time

问题 How can I do this in Python? I just want the day of the week to be returned. >>> convert_epoch_time_to_day_of_the_week(epoch_time_in_miliseconds) >>> 'Tuesday' 回答1: ep = 1412673904406 from datetime import datetime print datetime.fromtimestamp(ep/1000).strftime("%A") Tuesday def ep_to_day(ep): return datetime.fromtimestamp(ep/1000).strftime("%A") 回答2: from datetime import date def convert_epoch_time_to_day_of_the_week(epoch_time_in_miliseconds): d = date.fromtimestamp(epoch_time_in_miliseconds

问题 I want to achieve similar function that is available in Time Period Library for .NET, but in SQL. First, I have a table with several rows with an Start Date and an End Date, and I want to consolidate them together like this: Then with that result and another coming from a different table, I want to find out the intersection between the two of them, like this but only 2 inputs (find the periods that are present in both): Once I have the intersection is just summing up the time on it. Here I

问题 I have a column in a MySQL database that contains a date as milliseconds (epoch). I want to build an SQL query that formats the date as something human readable (day, month, year, hours, minutes, seconds in any format and time zone). Is there an SQL (or MySQL-specific) function to do this? 回答1: Try using the FROM_UNIXTIME function like this as given in the manual SELECT FROM_UNIXTIME(1196440219); -> '2007-11-30 10:30:19' You could also use formatting like this mysql> SELECT FROM_UNIXTIME(UNIX

问题 The following piece of code: Instant inFourWeeks = Instant.now().plus(4L, ChronoUnit.WEEKS); Throws an exception: java.time.temporal.UnsupportedTemporalTypeException: Unsupported unit: Weeks Why are weeks unsupported? I understand why months and years are not supported, because their duration in smaller units may vary. But a week has constant duration (7 days) and I can achieve the same by writing: Instant inFourWeeks = Instant.now().plus(4L * 7L, ChronoUnit.DAYS); 回答1: It throws

问题 I want to create a timer in python with the following functions: timer.start() - should start the timer timer.pause() - should pause the timer timer.resume() - should resume the timer timer.get() - should return the current time The timer should run from 0 upwards. It is meant to measure time, not trigger a callback function. So if you start it, it should start counting the seconds like 0 1 2 3, if you pause it, it should be stilll at 3, but not going further. After its resumed it then goes

问题 In the time package, when formatting a time.Time variable, the output will use the English names for weeks and months as defined in unexported []string slices. How to localize the string, using a different language (hopefully still using Format() )? Example: fmt.Println(time.Now().Format("Mon 2 January 2006")) Output: Tue 28 January 2014 Desired output: Tis 28 Januari 2014 Playground 回答1: As you can see in time package sourcecode that values are hardcoded in source. So, basically, Go doesn't

问题 In the time package, when formatting a time.Time variable, the output will use the English names for weeks and months as defined in unexported []string slices. How to localize the string, using a different language (hopefully still using Format() )? Example: fmt.Println(time.Now().Format("Mon 2 January 2006")) Output: Tue 28 January 2014 Desired output: Tis 28 Januari 2014 Playground 回答1: As you can see in time package sourcecode that values are hardcoded in source. So, basically, Go doesn't

问题 I have a database table 'email_log' which would be filled with information as: user, subject and opened (as datetime) What I need is a new query from which I can see how many rows contain the column 'opened' between 08:00 and 09:00 . What I had didn't work: SELECT count(*) as count FROM email_log WHERE opened BETWEEN '00:08:00' AND '00:09:00'; Does anyone know the trick? 回答1: You might need to include the entire format for the datetime - since it's got both a date and a time. See: mysql: get

问题 I am studying CalDAV protocol. I have some question for time conflict or overlap for CalDAV. Let me explain by instance for some scenario. I made an event PM1 ~ PM6 in calendar. And then I try to made another event PM2~7 in same calendar. It is time conflict or overlap. How does CalDav server resolve this conflict? Does server make error when second event make? I did search out RFC 6638. But I could not find solution. Please help my question. Thanks for reading. 回答1: It is up to the CalDAV

问题 I am studying CalDAV protocol. I have some question for time conflict or overlap for CalDAV. Let me explain by instance for some scenario. I made an event PM1 ~ PM6 in calendar. And then I try to made another event PM2~7 in same calendar. It is time conflict or overlap. How does CalDav server resolve this conflict? Does server make error when second event make? I did search out RFC 6638. But I could not find solution. Please help my question. Thanks for reading. 回答1: It is up to the CalDAV