syntax

问题 Given a syntactically valid, but otherwise arbitrary, Julia expression, such as 3 - 4 > 1 & 2 + 2 == 4 | 10 - 5 > 2 or 2 + 9 - 8 * 8 ^ 7 / 2 == 8 + 8 / 1 ^ 2 ...is there a convenient way to fully parenthesize the expression in a way consistent with Julia's standard parsing of it? One approach that won't go far enough: julia> parse("3 - 4 > 1 & 2+2 == 4 | 10 - 5 > 2") :(3 - 4 > 1 & 2 + 2 == (4 | 10) - 5 > 2) julia> parse("2 + 9 - 8 * 8 ^ 7 / 2 == 8 + 8 / 1 ^ 2") :((2 + 9) - (8 * 8^7) / 2 == 8

问题 Please note: although this question mentions Mongo it is surely a pure Groovy question at heart. My MyApp#bootstrap method: def bootstrap(AppConfiguration config) { String h = config.dbHost String p = config.dbPort println "Mongo is at: ${h}:${p}." dao = new MongoDao(host: h, port: p) } My MongoDao class (snippet): class MongoDao implements BasicDao { String dbName Mongo mongo String host String port Morphia morphia Datastore datastore MongoDao(String host, String port) { this.dbName = "db

问题 I want to use the following syntax in Javascript: var bar = foo.replace(/really long regex/, something) .replace(/another really long regex/, something) .replace(/yet another really long regex/, something); since it's (somewhat) more readable than doing this on one line. Is this allowed? It works fine in Firefox, but I can't find any reference to this syntax anywhere, and I don't want to find out later that there's some obsure browser where this doesn't work. 回答1: Yes, Javascript ignores

问题 Basically, I have an array of char* that I want to pass and modify in this function, so I pass in a pointer to an array of char*. That is, I want to pass a pointer to char* arr[]. What is the difference between the two? 回答1: As always, http://cdecl.org is your friend: char * (*arr)[] - "declare arr as pointer to array of pointer to char" char *** arr - "declare arr as pointer to pointer to pointer to char" These are not the same. For a start, the first is an incomplete type (in order to use a

问题 Hi guys I've fonund this useful python script that allows me to get some weather data from a site. I'm going to create a file and the dataset indide. Something is not working. It returns this error. File "<stdin>", line 42 f.close() ^ SyntaxError: invalid syntax What's wrong? In this line I'm only closing the file! Could anyone help me please? This is the python code. import urllib2 from BeautifulSoup import BeautifulSoup # Create/open a file called wunder.txt (which will be a comma-delimited

问题 I'am a little bit confused. I would like do debounce the function resizeAd on windows-resize. I played with this code but without any result. The debouncing is not done. How I have to call the debouncing-function in this case? The debouncing function works fine by calling them like this: var resizeIframeAd = debounce(function() {... } (function(window, document, undefined) { 'use strict'; /* * Global api. */ var adTech = window.adTech = { get: function() { return _instance; }, //Main entry

问题 I am having an issue on my problem where the console is saying SyntaxError: Unexpected token { and I'm not sure where it's coming from. I am a JS newbie, just learning this stuff. Would you mind pointing out where I am going wrong with my brackets please. var myArray = [4, 6, 23, 10, 1, 3]; var arrayAdditon = function (arr) { var largestNumber = arr[0]; var sumTotal; for (var i = 0; i < arr.length; i += 1) { if (arr[i] > largestNumber) { largestNumber = arr[i]; } } for (var i = 0; i < arr

问题 I've been going nuts trying to figure this out. Consider the following code (I'm assuming forward references have been defined): // Signature representing a pointer to a method call typedef void (MyClass::*MyMethod)(int); class MyClass { MyClass(); void method1(int i); void method2(int i); void associateMethod(int index, MyMethod m); } Given the above, the constructor can do things like the following: MyClass::MyClass() { associateMethod(1, &MyClass::method1); associateMethod(2, &MyClass:

问题 I'm finding this in some legacy code and just curious what the brackets are for? Public Enum myEnum none = 0 abc = 2 def = 4 ghi= 6 [jkl] = 8 mno = 9 End Enum 回答1: They're not needed in the example you provided, which I assume you have obscured, but the brackets let you specify a name for an enum item that would otherwise conflict with a reserved word. 回答2: Brackets are usually used when you want to use a keyword for a variable, classname, function name, or something else where using a

问题 i know the meaning of $('.some-class') and $('#some-id') , but i do really not know the meaning of $('.some-class',$('#some-id')) , hoping some one can explain it for me, many thanks. 回答1: You have selector with context , some-class will be looked up in element with in element with id some-id . '.some-class' is selector and $('#some-id') is context The syntax in the jQuery documents for selector is jQuery( selector [ , context ] ) you can read more about selectors here Without context $('