this

Unexpected use of 'event' no-restricted-globals when using event.target.id to get id from bind(this)

故事扮演 提交于 2019-12-05 05:28:34
This code works on Codepen: See https://codepen.io/pkshreeman/pen/YQNPKB?editors=0010 However I am trying to use this in my own 'create-react-app' and the error of 'no-restricted-globals' is trigged by event.target.id . What is a workaround for this. How do you get id from 'this' in react other than using the event target? const Elem = (props) =>{ return (<div> <h1 onClick={props.clickon} id="GM"> Good Morning! <br/> {props.name} {props.last} <br /> This is phase three</h1> <button id="btn1" onClick={props.clickon}> {props.text} </button> <button id="btn2" onClick={props.clickon}> Second

The C++ implicit this, and exactly how it is pushed on the stack

随声附和 提交于 2019-12-05 05:09:12
I need to know whether, when a class method in C++ is called, the implicit 'this' pointer is the first argument, or the last. i.e: whether it is pushed onto the stack first or last. In other words, I'm asking whether a class method, being called, is taken by the compiler to be: int foo::bar(foo *const this, int arg1, int arg2); //or: int foo::bar(int arg1, int arg2, foo *const this); By extension therefore, and more importantly, that would also answer whether G++ would push the this pointer last or first, respectively. I interrogated google, but I didn't find much. And as a side note, when C++

What does assignment to *this do (*this = val)?

会有一股神秘感。 提交于 2019-12-05 04:26:13
I was browsing Qt sources, and noticed this QUuid &operator=(const GUID &guid) { *this = QUuid(guid); return *this; } I've never seen assignment to "this" before. What does assignment to "this" do? That is not an assignment to this but to the object pointed by this . That will effectively call operator=( QUuid const & ) on the current object. It just invokes QUuid &operator=(const QUuid& quUid); . 'this' is simply a pointer to the object on which the current method is invoked. Changing the value behind 'this' (by dereferencing the pointer using '*this' and assigning another object) modifies

Calling functions inside a map() function in React render() [duplicate]

风流意气都作罢 提交于 2019-12-05 03:51:07
This question already has answers here : React 'cannot read property of undefined' when using map (2 answers) Closed 2 years ago . This is a follow up to my previous question, but how do I call a function inside React's render() method, if I have a map inside that. Example (this code is inside a class that extends React.Component ): getItemInfo(item){ return `${item.Something} ${item.SomethingElse}` } render() { return ( <div className="someDiv"> { collection.map(function (item) { return <div> {item.Name} {this.getItemInfo(item)} </div> }) } </div> ); } No matter what I try I always end up

C# StyleCop - Using “this.” prefix for base class members like current class members or not?

点点圈 提交于 2019-12-05 03:32:23
StyleCop has a rule about using "this." prefix to calling class members (SA1101). Is this rule holds true about a member (for example a method) of a class which is inherited from its base class. Example: class BaseClass { protected void F1() { ... } } class ChildClass : BaseClass { protected void F2() { ... } protected void F3() { this.F2(); // This is correct acording to SA1101 // F1 is a member of base class and if I dont put this prefix, stylecop will not show any message. this.F1(); // Is this correct? F1(); // Or this? } } I know this is just for better readability. The documentation for

How to get innerHTML of this element in javascript?

微笑、不失礼 提交于 2019-12-05 02:24:16
问题 Pretty simple question. I have an element (a tag) which has an onclick to call a javascript function. Amoung other things, I want this function to echo the innerHTML of the element that called it. So, in this case, the innerHTML of the atag. How do I do this? 回答1: <element onClick="alert(this.innerHTML);"> ... </element> 回答2: markup: <element id="foo"> ... </element> js: document.getElementById('foo').addEventListener('click', fn); function fn(){ alert(this.innerHTML); } http://jsfiddle.net

Why does Backbone.js model's 'on()' take 'this' as last parameter if it's almost always going to be this?

自古美人都是妖i 提交于 2019-12-05 02:15:21
问题 I'm just getting into Backbone, and one thing that I don't understand is why the 'on()' method for models always takes three arguments--event, handler, and context. It seems that almost always 'this' is used for context and I haven't seen any other usage. Even if there were, since I haven't seen one yet it must be pretty rare. So my question is: When does one use a context other than 'this', and why is Backbone designed this way? By the way, I do understand why you need to provide context, it

How to get this pointer from std::function?

我与影子孤独终老i 提交于 2019-12-05 00:02:39
问题 Since std::function can hold member functions, so it must store a pointer to the object instance somewhere. How can I fetch the this pointer from a std::function that holds a member function? 回答1: An object of type std::function holds a callable object . A pointer to member function is a kind of callable object; it can be called with an argument of the appropriate class type, plus any additional arguments that it needs. For example: struct S { void f(int); }; std::function<void(S, int)> g(&S:

Why `this.synchronized` instead of just `synchronized` in Scala?

百般思念 提交于 2019-12-04 23:49:34
In an example of working with JDBC in Scala, there is a following code: this.synchronized { if (!driverLoaded) loadDriver() } Why this.synchronized instead of just synchronized ? In scala synchronized is not a keyword, as in java. It is in fact a member of AnyRef , which is scala equivalent for java's Object . So to answer your question, you can either use synchronized or this.synchronized , just as you can do toString or this.toString . 来源: https://stackoverflow.com/questions/7826822/why-this-synchronized-instead-of-just-synchronized-in-scala

what does this() mean in Java [duplicate]

半城伤御伤魂 提交于 2019-12-04 20:33:32
问题 This question already has answers here : Whats the use of this() in linkedlist.java (2 answers) Closed 6 years ago . what does this() mean in Java? It looks it is only valid when put this(); in the class variable area. Any one has idea about this? Thanks. 回答1: It means you are calling the default constructor from another constructor. It has to be the first statement and you cannot use super() if you have. It is fairly rare to see it used. 回答2: It's a call to the no-argument constructor, which