title

ASP.NET 4.0 URL Rewriting: How to deal with the IDs

匿名 (未验证) 提交于 2019-12-03 02:27:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have just started adding the new .NET 4.0 URL Rewriting into my project. I have a question. Let's say I have a Article.aspx that displays, well, articles. I made a route for it in the Global.asax: routes.MapPageRoute("article-browse", "article/{id}", "~/Article.aspx"); So the link consists of the article's id which is, obviously, not a very nice, nor SEO friendly link. I would like to display the Article's title in the link, instead of the ID. Do I have to pass the whole title in the parameter (instead of the id) and then make a SQL query

Finding an Embedded Document by a specific property in Mongoose, Node.js, MongodDB

匿名 (未验证) 提交于 2019-12-03 02:26:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: For this app, I'm using Node.js, MongoDB, Mongoose & Express So I have a Param Object that contains an array of Pivots, and I want to read certain data from the pivots as outlined below ---in models.js------------------------- var Pivot = new Schema({ value : String , destination : String , counter : Number }); var Param = new Schema({ title : String , desc : String , pivots : [Pivot] }); ------------- in main.js -------------- var Param = db.model('Param'); app.get('/:title/:value', function(req, res){ Param.findOne({"title":req.param(

if (key in object) or if(object.hasOwnProperty(key)

匿名 (未验证) 提交于 2019-12-03 02:24:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Do the following two statements produce the same output? Is there any reason to prefer one way to the other? if (key in object) if (object.hasOwnProperty(key)) 回答1: Be careful - they won't produce the same result. in will also return true if key gets found somewhere in the prototype chain , whereas Object.hasOwnProperty (like the name already tells us), will only return true if key is available on that object directly (its "owns" the property). 回答2: I'l try to explain with another example. Say we have the following object with two properties

How can I iterate through a MySQL result set?

匿名 (未验证) 提交于 2019-12-03 02:24:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Here is the code I'm using: # Run the query against the database defined in .yml file. # This is a Mysql::result object - http://www.tmtm.org/en/mysql/ruby/ @results = ActiveRecord::Base.connection.execute(@sql_query) In my View, here's what I do to see the values: <pre><%= debug @results %></pre> Outputs: #<Mysql2::Result:0x007f31849a1fc0> <% @results.each do |val| %> <%= val %> <% end %> Outputs: ["asdfasdf", 23, "qwefqwef"] ["sdfgdsf", 23, "asdfasdfasdf"] So imagine I query something like select * from Person , and that returns a result

Logical AND operator in mySql REGEXP?

匿名 (未验证) 提交于 2019-12-03 02:24:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I use MySql REGEXP: SELECT * FROM myTable WHERE title REGEXP "dog|cat|mouse"; The dataset is small, so I am not concerned about performance. And I prefer this over LIKE notation, because I do not have to concatenate a bunch of "LIKE" statements. However, the above notation uses a logical OR operator. Is there a logical AND operator, so that only rows containing all of the keywords are matched? (I am using InnoDB so fulltext search not an option) 回答1: There's really no nice solution except concatenating ANDs: SELECT * FROM myTable WHERE title

Android ArrayAdapter and JSONArray

匿名 (未验证) 提交于 2019-12-03 02:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am new to Android Development. I purely like to work with JSON Objects and Arrays for my simple application considering the lightness of the JSON Carrier compared to XMLs. I had challenges with ArrayAdapter to populate the ListView. This is how I overcome and need your suggestions on it. Extend the Adaptor class. Then pass the JSONArray to the constructor. Here the constructor calls super with dummy String array setting the length of the JSONArray. Store the constructor arguments in class for further use. public myAdaptor(Context context,

find all two word phrases that appear in more than one row in a dataset

匿名 (未验证) 提交于 2019-12-03 02:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: We would like to run a query that returns two word phrases that appear in more than one row. So for e.g. take the string "Data Ninja". Since it appears in more than one row in our dataset, the query should return that. The query should find all such phrases from all the rows in our dataset, by querying for two adjacent word combination (forming a phrase) in the rows that are in the dataset. These two adjacent word combinations should come from the dataset we loaded into BigQuery How can we write this query in Google BigQuery? The dataset is

Joomla plugin : how to get article title and article id

匿名 (未验证) 提交于 2019-12-03 02:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have developed on simple plugin in Joomla 1.6 I stuck at : How to get article title and article url. I am getting no output if tried to print below statement: echo $article->title; echo $article->id; I have written this in php file, not used MVC architecture. Is there any other settings need to do in Joomla admin side ? Please suggest your pointers for extracting article title and article url. Thanks in advance! Pravin 回答1: i tried : public function onContentPrepare($context,&$article, &$params, $limitstart) { echo JRequest::getVar('id');

Declare variable in a Play2 scala template

匿名 (未验证) 提交于 2019-12-03 02:19:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: How do you declare and initialize a variable to be used locally in a Play2 Scala template? I have this: @var title : String = "Home" declared at the top of the template, but it gives me this error: illegal start of simple expression """),_display_(Seq[Any](/*3.2*/var)),format.raw/*3.5*/(""" title : String = "Home" 回答1: @defining ( "foo" ) { title => @title ... } basically, you have to wrap the block in which you are going to use it 回答2: Actually, @c4k 's solution is working (and quite convenient) as long as you don't try to change

Swift Custom Back Button and Destination

匿名 (未验证) 提交于 2019-12-03 02:18:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am currently using SWRevealViewController for a sidebar menu in my app. When I click one of the options, the destination view controller doesn't have a 'back' button because it hasn't come from a proper view controller (i.e. page to go back to). Therefore I am wanting to manually create a back button on the destination view controller which will go back to the home view controller. I have looked at the code here: How do I manually set the "Back" destination in iOS apps But I am struggling to implement this in Swift (one error after another