sublist

问题 I'm making a sublist of every row inside a csv file but i'm getting a single list back wines_list = [] for row in wines: wines_list.append(row) print(wines_list) This returns: ['id', 'country', 'description', 'designation', 'points', 'price', 'province', 'taster_name', 'title', 'variety', 'winery', 'fixed acidity', 'volatile acidity', 'citric acid', 'residual sugar', 'chlorides', 'free sulfur dioxide', 'total sulfur dioxide', 'density', 'pH', 'sulphates', 'alcohol'] But i wan't it to append

问题 I'm new here and to programming as well. I don't know if I put the question right, but I have been trying to generate sublists from a list. i.e say if L = range(5) , generate sublists from L as such [[],[0],[0,1],[0,1,2],[0,1,2,3],[0,1,2,3,4]] . Kindly assist. Thanks. 回答1: Look at this: >>> # Note this is for Python 2.x. >>> def func(lst): ... return map(range, xrange(len(lst)+1)) ... >>> L = range(5) >>> func(L) [[], [0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]] >>> 回答2: You can

问题 In R, I have a list, composed of 12 sublists, each themselves composed of 5 subsublists as follow lists and sublists In this example, I want to extract the info "MSD", for each of these sublists. I can extract the level "statistics" for each using lapply(letters, '[[', "statistics") That worked well. It gave me all the values contained in the sublist "statistics", for each list However, I want to go one level down of that, as I am not interested in the other data such as MSerror, Df, .....

问题 I have a list of lists and would like to extract the last items and place them in a lists of lists. It is relatively easy to extract the last items. But all my attempts result in one list, rather than in a list of lists. Any suggestions? lst = [[[11, 12, 15], [12, 13, 14], [13, 14, 15], [14, 15, 17], [15, 16, 17]], [[14, 15, 18], [15, 16, 17]]] The result I would like from this is: [[15, 14, 15, 17, 17], [18, 17]] What I tried for example, is this function: def Extract(lst): for i in lst:

问题 I am trying to write the sublist search algorithm using Python. For reference : https://www.geeksforgeeks.org/sublist-search-search-a-linked-list-in-another-list/ Here is my code: def sublist(arr1,arr2): i = 0 j = 0 k = 0 if len(arr1) == 0: print('List1 Empty') if len(arr2) == 0: print('List 2 Empty') for j in range(0,len(arr2)): for i in range(0,len(arr1)): if arr1[i] != arr2[j]: break while arr1[i] == arr2 [j]: if i == len(arr1) - 1: return True i = i + 1 j = j + 1 if i == len(arr1): return

问题 I am trying to split a list into n sublists where the size of each sublist is random (with at least one entry; assume P>I ). I used numpy.split function which works fine but does not satisfy my randomness condition. You may ask which distribution the randomness should follow. I think, it should not matter. I checked several posts which were not equivalent to my post as they were trying to split with almost equally sized chunks. If duplicate, let me know. Here is my approach: import numpy as

问题 java.util.ArrayList.SubList is a non-static inner class class of java.util.ArrayList, which means that it holds an reference to its enclosing class. We can access the members of java.util.ArrayList by using ArrayList.this. But java.util.ArrayList.SubList also has a member "parent" which is also a reference to the enclosing class of java.util.ArrayList.SubList. Why the "parent" member variable is needed or why not declare java.util.ArrayList.SubList as a static inner class? My jdk is the

来源： https://stackoverflow.com/questions/64688081/transform-a-list-into-a-list-of-lists-with-fold-in-haskell

来源： https://stackoverflow.com/questions/64688081/transform-a-list-into-a-list-of-lists-with-fold-in-haskell

问题 I looked but i didn't found the answer (and I'm pretty new to python). The question is pretty simple. I have a list made of sublists: ll [[1,2,3], [4,5,6], [7,8,9]] What I'm trying to do is to create a dictionary that has as key the first element of each sublist and as values the values of the coorresponding sublists, like: d = {1:[2,3], 4:[5,6], 7:[8,9]} How can I do that? 回答1: Using dict comprehension : {words[0]:words[1:] for words in lst} output: {1: [2, 3], 4: [5, 6], 7: [8, 9]} 回答2: