symlink

How are symbolic links managed internally by UNIX/Linux systems. It is known that a symbolic link may exist even without an actual target file (Dangling link). So what is that which represents a symbolic link internally. In Windows, the answer is a reparse point . Questions: Is the answer an inode in UNIX/Linux? If yes, then will the inode number be same for target and links? If yes, can the link inode can have permissions different from that of target's inode (if one exists)? jm666 It is not about UNIX/Linux but about filesystem implementation - but yes, Unix/Linux uses inodes at kernel level

I got excited when I saw the following post but it doesn't cover my case: Mount an FTP server locally Is there any way for me to create symbolic links on a remote server without having SSH access, possibly via some FTP hack? Regular FTP is too abstract to know about symbolic links. If the server supports custom commands, it might let you send the unix shell commands directly. Not all servers support this but some of them do. If you have SFTP access (sometimes admins give users SFTP access but no SSH shell), SFTP protocol supports creation of symbolic links. Use a script. If you have sh, bash

If I call os.stat() on a broken symlink , python throws an OSError exception. This makes it useful for finding them. However, there are a few other reasons that os.stat() might throw a similar exception. Is there a more precise way of detecting broken symlinks with Python under Linux? Thomas Vander Stichele A common Python saying is that it's easier to ask forgiveness than permission. While I'm not a fan of this statement in real life, it does apply in a lot of cases. Usually you want to avoid code that chains two system calls on the same file, because you never know what will happen to the

I am having a PowerShell script which is walking a directory tree, and sometimes I have auxiliary files hardlinked there which should not be processed. Is there an easy way of finding out whether a file (that is, System.IO.FileInfo ) is a hard link or not? If not, would it be easier with symbolic links (symlinks)? Keith Hill Try this: function Test-ReparsePoint([string]$path) { $file = Get-Item $path -Force -ea SilentlyContinue return [bool]($file.Attributes -band [IO.FileAttributes]::ReparsePoint) } It is a pretty minimal implementation, but it should do the trick. Note that this doesn't

I'm tring to commit a symlink into subversion, but I get this error when I try to add the actual symlink: Can't replace 'path/to/symlink' with a node of a differing type; the deletion must be committed and the parent updated before adding 'path/to/symlink' I read it as - you have to remove the file, commit, update, create symlink, add it, commit. And my guess is that you're trying to remove the file, create symlink, commit in one go. svn delete x svn ci -m'blah' svn update ln -s blee x svn add x The error I got on svn 1.6.11 reads svn: Commit failed (details follow): svn: Entry '/path/to

In Ruby, Dir.glob("**/*.rb") (for instance) doesn't traverse symlinked directories. Is it possible to get the ** to traverse symlinks? I'm using two gems which find files this way, but I need them to see files within a symlinked directory. Jonathan's clever and cunning approach is great, capable of slashing through hordes of symlinks with but a mere flick of a few asterisks, muahaha. However, it has the unfortunate side-effect of not returning immediate-child matches. An improved version might be: Dir.glob("**{,/*/**}/*.rb") Which will (in my tests) do both follow one symlink and return

when i give ls -l /etc/fonts/conf.d/70-yes-bitmaps.conf lrwxrwxrwx <snip> /etc/fonts/conf.d/70-yes-bitmaps.conf -> ../conf.avail/70-yes-bitmaps.conf so for a symbolic link or soft link, how to find the target file's full(absolute path) in python, If i use os.readlink('/etc/fonts/conf.d/70-yes-bitmaps.conf') it outputs ../conf.avail/70-yes-bitmaps.conf but i need the absolute path not the relative path, so my desired output must be, /etc/fonts/conf.avail/70-yes-bitmaps.conf how to replace the .. with the actual full path of the parent directory of the symbolic link or soft link file. os.path

What's the simplest way on Linux to "copy" a directory hierarchy so that a new hierarchy of directories are created while all "files" are just symlinks pointing back to the actual files on the source hierarchy? cp -s does not work recursively. I googled around a little bit and found a command called lns , available from here . I just did a quick test on a linux box and cp -sR /orig /dest does exactly what you described: creates a directory hierarchy with symlinks for non-directories back to the original. cp -as /root/absolute/path/name dest_dir will do what you want. Note that the source name

I have a string containing the file system path to an existing symlink. I want to get the path that this link points to. Basically I want the same that I'd get through this bit of hackery: s = "path/to/existing/symlink" `ls -ld #{s}`.scan(/-> (.+)/).flatten.last but I want to do it without shelling out. I think readlink is what you are looking for: File.readlink("path/to/symlink") require 'pathname' Pathname.new("symlink").realpath or readlink as others said Or you can try: File.realpath("symlink_path") Which works for both symlinks and normal files. 来源： https://stackoverflow.com/questions