try-catch

问题 I was wondering if there is a way to not specify the argument when doing a JS try/catch. Every time I try this though, the try/catch doesn't work. The working version: try{ //Breaking code } catch(e){ //Nothing happens here } What I have in mind (No 'e'): try{ //Breaking code } catch(){ //Nothing happens here } 回答1: You just can't. The spec says that there must always be an identifier inside parens after catch . 回答2: Optional catch binding in 2019 Node.js In Node.js, this feature is called

问题 I was wondering if there is a way to not specify the argument when doing a JS try/catch. Every time I try this though, the try/catch doesn't work. The working version: try{ //Breaking code } catch(e){ //Nothing happens here } What I have in mind (No 'e'): try{ //Breaking code } catch(){ //Nothing happens here } 回答1: You just can't. The spec says that there must always be an identifier inside parens after catch . 回答2: Optional catch binding in 2019 Node.js In Node.js, this feature is called

问题 I am having trouble with this line of code right here...why am I being prompted with this error? I am getting an error saying "Operator '|' cannot be applied to operands of type 'bool' and 'string' How do check if my residency variable is not equal to these 2 strings I have listed in the if statement? catch (ArgumentException) { if (age > 16 | age > 80) { Console.WriteLine("You can only enter states of OH or MI ad the driver's age must be between 16 and 80."); } if (residency != "OH" | "MI")

问题 I am having trouble with this line of code right here...why am I being prompted with this error? I am getting an error saying "Operator '|' cannot be applied to operands of type 'bool' and 'string' How do check if my residency variable is not equal to these 2 strings I have listed in the if statement? catch (ArgumentException) { if (age > 16 | age > 80) { Console.WriteLine("You can only enter states of OH or MI ad the driver's age must be between 16 and 80."); } if (residency != "OH" | "MI")

问题 Is there any way to check if a asset file exists in Flutter before try to load the data? For now I have the following: String data; try { data = await rootBundle .loadString('path/to/file.json'); } catch (Exception) { print('file not found'); } The problem is, that I have to check for file 1, if this does not exits I have to check for a fallback file (file 2) and if this does also not exist I load a third file. My complete code would look like this: try{ //load file 1 } catch (..) { //file 1

问题 Is there any way to check if a asset file exists in Flutter before try to load the data? For now I have the following: String data; try { data = await rootBundle .loadString('path/to/file.json'); } catch (Exception) { print('file not found'); } The problem is, that I have to check for file 1, if this does not exits I have to check for a fallback file (file 2) and if this does also not exist I load a third file. My complete code would look like this: try{ //load file 1 } catch (..) { //file 1

问题 I know I can catch a specific Exception type in dart with the following: try { ... } on SpecificException catch(e) { ... } But is there a way to catch multiple specific exception types with on line instead of using multiple catch statements? 回答1: You can only specify one type per on xxx catch(e) { line or alternatively use catch(e) to catch all (remaining - see below) exception types. The type after on is used as type for the parameter to catch(e) . Having a set of types for this parameter

问题 I know I can catch a specific Exception type in dart with the following: try { ... } on SpecificException catch(e) { ... } But is there a way to catch multiple specific exception types with on line instead of using multiple catch statements? 回答1: You can only specify one type per on xxx catch(e) { line or alternatively use catch(e) to catch all (remaining - see below) exception types. The type after on is used as type for the parameter to catch(e) . Having a set of types for this parameter

问题 I know I can catch a specific Exception type in dart with the following: try { ... } on SpecificException catch(e) { ... } But is there a way to catch multiple specific exception types with on line instead of using multiple catch statements? 回答1: You can only specify one type per on xxx catch(e) { line or alternatively use catch(e) to catch all (remaining - see below) exception types. The type after on is used as type for the parameter to catch(e) . Having a set of types for this parameter

问题 # Open new file to write file = None try: file = open(filePath, 'w') except IOError: msg = ("Unable to create file on disk.") file.close() return finally: file.write("Hello World!") file.close() The above code is ripped from a function. One of the user's system is reporting an error in line: file.write("Hello World!") error: AttributeError: 'NoneType' object has no attribute 'write' Question is, If python is failed to open given file, 'except' block executes and it has to return, but control