transpose

Cache Memory Optimization Array Transpose: C

柔情痞子 提交于 2019-12-03 08:10:21
typedef int array[2][2]; void transpose(array dst, array src) { int i, j; for (j = 0; j < 2; j++) { for (i = 0; i < 2; i++) { dst[i][j] = src[j][i]; } } } src array starts at address 0 and the dst array starts at address 0x10. L1 data cache, direct map, write-allocate, 8 byte block size. cache total size is 16 data bytes. What is the hit or miss on each entry of src and dst array? The answer is: src: [0][0] -> miss, [0][1] -> miss, [1][0] -> miss, [1][1] -> hit dst: [0][0] -> miss, [0][1] -> miss, [1][0] -> miss, [1][1] -> miss If the cache total size is 32 data bytes, the answer is: src: [0]

Transpose values in excel using C#

心已入冬 提交于 2019-12-02 17:42:49
问题 I saw this link - C# Transpose() method to transpose rows and columns in excel sheet in stackoverflow and this is what I am trying to do. But the guy is pretty unhelpful in the answers as he does not provide the full information needed. I am simply wanting to transpose cells A9:B15 in my excel sheet and then copy them either into a new xls file, a new worksheet, or better yet delete the current worksheet contents and replace it with the newly transposed paste contents. Clearly it can be done

Flatten list and push list key to vector on second level

元气小坏坏 提交于 2019-12-02 17:34:09
问题 I suppose this is simple, but I just can't seem to figure it out. I need to flatten the second level structure and push the list name/key to a vector on the same level as the other vectors. The current structure of myList is $ 13454:List of 30 ..$ subjectId : num 187 ..$ procedureId : num 3 ..$ procedureSampleId: num 3 ..$ timestamp : chr "2017-04-21T17:15:10.911Z" ..$ n001 : num -999 ..$ n002 : num -999 ..$ gender : num 1 ..$ age : num 18 $ 13455:List of 30 ..$ subjectId : num 188 ..$

PySpark - How to transpose a Dataframe [duplicate]

自闭症网瘾萝莉.ら 提交于 2019-12-02 16:23:05
问题 This question already has answers here : How to pivot Spark DataFrame? (9 answers) Closed last year . I want to transpose a dataframe. This is just a small excerpt from my original dataframe - from pyspark.sql.functions import to_timestamp, date_format valuesCol = [('22','ABC Ltd','U.K.','class 1',102),('22','ABC Ltd','U.K.','class 2',73),('22','ABC Ltd','U.K.','class 3',92), ('51','Eric AB','Sweden','class 1',52),('51','Eric AB','Sweden','class 2',34),('51','Eric AB','Sweden','class 3',11)]

Python - CSV time oriented Transposing large number of columns to rows

▼魔方 西西 提交于 2019-12-02 14:05:23
问题 I have many csv files which are "column" oriented and that I need to pre-process to finally index them. This is time oriented data, with a very large number of columns for each "device" (up to 128 columns) like: LDEV_XXXXXX.csv Serial number : XXXXX(VSP) From : 2014/06/04 05:58 To : 2014/06/05 05:58 sampling rate : 1 "No.","time","00:30:00X(X2497-1)","00:30:01X(X2498-1)","00:30:02X(X2499-1)" "242","2014/06/04 10:00",0,0,0 "243","2014/06/04 10:01",0,0,0 "244","2014/06/04 10:02",9,0,0 "245",

Transpose static range in a loop

非 Y 不嫁゛ 提交于 2019-12-02 13:33:07
I've tried to transpose a static range from column A on sheet 1 to rows on sheet 3 in a loop, to no avail. Here is the code I'm using so far: Sub Looptranspose() ' ' Looptranspose Macro ' ' Keyboard Shortcut: Ctrl+a Dim x As Integer Dim y As Integer x = 1 y = x + 18 Range("A" & CStr(x) & ":A" & CStr(y)).Select Selection.Copy Sheets("Sheet3").Select Selection.PasteSpecial Paste:=xlPasteAll, Operation:=xlNone, SkipBlanks:= _ False, Transpose:=True x = x + 19 End Sub How do I loop this until row A is complete? This code transposes the selected 1st range of 19 cells in column A into a selected row

Powershell transpose rows into columns

◇◆丶佛笑我妖孽 提交于 2019-12-02 12:58:22
Can someone help me to transpose row into colums. Need to transpose MachineName into columns. Endtime must be sorted. <#MachineName, TotalDataSizeBytes, ActualStartTime, EndTime, FinalJobStatus SERVER1, 322349304901, 28/02/2016 23:00:03, 29/03/2016 23:33:23, OK SERVER1, 322349304902, 26/02/2016 23:00:03, 27/03/2016 23:33:23, OK SERVER2, 322349304903, 28/02/2016 23:00:01, 29/03/2016 23:33:23, OK SERVER2, 322349304904, 26/02/2016 23:00:01, 27/03/2016 23:33:23, OK #> $graph = Import-Csv d:\report3.csv | foreach { New-Object PSObject -prop @{ EndTime = [DateTime]::Parse($_.EndTime); MachineName =

Powershell csv row column transpose and manipulation

我怕爱的太早我们不能终老 提交于 2019-12-02 12:33:08
I'm newbie in Powershell. I tried to process / transpose row-column against a medium size csv based record (around 10000 rows). The original CSV consist of around 10000 rows with 3 columns ("Time","Id","IOT") as below: "Time","Id","IOT" "00:03:56","23","26" "00:03:56","24","0" "00:03:56","25","0" "00:03:56","26","1" "00:03:56","27","0" "00:03:56","28","0" "00:03:56","29","0" "00:03:56","30","1953" "00:03:56","31","22" "00:03:56","32","39" "00:03:56","33","8" "00:03:56","34","5" "00:03:56","35","269" "00:03:56","36","5" "00:03:56","37","0" "00:03:56","38","0" "00:03:56","39","0" "00:03:56","40"

Copy Paste VBA Range from one to another worksheet Loop and transpose the data

冷暖自知 提交于 2019-12-02 11:29:28
问题 For A model in Excel I would like to copy and paste data from one sheet in a workbook to the other sheet in the workbook and transpose this data with the usage of a for next loop. Data from the workfile CME should be pasted in the workfile of RME. The total lines of data is 2420. However, since the ranges in the copy and paste different workbook are different and step sizes are different, I assume that i should use two different variables i and j. The first two lines of code is the manual way

proc transpose with duplicate ID values

百般思念 提交于 2019-12-02 11:13:13
I need help with proc transpose procedure in SAS. My code initially was: proc transpose data=temp out=temp1; by patid; var text; Id datanumber; run; This gave me error "The ID value " " occurs twice in the same BY group". I modified the code to this: proc sort data = temp; by patid text datanumber; run; data temp; set temp by patid text datanumber; if first.datanunmber then n = 0; n+1; run; proc sort data = temp; by patid text datanumber n; run; proc transpose out=temp1 (drop=n) let; by patid; var text; id datanumber; run; This is giving me error: variable n is not recognized. Adding a let