superclass

I'm trying to understand how does the inheritance work in play! But unsuccessfully yet. So, I have such superclass: @Inheritance(strategy = InheritanceType.TABLE_PER_CLASS) abstract class SuperClass extends Model { @Id @GeneratedValue(strategy = GenerationType.TABLE, generator = "SEQ_TABLE") @TableGenerator(name = "SEQ_TABLE") Long id; int testVal; } And 2 inherited classes: @Entity public class Sub extends SuperClass { String name; @Override public String toString() { return name; } } @Entity public class Sub1 extends SuperClass { String name; @Override public String toString() { return name;

This is more of a puzzle than question. I have the following code: public class PrivateBaseConstructor { public static class BaseClass { private BaseClass() { } } public static class DerivedClass extends BaseClass { public DerivedClass() { super(); // 1* } } } Here the call for super(); at 1* is allowed event though the base class constructor is private . If we write the classes as separate classes in same package: BClass.java public class BClass { private BClass() { } } DClass.java public class DClass extends BClass { public DClass() { super(); // 2* } The compiler rightly gives error at 2*

In C#, how does one obtain a reference to the base class of a given class? For example, suppose you have a certain class, MyClass , and you want to obtain a reference to MyClass ' superclass. I have in mind something like this: Type superClass = MyClass.GetBase() ; // then, do something with superClass However, it appears there is no suitable GetBase method. Use Reflection from the Type of the current class. Type superClass = myClass.GetType().BaseType; Timothy Carter Type superClass = typeof(MyClass).BaseType; Additionally, if you don't know the type of your current object, you can get the

I have the following class, with an init method: class user { var name:String var address:String init(nm: String, ad: String) { name = nm address = ad } } I'm trying to subclass this class but I keep getting errors on the super.init() part: class registeredUser : user { var numberPriorVisits: Int // This is where things start to go wrong - as soon as I type 'init' it // wants to autocomplete it for me with all of the superclass' arguments, // and I'm not sure if those should go in there or not: init(nm: String, ad: String) { // And here I get errors: super.init(nm: String, ad: String) // etc..

How do I call a super constructor in Dart? Is it possible to call named super constructors? Eduardo Copat Yes, it is, the syntax is close to C# , here is an example with both default constructor and named constructor: class Foo { Foo(int a, int b) { //Code of constructor } Foo.named(int c, int d) { //Code of named constructor } } class Bar extends Foo { Bar(int a, int b) : super(a, b); } class Baz extends Foo { Baz(int c, int d) : super.named(c, d); } If you want to initialize instance variables in the subclass, the super() call must be last in an initializer list. class CBar extends Foo { int