transformation

Azure App Services Deployment Slot Transformations

六月ゝ 毕业季﹏ 提交于 2021-02-08 10:55:54
问题 I would like to start using the deployment slots in my Azure App Services for a staging to production task. The problem that I am running into is I can't seem to find a way to do transformations on the web.config outside of the appsetting and connectionstrings. I seem to be missing something, but I need to be able to adjust other configurations, from logging levels, to other integrated config sections. We currently have been using direct deployments from our build server with msdeploy and

JSON to JSON transformation (preferably inside Apache Camel)

て烟熏妆下的殇ゞ 提交于 2021-02-08 03:01:21
问题 I have somewhat unique requirement, which I could not find an answer to so far. I need a JSON to JSON transformation. Preferably, if I could plug it into Apache Camel, that would be wonderful. As a side note, I would also welcome any suggestion to optimally store the JSON to JSON mapping. Is there any XSLT-based way of achieving this? Thanks! Mario 回答1: ZORBA with jsonIQ : http://www.jsoniq.org/ it's a native library, but with high performance. You have examples in the web page. 回答2: There is

JSON to JSON transformation (preferably inside Apache Camel)

好久不见. 提交于 2021-02-08 03:00:35
问题 I have somewhat unique requirement, which I could not find an answer to so far. I need a JSON to JSON transformation. Preferably, if I could plug it into Apache Camel, that would be wonderful. As a side note, I would also welcome any suggestion to optimally store the JSON to JSON mapping. Is there any XSLT-based way of achieving this? Thanks! Mario 回答1: ZORBA with jsonIQ : http://www.jsoniq.org/ it's a native library, but with high performance. You have examples in the web page. 回答2: There is

How to perform perspective distort transformation in VIPS?

二次信任 提交于 2021-02-05 08:56:36
问题 Is it possible to do the following ImageMagick perspective distort command using VIPS? If so, what would the command be (using ruby-vips )? $ convert my_file.png -matte -virtual-pixel transparent +distort Perspective '0,0,0,60 1500,0,300,0 0,2100,0,2310 1500,2100,300,2100' -crop 300x2310+0+0 回答1: There isn't a built-in thing for perspective distort, but you can make one using mapim : http://jcupitt.github.io/libvips/API/current/libvips-resample.html#vips-mapim #!/usr/bin/ruby require 'vips'

How to create new columns in a data.frame based on row values in R?

≡放荡痞女 提交于 2021-01-28 19:30:40
问题 Hej, I have a data.frame with family trios, and I would like to add a column with the full sibs of every "id" (= offspring). My data: df id dam sire 1: 83295 67606 79199 2: 83297 67606 79199 3: 89826 67606 79199 What I would like to retrieve: df2 id dam sire fs1 fs2 1: 83295 67606 79199 83297 89826 2: 83297 67606 79199 83295 89826 3: 89826 67606 79199 83295 83297 What I’ve tried: (similar to: How to transform a dataframes row into columns in R?) library(dplyr) library(splitstackshape) df2 <-

How to create new columns in a data.frame based on row values in R?

邮差的信 提交于 2021-01-28 19:25:46
问题 Hej, I have a data.frame with family trios, and I would like to add a column with the full sibs of every "id" (= offspring). My data: df id dam sire 1: 83295 67606 79199 2: 83297 67606 79199 3: 89826 67606 79199 What I would like to retrieve: df2 id dam sire fs1 fs2 1: 83295 67606 79199 83297 89826 2: 83297 67606 79199 83295 89826 3: 89826 67606 79199 83295 83297 What I’ve tried: (similar to: How to transform a dataframes row into columns in R?) library(dplyr) library(splitstackshape) df2 <-

SVG - How to apply a gradient transform matrix to a linear gradient brush?

独自空忆成欢 提交于 2021-01-28 12:09:11
问题 I'm writing a SVG viewer application in c++ language. I actually face a transform issue in several SVG files that I cannot figure out. Considering the following SVG file: <?xml version="1.0" encoding="UTF-8" standalone="no"?> <!-- Created with Inkscape (http://www.inkscape.org/) --> <svg id="svg9686" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns="http://www.w3.org/2000/svg" height="90mm" width="145mm" version="1.1" xmlns:cc="http://creativecommons.org/ns#" xmlns:xlink="http:/

How to replace namespace prefix in element and attributes using xslt

人盡茶涼 提交于 2021-01-20 07:13:57
问题 I have a source xml like following: <SampleRequest xmlns="http://sample.com/s" xmlns:s1="http://sample.com/s1" xmlns:s2="http://sample.com/s2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://sample.com/s schema.xsd"> <data> <s1:customer s1:firstName="Jim" s1:lastName="Ellison"/> <s2:address> 123 test street </s2:address> </data> </SampleRequest> I need to transform it to the following <SampleRequest xmlns="http://sample.com/t" xmlns:t1="http://sample.com/t1"

How to replace namespace prefix in element and attributes using xslt

放肆的年华 提交于 2021-01-20 07:13:35
问题 I have a source xml like following: <SampleRequest xmlns="http://sample.com/s" xmlns:s1="http://sample.com/s1" xmlns:s2="http://sample.com/s2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://sample.com/s schema.xsd"> <data> <s1:customer s1:firstName="Jim" s1:lastName="Ellison"/> <s2:address> 123 test street </s2:address> </data> </SampleRequest> I need to transform it to the following <SampleRequest xmlns="http://sample.com/t" xmlns:t1="http://sample.com/t1"

How to plot regression transformed back on original scale with colored confidence interval bands?

旧城冷巷雨未停 提交于 2021-01-01 04:38:24
问题 I would like to plot the line and the 95% confidence interval from a linear model where the response has been logit transformed back on the original scale of the data. So the result should be a curved line including the confidence intervals on the original scale, where it would be a straight line on the logit transformed scale. See code: # Data dat <- data.frame(c(45,75,14,45,45,55,65,15,3,85), c(.37, .45, .24, .16, .46, .89, .16, .24, .23, .49)) colnames(dat) <- c("age", "bil.") # Logit