fix this so I can learn/review what the code is supposed to be doing? Q4 Class public static void main(String [] args) { Q4Exception q1 = new Q4Exception(); try{ q1.sampleMethod(); try{ q1.sampleMethod(); } //This catch does not throw an error

IOException can not be resolved to a type error

半世苍凉 提交于 2020-03-14 18:38:29
问题 For my final in Java we have a "exceptions" part on the test with try, catch, and finally calls. When I try to put the example code into Eclipse I get errors in the catch and throw new areas. All of the errors say "Can not be resolved to type". How do I fix this so I can learn/review what the code is supposed to be doing? Q4 Class public static void main(String [] args) { Q4Exception q1 = new Q4Exception(); try{ q1.sampleMethod(); try{ q1.sampleMethod(); } //This catch does not throw an error

Java: overhead of entering/using “try-catch” blocks?

匆匆过客 提交于 2020-02-27 08:35:31
问题 The question says it all. Although the hit is not highly significant (I measured it to be between 1.5x to 2x slower), there's no difference between the byte code with try-catch and the byte code without it. So what makes it generally slower? Pl. note that the question is not about overhead of throwing an exception, but of entering/leaving a try block. EDIT: here's the code (run on Hotspot 1.6.0_31 server) static void tryCatch() { int i = 0; long l1 = getTime(); for(int j = 0; j < 100000; j++)

Why finally block may not execute when exception is thrown?

允我心安 提交于 2020-02-23 08:32:19
问题 For a long time I thought that it allows me to free up all the resources in the finally block and I thought that if an exception happens in the try block, then the resources will still be free up in the finally block. But that seems not to be the case. I have the following piece of code: using System; public sealed class Program { public static void Main() { try { int zero = 0; int i = 1/zero; } finally { Console.WriteLine("divide by zero"); //the line is never called } } } I never reach the

Do - while goes into an infinite loop

不羁岁月 提交于 2020-02-23 07:16:08
问题 Im trying to add an input validation to this menu. When the user enters eg: 'a' or any input that is not a integer and with the given range, it must execute the catch block and loop again to prompt the user to enter again but instead it keeps looping infinitely after taking the input once. So it goes from executing the menu and just skipping over the input part and executes the catch block. Edit: it goes into infinite loop if i input anything that is not an integer. Scanner sc = new Scanner

Javassist: insert a method at the beginning of catch block

隐身守侯 提交于 2020-02-06 02:51:08
问题 I have code: ControlFlow cf = new ControlFlow(method); for (ControlFlow.Block block : cf.basicBlocks()) { ControlFlow.Catcher catchBlocks[] = block.catchers(); for (int i = 0;i < catchBlocks.length;i++) { int position = catchBlocks[i].block().position(); method.insertAt(position, "System.out.println(\"catch block\")") } } This code snippet inserts the print statement at beginning of the method, which is not what I want. I want the code to be placed like: void foo() { try { a(); } catch

Javassist: insert a method at the beginning of catch block

对着背影说爱祢 提交于 2020-02-06 02:50:13
问题 I have code: ControlFlow cf = new ControlFlow(method); for (ControlFlow.Block block : cf.basicBlocks()) { ControlFlow.Catcher catchBlocks[] = block.catchers(); for (int i = 0;i < catchBlocks.length;i++) { int position = catchBlocks[i].block().position(); method.insertAt(position, "System.out.println(\"catch block\")") } } This code snippet inserts the print statement at beginning of the method, which is not what I want. I want the code to be placed like: void foo() { try { a(); } catch